Analyzing Stub Matching with Reflection Coefficients
 

Keith Dysart wrote:
Could you clarify; At what frequency does the signal in the
transmission line become "EM" energy?

Additional Hint: Try storing the energy in a light wave
in a capacitor.
--
73, Cecil http://www.w5dxp.com

Analyzing Stub Matching with Reflection Coefficients
 

On Mon, 23 Apr 2007 18:03:20 -0500, Cecil Moore
wrote:
(another, less profound question: "When did caps stop working in tank
circuits?")
When the tank gets hit by a Scud missile?

Ah yes! The only thing we have here is entertainment value.
Unfortunately this is how vaudeville died.

Analyzing Stub Matching with Reflection Coefficients
 

Cecil Moore wrote:

Good grief, Jim, are you too lazy to perform the math???

Squaring both sides of the above equation to obtain
joules/sec:

Voltage squared does not EQUAL joules/sec (still).

b1^2 = |s11(a1)|^2 + 2*s11(a1)*s12(a2) + |s12(a2)|^2

and from an earlier post:

HP would simply observe that what b1 = 0 means is that there is no
energy and there are no waves moving in the direction of b1.

Yes, and HF also observes that, e.g.:

|s11(a1)|^2 = 1 joule/sec

|s12(a2)|^2 = 1 joule/sec

From which it follows that 0 = 4.

You might want to consider performing the math yourself before you
post it.

73, Jim AC6XG

Analyzing Stub Matching with Reflection Coefficients
 

Cecil Moore wrote:

Keith Dysart wrote:

Could you clarify; At what frequency does the signal in the
transmission line become "EM" energy?


Additional Hint: Try storing the energy in a light wave
in a capacitor.

Ever hear of a CCD camera?

73, ac6xg

Analyzing Stub Matching with Reflection Coefficients
 

Jim Kelley wrote:
Squaring both sides of the above equation to obtain
joules/sec:

Voltage squared does not EQUAL joules/sec (still).

That shows exactly how much you understand the s-parameter
analysis. The s-parameter voltages have been normalized such
that the square of the normalized voltage is indeed equal to
joules/sec. If you had paid attention, or were half as smart
as you think you are, or even read HP Ap Note 95-1, you would
have realized that fact a long time ago and not be showing
your ignorance here and now.

From which it follows that 0 = 4.

Obviously either an ignorant response or an obfuscation.
It follows that the result of destructive interference is
zero while the result of constructive interference is 4,
just as Born and Wolf asserted in "Principles of Optics",
Chapter VII.

Imin = I1 + I2 +2*SQRT(I1*I2) = 0 equation (16b)

Imax = I1 + I2 + 2*SQRT(I1*I2) equation (16a)

If I1=I2, then Imax = 4*I1 equation (17)

There's your 0 and 4, Jim, straight from Born and Wolf.
Now you can assert that Born and Wolf have been discredited
just as you asserted that Hecht has been discredited.
--
73, Cecil http://www.w5dxp.com

Analyzing Stub Matching with Reflection Coefficients
 

Jim Kelley wrote:

Cecil Moore wrote:
Additional Hint: Try storing the energy in a light wave
in a capacitor.

Tsk, tsk! You unethically trimmed the context, Jim. Try
storing the energy in a light wave in a capacitor and then
recovering that same energy coherent with the original wave.

Ever hear of a CCD camera?

I've never heard of a CCD camera that stored EM waves.
Exactly how long does a CCD camera store EM waves?
Does it store them in a delay line or what?
--
73, Cecil http://www.w5dxp.com

Analyzing Stub Matching with Reflection Coefficients
 

Jim Kelley wrote:

Cecil Moore wrote:
Squaring both sides of the above equation to obtain
joules/sec:

Voltage squared does not EQUAL joules/sec (still).

What dimensions do you get when you perform the
following operation using the s-parameter dimensions
of a1, a2, b1, and b2?

[volts/SQRT(Z0)]^2 = _____________

Apparently, that is a really tough one for you since
you have failed to comprehend it for weeks now.

[volts/SQRT(Z0)]^2 = volts^2/Z0

Maybe if I simplified it to V^2/R, you would recognize
it as joules/sec?
--
73, Cecil http://www.w5dxp.com

Analyzing Stub Matching with Reflection Coefficients
 

Jim Lux wrote:
Sources are linear.

Can we agree that class-B, class-C, class-D,
and class-E sources are not linear?
--
73, Cecil http://www.w5dxp.com

Analyzing Stub Matching with Reflection Coefficients
 

Cecil Moore wrote:
Imin = I1 + I2 +2*SQRT(I1*I2) = 0 equation (16b)

Typo there - should be:

Imin = I1 + I2 - 2*SQRT(I1*I2) = 0 equation (16b)
--
73, Cecil http://www.w5dxp.com

Analyzing Stub Matching with Reflection Coefficients
 

On Apr 23, 6:23 pm, Cecil Moore wrote:
Jim Kelley wrote:

Cecil Moore wrote:
Additional Hint: Try storing the energy in a light wave
in a capacitor.

Tsk, tsk! You unethically trimmed the context, Jim.

Hi Cecil -

I included your entire post - Keith's remarks and yours. Please
refrain from making ad hominem remarks. Particularly baseless ones.

Ever hear of a CCD camera?

I've never heard of a CCD camera that stored EM waves.

The context of your remark, which you have now deleted, was "energy
from EM waves". The little capacitors in a charge coupled device store
the light energy until it is read-out and converted to digital.

73, Jim AC6XG