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Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
Cecil Moore wrote: Once again, you have refused to answer a simple question. If E and H are not zero, how can ExH be zero? What is this? The RRAA version of "When did you stop beating your wife?" No, this is the RRAA version of someone unwilling to accept technical facts. Your name is Legion. -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Jim Kelley wrote:
You fail to explain how any of that makes energy unavailable for "radiation purposes". This is not rocket science. If the energy is being used to transform impedances, it is obviously unavailable to be lost as radiation. If all the forward energy is radiated by the antenna, there exists no impedance transformation in the transmission line. A highly technical quote must be needed: "You can't have your energy cake and eat it too." :-) -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote:
Gene Fuller wrote: The graph is complete nonsense. There is no rotation of the fields when they undergo reflection. Any ordinary text on E&M or optics will show you the equations and the correct sketches. Good grief, Gene. There is a 360 degree rotation in the fields every wavelength. The direction of rotation is associated with the direction of travel of the wave and is displayed by EZNEC when the current phase option is turned on. All you have to do to see the rotation of the traveling wave is to download http://www.w5dxp.com/rhombicT.EZ Those simplified sketches are making you simple-minded. Assuming you are a member of the IEEE, look up this paper: "Rotation in electromagnetic field equations". Or Google "Rotation and the Electromagnetic Field". "Optics", by Hecht, is one of your ordinary texts. That is where the material for that graph comes from. The IEEE Dictionary says: "E and H are the electric and magnetic field vectors in phasor notation". If that graph is nonsense to you, it is your fault, not mine. Hecht says "Optics", 4th edition, page 289, about standing waves: "The composite disturbance is then: E = Eo[sin(kx+wt) + sin(kx-wt)] Applying the identity: sin A + sin B = 2 sin 1/2(A+B)*cos 1/2(A-B) yields: E(x,t) = 2*Eo*sin(kx)*cos(wt)" "This is the equation for a STANDING or STATIONARY WAVE, as opposed to a traveling wave. Its profile does not move through space; it is clearly not of the form Func(x +/- vt)." "... a phasor rotating counterclockwise at a rate omega is equivalent to a wave traveling to the left (decreasing x), and similarly, one rotating clockwise corresponds to a wave traveling to the right (increasing x)." Hecht uses phasors to represent EM waves all through his book. He explains the standing wave E-field based on the two traveling waves, E1-field and E2-field, thusly: "The resultant phasor is E1 + E2 = E ... Keeping the two [traveling wave] phasors tip-to-tail and having E1 rotate counterclockwise as E2 rotates (at the same rate) clockwise, generates E [total] as a function of 't'." [Standing wave phase] "doesn't rotate at all, and the resultant wave it represents doesn't progress through space - its a standing wave." Traveling wave phase rotates. Standing wave phase doesn't. Speaking of "... net transfer of energy, for the pure standing wave there is none." The forward wave and reflected wave E-field and H-field vectors are represented by phasors just as indicated in the IEEE Dictionary. One is rotating clockwise and the other is rotating counterclockwise. The Poynting vector for a pure standing wave is equal to zero just as illustrated in my graph at: http://www.w5dxp.com/EHSuper.JPG Given those boundary conditions and solving for the angle between the standing wave E-field and H-field yields 0 or 180 degrees. Are you really more interested in presenting false information and saving face than you are in valid technical facts? Cecil, This is truly sad. I thought you had finally begun to understand this stuff, but you have regressed back into the same old nonsense. You are still totally confusing phasors with field vectors. They are utterly, totally, and absolutely unrelated. Get help. Call me what you like. Bye. 73, Gene W4SZ |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
Any ordinary text on E&M or optics will show you the equations and the correct sketches. Please stop staring at your simple-minded sketches and stare at this diagram of an EM wave for awhile. Maybe you are due for an epiphany. http://www.w5dxp.com/EHWave.JPG -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
Cecil Moore wrote: Jim Kelley wrote: You fail to explain how any of that makes energy unavailable for "radiation purposes". This is not rocket science. Or any other kind of science for that matter. If the energy is being used to transform impedances, it is obviously unavailable to be lost as radiation. Sure, assuming energy is being "used" to perform an operation in which no work is done. You'll need to prove the first part of the sentence in order to show the second part to be true. ac6xg |
Standing morphing to travelling waves, and other stupid notions
Gene Fuller wrote:
This is truly sad. I thought you had finally begun to understand this stuff, but you have regressed back into the same old nonsense. You are still totally confusing phasors with field vectors. They are utterly, totally, and absolutely unrelated. Saying that doesn't make it true, Gene, although it may hoodwink some of the uninitiated into believing your old wives' tales. I just posted a more sophisticated diagram of an EM wave for you at: http://www.w5dxp.com/EHWave.JPG Have those simple-minded sketches that you have been staring at made you simple-minded or are you capable of something else? -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
On 18 Jan, 10:52, Cecil Moore wrote:
Gene Fuller wrote: The graph is complete nonsense. There is no rotation of the fields when they undergo reflection. Any ordinary text on E&M or optics will show you the equations and the correct sketches. Good grief, Gene. There is a 360 degree rotation in the fields every wavelength. The direction of rotation is associated with the direction of travel of the wave and is displayed by EZNEC when the current phase option is turned on. All you have to do to see the rotation of the traveling wave is to downloadhttp://www.w5dxp.com/rhombicT.EZ Those simplified sketches are making you simple-minded. Assuming you are a member of the IEEE, look up this paper: "Rotation in electromagnetic field equations". Or Google "Rotation and the Electromagnetic Field". "Optics", by Hecht, is one of your ordinary texts. That is where the material for that graph comes from. The IEEE Dictionary says: "E and H are the electric and magnetic field vectors in phasor notation". If that graph is nonsense to you, it is your fault, not mine. Hecht says "Optics", 4th edition, page 289, about standing waves: "The composite disturbance is then: E = Eo[sin(kx+wt) + sin(kx-wt)] Applying the identity: sin A + sin B = 2 sin 1/2(A+B)*cos 1/2(A-B) yields: E(x,t) = 2*Eo*sin(kx)*cos(wt)" "This is the equation for a STANDING or STATIONARY WAVE, as opposed to a traveling wave. Its profile does not move through space; it is clearly not of the form Func(x +/- vt)." "... a phasor rotating counterclockwise at a rate omega is equivalent to a wave traveling to the left (decreasing x), and similarly, one rotating clockwise corresponds to a wave traveling to the right (increasing x)." Hecht uses phasors to represent EM waves all through his book. He explains the standing wave E-field based on the two traveling waves, E1-field and E2-field, thusly: "The resultant phasor is E1 + E2 = E *... Keeping the two [traveling wave] phasors tip-to-tail and having E1 rotate counterclockwise as E2 rotates (at the same rate) clockwise, generates E [total] as a function of 't'." [Standing wave phase] "doesn't rotate at all, and the resultant wave it represents doesn't progress through space - its a standing wave." Traveling wave phase rotates. Standing wave phase doesn't. Speaking of "... net transfer of energy, for the pure standing wave there is none." The forward wave and reflected wave E-field and H-field vectors are represented by phasors just as indicated in the IEEE Dictionary. One is rotating clockwise and the other is rotating counterclockwise. The Poynting vector for a pure standing wave is equal to zero just as illustrated in my graph at:http://www.w5dxp.com/EHSuper.JPG Given those boundary conditions and solving for the angle between the standing wave E-field and H-field yields 0 or 180 degrees. Are you really more interested in presenting false information and saving face than you are in valid technical facts? -- 73, Cecil *http://www.w5dxp.com Cecil, Just a small question. Do you include in your analysis of E and H waves the effect of the field produced by a diamagnetic field produced by current flow in the material, where the field has a tendency to be at right angles? This is what PROF Hately was looking to do on his EH invention without understanding the importance of the material used in generating the fields in question. Best regards Art Unwin KB9MZ...xg |
Standing morphing to travelling waves, and other stupid notions
art wrote:
Do you include in your analysis of E and H waves the effect of the field produced by a diamagnetic field produced by current flow in the material, ... Nope, I tend to ignore effects that I judge to be secondary. Of course, I don't even pretend to exercise perfect judgment. -- 73, Cecil http://www.w5dxp.com |
Standing morphing to travelling waves, and other stupid notions
On 18 Jan, 12:15, Cecil Moore wrote:
art wrote: Do you include in your analysis of E and H waves the effect of the field produced by a diamagnetic field produced by current flow in the material, ... Nope, I tend to ignore effects that I judge to be secondary. Of course, I don't even pretend to exercise perfect judgment. -- 73, Cecil *http://www.w5dxp.com But when adding vectors as I see it there is no secondary vectors, which in this case says both vectors are in phase no less.I thought I would probe a bit in this long thread to ascertain where the controversy is. To understand that alone in the face of thousand postings is a very difficult task indeed.Even more so for a mechanical engineer Very best regards Art |
Standing morphing to travelling waves, and other stupid notions
On Jan 18, 12:44*am, art wrote:
On 17 Jan, 20:44, "AI4QJ" wrote: "art" wrote in message ... On 17 Jan, 18:25, "AI4QJ" wrote: "art" wrote in message .... your whole posting is just silly. First you accuse me of lieing now you want to provoke me with stupidity. You need to upgrade to a understanding of a tank circuit.Yes, it is used in your transmitter. Google it and study it. Free speech is great but it also reveals your mentality. And you are just bull ****ing in the absence of knoweledge.." OK art, I notice a great improvement in your having only 3 spelling errors in 5 sentences. You are a fool. If your postings could ever be elevated to the level of mere stupidity, then it might be possible to correct your misconceptions. However, one cannot deal with true insanity by any rational approach such as that. You do not drive me to use Google; you drive me to dictionary.com so I can find the words appropriate to describe the idiocy of your ravings. However, it isn't worth the effort so I will leave you mired in your intellectual wasteland, reading your postings from time to time for the entertainment value of comic relief. For the sake of the hobby I will continue point out the fairy-tale nature of your postings lest the casual reader of this newsgroup ever get the wrong impression of what the typical ham radio operator thinks is antenna "theory". AI4QJ :No, I am not going to insult you, I'm sure you have had you fill of hurling insults at me tonite. Just part of the entertainment. :your own actions show what manner of: :man you are. Pot Kettle Black Tell me how a 1/4W tank circuit in my transmitter works, art. AI4QJ- Hide quoted text - - Show quoted text - You have one in your transmitter and you don't know how it works so you ask me. Why? You can ask KB9..... or the MI5. If you cross post they will get back to you. I promise.They miss you. Maybe one of the above is actually you!- Hide quoted text - - Show quoted text - So you found out that I have a 1/4 wave tank circuit in my transmitter. Only the MI5 could have known that. Hmmm... |
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