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Analyzing Stub Matching with Reflection Coefficients
Gene Fuller wrote:
Cecil Moore wrote: This is steady-state after the wave interaction. What you guys don't seem to realize is that s11(a1) and s12(a2) are continually changing, continually interacting, and a1 & a2 are rotating phasors changing with time. Utter nonsense. Any setup that includes t0 or t=0 is not steady state. Gene, you obviously misunderstood what I said. There is no t0 or t=0 in my above statement. It is just that the delta-t doesn't change from the transient state to the steady-state. In an s-parameter analysis: The normalized voltage, a1, equals Vi1/SQRT(Z0) where 'i' stands for incident voltage. a2 equals Vi2/SQRT(Z0). These voltages are normally represented in phasor notation but they can just as easily be represented in exponential notation where a1 = Vi1*e^jwt+X and a2 = Vi2*e^jwt+Y, where X and Y are constant phase angles. Thus, the s-parameter equation becomes: b1 = Vi1[cos(wt+X)]/SQRT(Z0) + Vi2[cos(wt+Y)]/SQRT(Z0) = 0 adding the delta-t "tick" gives: b1 = Vi1{cos[w(t+delta-t)+X]}/SQRT(Z0) + Vi2{cos[w(t+delta-t)+Y]}/SQRT(Z0) = 0 Vi1 obviously has to be an equal magnitude to Vi2 and X and Y obviously have to be 180 degrees apart. Given that, for every delta-t "tick" of time, the two real normalized voltages sum to zero. The square of the normalized RMS value gives average power in each wave. The equation can be turned into a differential equation by having delta-t approach zero in the limit. -- 73, Cecil http://www.w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
Keith Dysart wrote:
You really do need to realize that there is no need for a circulator. So Tektronix can just abandon its circulator business and kiss their circulator profits goodbye? When are you going to patent your idea and get rich? There you go. Still stuck. You really should crack the books in search of a reference to support your contention. You won't find one. And that is exactly why the argument has been raging for decades. Humans have not yet acquired 100% of all knowledge. You seem to claim that you have mastered that task but I seriously doubt it. And the relevence of the conjugate match is that the conjugate is the generator source impedance and it is the impedance that the wave incident upon the generator sees. I see you have not yet read Walter Maxwell's article. The generator source impedance is not what is seen by the reflected waves. I have certainly never said that. If you could point me to the words that misled you into thinking that, I will attempt to clarify your misunderstanding. Correct me if I'm wrong. I understood you to say that energy cannot flow past an instantaneous zero energy point yet there is an instantaneous zero energy point every 1/2WL in an EM traveling wave. -- 73, Cecil http://www.w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
Keith Dysart wrote:
On Apr 20, 12:46 pm, Cecil Moore wrote: I already did - Bruene's early 1990's QST article. Sorry. Not a good enough description for any kind of analysis. Ignore it if you choose. That's when the present hoopla began, at least in the amateur radio community. You can follow the thread from that point to the present to see what is happening in the present. Nothing to sweep under the rug, I am afraid. It is key that the dissipation depends on the design of the generator. Some times those 'reverse watts' cause the dissipation to drop to 0, sometimes they cause it to increase by a factor of 4, sometimes they cause it to increase by the numerical value of the 'reverse watts'. Pretty much hard to argue that those 'reverse watts' are real when their heating effect is so variable. Not at all. The heating effect depends upon how much of the reverse joules/sec are re-reflected. If the dissipation drops to 0, that is prima facie evidence that all the reflected joules/sec have been re-reflected. If the dissipation increases by a factor of 4, that is prima facie evidence that all of the reflected joules/sec are being dissipated in the source along with all of the joules/sec available from the source into a matched load. Anything else would violate the conservation of energy principle. I'd suggest you think of power as a quantity not a situation. Superposition works for linear, time invariant circuits with multiple sources. Check any text book. The generators and lines under discussion meet these requirements. But superposition obviously doesn't work at the source *point*. One possible technical conclusion may be that the dynamic active source is constant, fixed, and refuses to be superposed (for any constant, fixed load). If that is true, it would certainly stop the present raging debate in its tracks. -- 73, Cecil http://www.w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
Gene Fuller wrote: Cecil Moore wrote: This is steady-state after the wave interaction. What you guys don't seem to realize is that s11(a1) and s12(a2) are continually changing, continually interacting, and a1 & a2 are rotating phasors changing with time. Utter nonsense. Any setup that includes t0 or t=0 is not steady state. Gene, you obviously misunderstood what I said. There is no t0 or t=0 in my above statement. It is just that the delta-t doesn't change from the transient state to the steady-state. In an s-parameter analysis: The normalized voltage, a1, equals Vi1/SQRT(Z0) where 'i' stands for incident voltage. a2 equals Vi2/SQRT(Z0). These voltages are normally represented in phasor notation but they can just as easily be represented in exponential notation where a1 = Vi1*e^jwt+X and a2 = Vi2*e^jwt+Y, where X and Y are constant phase angles. Thus, the s-parameter equation becomes: b1 = Vi1[cos(wt+X)]/SQRT(Z0) + Vi2[cos(wt+Y)]/SQRT(Z0) = 0 adding the delta-t "tick" gives: b1 = Vi1{cos[w(t+delta-t)+X]}/SQRT(Z0) + Vi2{cos[w(t+delta-t)+Y]}/SQRT(Z0) = 0 Vi1 obviously has to be an equal magnitude to Vi2 and X and Y obviously have to be 180 degrees apart. Given that, for every delta-t "tick" of time, the two real normalized voltages sum to zero. The square of the normalized RMS value gives average power in each wave. The equation can be turned into a differential equation by having delta-t approach zero in the limit. Cecil, I should have know better than to read this with a cup of coffee in my hand. I just snorted coffee all over my keyboard. 8-) 73, Gene W4SZ |
Analyzing Stub Matching with Reflection Coefficients
Gene Fuller wrote:
I should have know better than to read this with a cup of coffee in my hand. I just snorted coffee all over my keyboard. Your highly technical rebuttal of my posting is noted. Have you ever seen the equation? The integral of e to the x = function of u to the n __ |_ __|e^x = F(u^n) -- 73, Cecil http://www.w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
Gene Fuller wrote:
I should have know better than to read this with a cup of coffee in my hand. I just snorted coffee all over my keyboard. Gene, I've got an experiment for you. Go to: http://micro.magnet.fsu.edu/primer/j...ons/index.html and set one phase to 0 and the other phase to 180 degrees. Then get an index card and cover up everything to the left except one point on each wave. All you see is those two single points moving up and down. That gives you a visual idea of how s11(a1) and s12(a2) originate and are canceled at a Z0-match *point*. Plot those points back in time and you will have a history of the canceled waves from which you can compute average power density as |s11(a1)|^2 and |s12(a2|^2. -- 73, Cecil http://www.w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
Cecil Moore wrote:
Gene Fuller wrote: I should have know better than to read this with a cup of coffee in my hand. I just snorted coffee all over my keyboard. Gene, I've got an experiment for you. Go to: http://micro.magnet.fsu.edu/primer/j...ons/index.html and set one phase to 0 and the other phase to 180 degrees. Then get an index card and cover up everything to the left except one point on each wave. All you see is those two single points moving up and down. That gives you a visual idea of how s11(a1) and s12(a2) originate and are canceled at a Z0-match *point*. Plot those points back in time and you will have a history of the canceled waves from which you can compute average power density as |s11(a1)|^2 and |s12(a2|^2. Cecil, You are going to pull a brain muscle by stretching so much. Are you suggesting that two wiggling points on a web page are the key to understanding the universe? Here's a thought experiment for you. Read the message by Tom, K7ITM, where he copied a quote from physicsforums.com. See if you can figure out how those waves you insist are created and then quickly canceled (delta-t later) might have never existed in the first place. Hint: waves don't interact with each other, but they do interact with materials containing electrons. (I believe that covers quite a few materials.) 73, Gene W4SZ |
Analyzing Stub Matching with Reflection Coefficients
On Apr 21, 8:35 am, Cecil Moore wrote:
Keith Dysart wrote: I have certainly never said that. If you could point me to the words that misled you into thinking that, I will attempt to clarify your misunderstanding. Correct me if I'm wrong. I understood you to say that energy cannot flow past an instantaneous zero energy point yet there is an instantaneous zero energy point every 1/2WL in an EM traveling wave. Actually I said a zero power point, but you are essentially correct. If the zero power point is stationary then no energy can be flowing. When energy is flowing, either there is no zero power point, or the zero power point is moving as well. At a given point on the line, when the voltage or current is always zero then no energy is flowing. When energy is flowing, the voltage and current will not always be zero at that point. There can also be a voltage and current but they can be 90 degrees out of phase so no net energy flows. In this case, energy will flow first forward then backwards with an average of zero. ....Keith |
Analyzing Stub Matching with Reflection Coefficients
On Apr 21, 8:47 am, Cecil Moore wrote:
Keith Dysart wrote: Nothing to sweep under the rug, I am afraid. It is key that the dissipation depends on the design of the generator. Some times those 'reverse watts' cause the dissipation to drop to 0, sometimes they cause it to increase by a factor of 4, sometimes they cause it to increase by the numerical value of the 'reverse watts'. Pretty much hard to argue that those 'reverse watts' are real when their heating effect is so variable. Not at all. The heating effect depends upon how much of the reverse joules/sec are re-reflected. If the dissipation drops to 0, that is prima facie evidence that all the reflected joules/sec have been re-reflected. If the dissipation increases by a factor of 4, that is prima facie evidence that all of the reflected joules/sec are being dissipated in the source along with all of the joules/sec available from the source into a matched load. Anything else would violate the conservation of energy principle. So you expect that some of the reverse wave is reflected at the generator and yet experiment has shown that none of the reverse wave is reflected at the generator when the generator] source impedance is the same as the line characteristic impedance. I am curious as to why you ignore these experimental results. I'd suggest you think of power as a quantity not a situation. Superposition works for linear, time invariant circuits with multiple sources. Check any text book. The generators and lines under discussion meet these requirements. But superposition obviously doesn't work at the source *point*. One possible technical conclusion may be that the dynamic active source is constant, fixed, and refuses to be superposed (for any constant, fixed load). If that is true, it would certainly stop the present raging debate in its tracks. As you noted previously, it does not matter whether the reverse wave is created by a reflection or another generator. So the experiment has been done with a generator at both ends of the line and the results are entirely consistent with the results predicted using the generator source impedance to compute the amount of reflection. I am curious as to why you ignore these results. And, of course, there results are consistent with the analysis described in any basic text book on transmission lines. ....Keith |
Analyzing Stub Matching with Reflection Coefficients
Gene Fuller wrote:
You are going to pull a brain muscle by stretching so much. Are you suggesting that two wiggling points on a web page are the key to understanding the universe? No, just wave cancellation. If the graphic is completely incorrect, as you say, why did they publish it? -- 73, Cecil http://www.w5dxp.com |
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