K7ITM wrote:

...
On the other hand, there's probably not much utility in discussing
photons of, say, a 14MHz signal, simply because the energy contained
in one quantum at that frequency is so small that you won't be able to
detect it: a little less than 10^-26 joules per photon. At one
photon per second, that's under 10^-26 watts, if you collect all the
energy. At 50 ohms, that's less than a picovolt. Noise in a 1Hz
bandwidth in a 50 ohm resistor at room temperature is about a
thousand times that much. -- Yes, the energy is quantized. But the
quanta are going to be _very_ difficult to distinguish.

Cheers,
Tom


If there are, indeed, as many photons being emitted by the thin edge of
the ribbon, as by the broad edges, what law/effect/affect is being
demonstrated here?

Or. why are the photons "drawn" to the thin edge with such magnitude of
force?

If this ribbon was white hot (even infrared) a meter would indicate more
energy from the greatest surface area. Occams' razor is wrong, again?

I have never read of the phenomenon you seem to be suggesting here ...

Regards,
JS

John Smith wrote:

...
I have never read of the phenomenon you seem to be suggesting here ...

Regards,
JS

Actually, that is not quite true as stated. I should have said, "I have
not read of that phenomenon occurring with photons. Electrons? Yes.
Photons? No.

Regards,
JS

John Smith wrote:

...
Regards,
JS

And, oh.

The missing double quotes, for Richards benefit == " :-)

JS

On Wed, 29 Aug 2007 17:35:40 -0700, John Smith
wrote:

If there are, indeed, as many photons being emitted by the thin edge of
the ribbon, as by the broad edges, what law/effect/affect is being
demonstrated here?

Try the combination of all amplitudes and phases at a distance (pretty
usual stuff already covered).

Or. why are the photons "drawn" to the thin edge with such magnitude of
force?

What force? Give us a number, Tom did.

If this ribbon was white hot (even infrared) a meter would indicate more
energy from the greatest surface area. Occams' razor is wrong, again?

I have never read of the phenomenon you seem to be suggesting here ...

Consult Planck where it (predating the term photon) is summed up in
two variables and one constant.

73's
Richard Clark, KB7QHC

Richard Clark wrote:

...
Try the combination of all amplitudes and phases at a distance (pretty
usual stuff already covered).
...
73's
Richard Clark, KB7QHC

For you Richard, just remember to stand the broadside of a stove on cold
winter days--wouldn't want 'ya to catch yer death of cold! :-)

Regards,
JS

On Wed, 29 Aug 2007 18:22:30 -0700, John Smith
wrote:

For you Richard, just remember to stand the broadside of a stove on cold
winter days--wouldn't want 'ya to catch yer death of cold! :-)

That has nothing to do with Photons.

73's
Richard Clark, KB7QHC

Richard Clark wrote:

...
That has nothing to do with Photons.

73's
Richard Clark, KB7QHC

Your post has nothing to do with my wifes' earlier email!

Well, other than they are both text, both sent over the internet, both
are smtp protocols, both are typed, both required the use of a computer,
both were/are in english--well, 'ya know what I mean ... :-)

Regards,
JS

On Wed, 29 Aug 2007 18:35:10 -0700, John Smith
wrote:

Well, other than they are both text, both sent over the internet, both
are smtp protocols

Even there you remain in error. NNTP. (nothing notably transmitting
photons) protocol.

73's
Richard Clark, KB7QHC

Richard Clark wrote:

...
73's
Richard Clark, KB7QHC

Yes, you are in error, NNTP is only a superset of smtp ... :-(

Regards,
JS

On Aug 29, 5:35 pm, John Smith wrote:
K7ITM wrote:

...

On the other hand, there's probably not much utility in discussing
photons of, say, a 14MHz signal, simply because the energy contained
in one quantum at that frequency is so small that you won't be able to
detect it: a little less than 10^-26 joules per photon. At one
photon per second, that's under 10^-26 watts, if you collect all the
energy. At 50 ohms, that's less than a picovolt. Noise in a 1Hz
bandwidth in a 50 ohm resistor at room temperature is about a
thousand times that much. -- Yes, the energy is quantized. But the
quanta are going to be _very_ difficult to distinguish.

Cheers,
Tom

If there are, indeed, as many photons being emitted by the thin edge of
the ribbon, as by the broad edges, what law/effect/affect is being
demonstrated here?

Or. why are the photons "drawn" to the thin edge with such magnitude of
force?

The 14MHz photons are being emitted by the whole antenna, not by
"broad edges" or "thin edges" as you suggest. You seem to be thinking
of them as little tiny balls, or some such. That mental image just
doesn't hold water. As I posted elsewhere in this thread, photons do
not behave like billiard balls. They don't behave like anything you
have encountered in the macro world we live in.

There are some decent "modern physics for the masses" books that will
explain to you some of the behaviour that you will probably think very
strange, if you are thinking in terms of how the macro particles
you're familiar with behave. Even particles like electrons, neutrons
and protons don't behave like large spheres. They have distinct "wave-
like" behaviour.

As a start, it would probably help if you dropped "wave" and
"photon" (particle) from your vocabulary when dealing with things like
this and realize that the antenna emits a stream of quantized energy,
with characteristics that can be described accurately without
resorting to "particles" or "waves". If you had no idea what a
passenger airplane was, but you were familiar with birds and busses,
would you get into a discussion about the new thing being a bird and
not a bus, or a bus and not a bird? Or would you realize that it has
some characteristics of each, but is neither, and deserves a
description all its own? Quantized radiation is rather like that.
You will NOT describe it accurately as either "waves" or
"particles" (in the macro sense).

Cheers,
Tom