| Home |
| Search |
| Today's Posts |
|
|
|
#2
|
|||
|
|||
|
In article ,
Don Bowey wrote: On 7/6/07 12:15 PM, in article , "isw" wrote: In article , Don Bowey wrote: On 7/6/07 9:36 AM, in article , "isw" wrote: In article , Don Bowey wrote: On 7/5/07 10:27 PM, in article , "Ron Baker, Pluralitas!" wrote: "Don Bowey" wrote in message ... On 7/5/07 12:00 AM, in article , "Ron Baker, Pluralitas!" wrote: "Don Bowey" wrote in message ... On 7/4/07 8:42 PM, in article , "Ron Baker, Pluralitas!" wrote: "Don Bowey" wrote in message ... On 7/4/07 10:16 AM, in article , "Ron Baker, Pluralitas!" wrote: "Don Bowey" wrote in message ... On 7/4/07 7:52 AM, in article , "Ron Baker, Pluralitas!" wrote: snip cos(a) * cos(b) = 0.5 * (cos[a+b] + cos[a-b]) Basically: multiplying two sine waves is the same as adding the (half amplitude) sum and difference frequencies. No, they aren't the same at all, they only appear to be the same before they are examined. The two sidebands will not have the correct phase relationship. What do you mean? What is the "correct" relationship? One could, temporarily, mistake the added combination for a full carrier with independent sidebands, however. (For sines it is sin(a) * sin(b) = 0.5 * (cos[a-b]-cos[a+b]) = 0.5 * (sin[a-b+90degrees] - sin[a+b+90degrees]) = 0.5 * (sin[a-b+90degrees] + sin[a+b-90degrees]) ) -- rb When AM is correctly accomplished (a single voiceband signal is modulated The questions I posed were not about AM. The subject could have been viewed as DSB but that wasn't the specific intent either. What was the subject of your question? Copying from my original post: Suppose you have a 1 MHz sine wave whose amplitude is multiplied by a 0.1 MHz sine wave. What would it look like on an oscilloscope? What would it look like on a spectrum analyzer? Then suppose you have a 1.1 MHz sine wave added to a 0.9 MHz sine wave. What would that look like on an oscilloscope? What would that look like on a spectrum analyzer? So the first (1) is an AM question and the second (2) is a non-AM question...... What is the difference between AM and DSB? AM is a process. DSB (double sideband), with carrier, is it's most simple result. DSB without carrier (suppressed carrier dsb) requires using, at least, a balanced mixer as the AM multiplier. And requires, for proper reception, that a carrier be recreated at the receiver which has not only the amplitude of the original, There is no need at all to match the carrier amplitude of the original signal. You can use an excessively high carrier injection amplitude with no detrimental affect, but if the injected carrier is too little, the demodulated signal will be over modulated and sound distorted. but also its exact phase. Exact, not required. The closer the better, however. Well, OK, the phase must at least bear a constant relationship to the one that created the signal. If you inject a carrier that has a quadrature relationship to the one that created the DSB signal, the output will be PM (phase modulation). In between zero and 90 degrees, the output is a combination of the two. If the injected carrier is not at precisely the proper frequency, the phase will roll around and the output will be unintelligible. Not unintelligible.... Donald Duckish. I think you are confusing *single* sideband, for which that is correct, and *double* sideband (which we were discussing), for which it is not true. On a more practical side, however, most receiver filters for ssb will essentially remove one sideband if there are two, and can attenuate a carrier so the local product detector can do it's job resulting in improved receiving conditions. But this is more advanced than the Ops questions. Doing it that way will work, but it's not "fair", because you are not actually demodulating a DSB signal (which was the subject of the discussion). Isaac |
|
#3
|
|||
|
|||
|
On 7/6/07 8:21 PM, in article
, "isw" wrote: In article , Don Bowey wrote: On 7/6/07 12:15 PM, in article , "isw" wrote: In article , Don Bowey wrote: On 7/6/07 9:36 AM, in article , "isw" wrote: In article , Don Bowey wrote: On 7/5/07 10:27 PM, in article , "Ron Baker, Pluralitas!" wrote: "Don Bowey" wrote in message ... On 7/5/07 12:00 AM, in article , "Ron Baker, Pluralitas!" wrote: "Don Bowey" wrote in message ... On 7/4/07 8:42 PM, in article , "Ron Baker, Pluralitas!" wrote: "Don Bowey" wrote in message ... On 7/4/07 10:16 AM, in article , "Ron Baker, Pluralitas!" wrote: "Don Bowey" wrote in message ... On 7/4/07 7:52 AM, in article , "Ron Baker, Pluralitas!" wrote: snip cos(a) * cos(b) = 0.5 * (cos[a+b] + cos[a-b]) Basically: multiplying two sine waves is the same as adding the (half amplitude) sum and difference frequencies. No, they aren't the same at all, they only appear to be the same before they are examined. The two sidebands will not have the correct phase relationship. What do you mean? What is the "correct" relationship? One could, temporarily, mistake the added combination for a full carrier with independent sidebands, however. (For sines it is sin(a) * sin(b) = 0.5 * (cos[a-b]-cos[a+b]) = 0.5 * (sin[a-b+90degrees] - sin[a+b+90degrees]) = 0.5 * (sin[a-b+90degrees] + sin[a+b-90degrees]) ) -- rb When AM is correctly accomplished (a single voiceband signal is modulated The questions I posed were not about AM. The subject could have been viewed as DSB but that wasn't the specific intent either. What was the subject of your question? Copying from my original post: Suppose you have a 1 MHz sine wave whose amplitude is multiplied by a 0.1 MHz sine wave. What would it look like on an oscilloscope? What would it look like on a spectrum analyzer? Then suppose you have a 1.1 MHz sine wave added to a 0.9 MHz sine wave. What would that look like on an oscilloscope? What would that look like on a spectrum analyzer? So the first (1) is an AM question and the second (2) is a non-AM question...... What is the difference between AM and DSB? AM is a process. DSB (double sideband), with carrier, is it's most simple result. DSB without carrier (suppressed carrier dsb) requires using, at least, a balanced mixer as the AM multiplier. And requires, for proper reception, that a carrier be recreated at the receiver which has not only the amplitude of the original, There is no need at all to match the carrier amplitude of the original signal. You can use an excessively high carrier injection amplitude with no detrimental affect, but if the injected carrier is too little, the demodulated signal will be over modulated and sound distorted. but also its exact phase. Exact, not required. The closer the better, however. Well, OK, the phase must at least bear a constant relationship to the one that created the signal. If you inject a carrier that has a quadrature relationship to the one that created the DSB signal, the output will be PM (phase modulation). In between zero and 90 degrees, the output is a combination of the two. If the injected carrier is not at precisely the proper frequency, the phase will roll around and the output will be unintelligible. Not unintelligible.... Donald Duckish. I think you are confusing *single* sideband, for which that is correct, and *double* sideband (which we were discussing), for which it is not true. What do you propose the term be for the output of a slightly de-tuned demodulator of a DSB sans carrier, signal? On a more practical side, however, most receiver filters for ssb will essentially remove one sideband if there are two, and can attenuate a carrier so the local product detector can do it's job resulting in improved receiving conditions. But this is more advanced than the Ops questions. Doing it that way will work, but it's not "fair", because you are not actually demodulating a DSB signal (which was the subject of the discussion). I don't believe the OP stated whether the DSB signal was with or without carrier. If without carrier, demodulation is certainly called for. If with carrier, it hardly merits discussion. Isaac |
|
#4
|
|||
|
|||
|
In article ,
Don Bowey wrote: --bunch of stuff trimmed off-- Well, OK, the phase must at least bear a constant relationship to the one that created the signal. If you inject a carrier that has a quadrature relationship to the one that created the DSB signal, the output will be PM (phase modulation). In between zero and 90 degrees, the output is a combination of the two. If the injected carrier is not at precisely the proper frequency, the phase will roll around and the output will be unintelligible. Not unintelligible.... Donald Duckish. I think you are confusing *single* sideband, for which that is correct, and *double* sideband (which we were discussing), for which it is not true. What do you propose the term be for the output of a slightly de-tuned demodulator of a DSB sans carrier, signal? I'm not sure it has a name. The output is constantly swishing around between AM and PM, at a rate determined by the frequency error of the reinjected carrier. Most detectors will have a problem with it. Isaac |
| Reply |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Forum | |||
| AM electromagnetic waves: astronomically-high modulation frequency on an astronomically-low carrier frequency | Antenna | |||
| AM electromagnetic waves: astronomically-high modulation frequency on an astronomically-low carrier frequency | Shortwave | |||
| DC waves??? Magic frequency??? | Antenna | |||
| Electromagnetic frequency allocations in xml ? | General | |||
| Which digital readout receivers always show the carrier frequency no matter what mode? | Shortwave | |||