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Not understanding some parts of wave refraction
MRW wrote:
I am skimming thru the Propagation chapter of the ARRL handbook, and I am having a difficult time understanding the shortening of wavelength and the retainment of frequency. They have an equation showing that wave velocity is: c = f*w (c = m/s, f = frequency, w = wavelength). It also states that during refraction "the wavelength is simultaneously shortened, but the wave frequency (number of crests that pass a certain point in a given unit of time) remains constant." I don't understand. If the wavelength is shortened, then shouldn't the frequency increase instead of remaining constant? 'c' decreases because of the fractional velocity factor in a transmission line. The decrease in 'c' compresses the wavelength but doesn't change the frequency. 'c' is less in a transmission line than it is in free space. The speed of light in RG-213, for instance, is 2/3 of the speed of light in free space. -- 73, Cecil, w5dxp.com |
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