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Rotational speed
Cecil Moore wrote:
The standing wave current phasor has the "same rotational speed as its components"??? It has to. Thankfully, rotational speed is the one thing that does not change between the radio and the antenna. How can that be when the forward current phasor and the reflected current phasor are rotating in opposite directions? Rotational speed has nothing to do with direction of travel. It has only to do with the source. Rotational speed is simply omega; 2pi*c/wavelength, or 2pi*f. When waves of equal frequency are traveling in opposite directions, the RF waveform which comprises the standing wave (the latter being simply the amplitude envelope of the superposed traveling waves) has the same wavelength, and thus the same rotational speed as the traveling waves. Although the position of the peaks does not vary with time, their amplitude is still a time varying function. This rudimentary effect is illustrated in the movie he http://www.kettering.edu/~drussell/D...rposition.html Mixing on the other hand is the product (rather than the sum) of two or more waveforms and does in fact yield different rotational speeds. 73, Jim AC6XG |
Analyzing Stub Matching with Reflection Coefficients
On 26 Apr 2007 16:39:41 -0700, Keith Dysart wrote:
Is there some other fault in the model that makes it sufficiently incorrect to be unusable? The story of the Princess and the Pea. How many mattresses before the Princess will be satisfied? 73's Richard Clark, KB7QHC |
Rotational speed
Jim Kelley wrote:
. . . Mixing on the other hand is the product (rather than the sum) of two or more waveforms and does in fact yield different rotational speeds. And multiplying voltage and current waveforms, or squaring a voltage or current waveform to get power gives a wave with double the rotational speed and, unless V and I are in quadrature, a DC offset. Roy Lewallen, W7EL |
Analyzing Stub Matching with Reflection Coefficients
Keith Dysart wrote:
Certainly the model I described is linear. Is there some other fault in the model that makes it sufficiently incorrect to be unusable? Yes, it doesn't model a class-C amplifier. -- 73, Cecil http://www.w5dxp.com |
Rotational speed
Jim Kelley wrote:
Rotational speed has nothing to do with direction of travel. I assumed that the "same rotational speed" implies the same direction. -- 73, Cecil http://www.w5dxp.com |
Rotational speed
Cecil Moore wrote:
Jim Kelley wrote: Rotational speed has nothing to do with direction of travel. I assumed that the "same rotational speed" implies the same direction. The reason I assumed that is this assertion by W7EL. "This is the total current. It has magnitude and phase like any other phasor, and the same rotational speed as its components." The total current, as graphed by Kraus and displayed by EZNEC *DOES NOT* have the same rotational speed as its components. It is obvious that Roy meant the same direction when he said "same rotational speed". -- 73, Cecil http://www.w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
On Apr 26, 9:12 pm, Cecil Moore wrote:
Keith Dysart wrote: Certainly the model I described is linear. Is there some other fault in the model that makes it sufficiently incorrect to be unusable? Yes, it doesn't model a class-C amplifier. Ah yes. At first there was a reason. But then that was taken care of, so now we have well... welll... well... It just does NOT model it. Rather lame, methinks. ....Keith |
Analyzing Stub Matching with Reflection Coefficients
Keith Dysart wrote:
It just does NOT model it. You got it. Einstein said an explanation should be as simple as possible, but not too simple. There is too much evidence gathered over decades of arguments for simple-minded models to work anywhere except in your dreams. Your earlier example proved it. In a source with absolute zero power, you claimed that all the reflected power was being dissipated in that source. Maybe you should fix your trivial model before tackling anything more complicated. -- 73, Cecil http://www.w5dxp.com |
Analyzing Stub Matching with Reflection Coefficients
On Apr 26, 9:48 pm, Cecil Moore wrote:
Keith Dysart wrote: It just does NOT model it. You got it. Einstein said an explanation should be as simple as possible, but not too simple. There is too much evidence gathered over decades of arguments for simple-minded models to work anywhere except in your dreams. Okay, so you can't find anything to point at that is wrong with the model. You could always ask. I could point to a few things that are arguably weak with the model. Your earlier example proved it. In a source with absolute zero power, you claimed that all the reflected power was being dissipated in that source. Of course I claimed no such thing; you do need to read more carefully. And you have conveniently neglected the other example which was presented right beside for which 4 times the "reflected power" was dissipated by the source. These two copmletely different results call into question the nature of "reflected power". ....Keith |
Analyzing Stub Matching with Reflection Coefficients
Keith Dysart wrote:
Okay, so you can't find anything to point at that is wrong with the model. What is wrong with the model is that it doesn't work in reality. Neither does the 6000 year old model of the age of the earth. Of course I claimed no such thing; you do need to read more carefully. And you have conveniently neglected the other example which was presented right beside for which 4 times the "reflected power" was dissipated by the source. These two copmletely different results call into question the nature of "reflected power". No, they call into question the validity of the model. The reflected energy is there and can be dissipated by a circulator load. That the model gets it wrong is proof of an invalid model, not proof that photons contain zero energy. Photons contain energy that obeys the conservation of energy principle. The fact that zero energy is dissipated in a source is prima facie evidence of destructive interference and a "redistribution of energy in a direction that allows constructive interference". Understanding interference is the key and your model doesn't even mention interference. -- 73, Cecil http://www.w5dxp.com |
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