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Jim Kelley wrote:
Were it not for waves standing on the coax, there would have been no damage to the coax, ... Were it not for traveling waves, there would be no standing waves and no damage to the coax. Kinda tough to have a standing wave in the absence of traveling waves now, isn't it. Exactly, but that supports my side of the argument. So there's energy in the standing waves, but not power. At the risk of you developing apoplexy, there is reactive power in the standing waves, as defined in The IEEE Dictionary. Probably best not to assume it's a 'different kind of wave' in the first place. Sorry Jim, but [Io*cos(kx)*cos(wt)] and [Io*cos(kx+wt)] *ARE* different. If you don't know enough math to realize that by looking at the equations, please go alleviate your ignorance. Yes I know that's basically what you've been trying to say "all along", but you were saying it so poorly ... Sorry, my native tongue is Texan. :-) -- 73, Cecil http://www.w5dxp.com |
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