Use 492 if you want theoretically correct length. 468 takes into account end
effects, ect.

"Brian Hill" wrote in message
...

"dxAce" wrote in message
...


Brian Hill wrote:

"dxAce" wrote in message
...


Brian Hill wrote:

"Don Forsling" wrote in message
...
Yes, I'm iold, tired, lazy and forgetful. That said, can
someone
remind
me
of the formula for calculating the length of a full-wave antenna
wire
if
the
frequency is known (think whip and a frequency of 160.890 mhz).

Your ant would be 2.9088196904717508856983031885139. So about 2
15/16 or
so
inches. I wouldn't recamend a dipole config. LOL!!!

Are you sure about that length? A dipole at 144 MHz is much, much
larger
than
that, so something at 160 MHz or so isn't going to be that much
smaller.

dxAce
Michigan
USA



I don't know what the logistics of VHF and above would be but the math
says
it's so. I'll have to refer to my ARRL handbook. I'm a HF guy and the
math
works for that spectrum.

A half wavelength dipole for 160.890 MHz would be be right about 3.06
feet
long.

This is found by dividing 492 by the frequency in MHz.

dxAce
Michigan
USA



Maybe some other math comes into play above a cirtain freq? Your right
because I've owned several ants I have bought for the higher freqs that
are
bigger. 468 is the number you use for figuring SW ants though. I do know
that for sure.

B.H