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Old April 9th 07, 07:01 PM posted to rec.radio.amateur.antenna
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Posts: 342
Default Constructive interference in radiowave propagation

Cecil Moore wrote:
Richard Fry wrote:
"Cecil Moore"
Being a little more precise:
With mutually incoherent equal-magnitude sources,
the maximum possible peak intensity is double the
intensity of a single wave. There's no interference.

____________

BUT, the two equal-power signals in my scenario are exactly coherent
at the output port where they combine to produce twice average output
power of either tx.

Please explain, in light of your concepts?


I thought I did. You have combined those outputs
without producing any interference. If there is
no interference, as far as power goes, it doesn't
matter if they are coherent or not.

Assuming P1 is the power output of the first
transmitter and P2 is the power output of the
second transmitter, if Ptotal = P1 + P2 + 0,
the interference (last) term is obviously zero,
i.e. it's prima facie - no interference.

If you double the H-field (current) while keeping
the E-field (voltage) constant, you have not
produced any interference.

If you double the E-field (voltage) while keeping
the H-field (current) constant, you have not
produced any interference.

If you double both the E-field (voltage) and the
H-field (current) at the same time, you have produced
total constructive interference.

If you zero both the E-field (voltage) and the
H-field (current) at the same time, you have produced
total destructive interference.

For interference to exist, both the E-field and
H-field must be changed by the same percentage
thus keeping their Z0 ratio constant.

If both fields decrease, extra energy is available
during that destructive interference event. If both
fields increase, extra energy is required by that
constructive interference event. In the absence
of a local source, |destructive interference| must
always equal |constructive interference|.


Cecil,

You are quite prolific at manufacturing even more crystalline spheres.

8-)


73,
Gene
W4SZ
 
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