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#1
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Just what is a "wave", anyway? Are there different "kinds" of
electromagnetic wave? If so, what are they? Does a "wave" have to travel in order to be a "wave", or can it just "vibrate" or "oscillate"? Or just "stand"? Most of my references call a standing wave a "pattern". Is a "pattern" a "wave"? Can a "wave" be a "pattern"? That should be good for another few hundred posts, at least. Sheesh. Roy Lewallen, W7EL |
#2
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On Jan 9, 11:22 pm, Roy Lewallen wrote:
Just what is a "wave", anyway? Are there different "kinds" of electromagnetic wave? Take a look at the E-field, H-field, and direction of travel for an EM (photonic) wave. An RF standing wave does not behave like an EM wave nor does it meet the definition of an EM wave which can be represented by a Poynting vector. The Poynting vector for an RF standing wave has a magnitude of zero and no direction. -- 73, Cecil, w5dxp.com |
#3
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![]() Cecil Moore wrote: An RF standing wave does not behave like an EM wave nor does it meet the definition of an EM wave which can be represented by a Poynting vector. The Poynting vector for an RF standing wave has a magnitude of zero and no direction. So much for the Poynting vector of a position envelope. What are your thoughts regarding the Poynting vector for a time varying envelope of an electromagnetic wave? :-) ac6xg |
#4
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On Thu, 10 Jan 2008 11:25:56 -0800, Jim Kelley
wrote: the Poynting vector for an RF standing wave has a magnitude of zero and no direction. So much for the Poynting vector of a position envelope. What are your thoughts regarding the Poynting vector for a time varying envelope of an electromagnetic wave? :-) Hi Jim, Imagine even more the dilemma this puts the dipole in! It has suddenly collapsed into a shielded, dummy load. ;-) DAMN! Did my TV screen just go blank? 73's Richard Clark, KB7QHC |
#5
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On Jan 10, 2:34 pm, Richard Clark wrote:
Imagine even more the dilemma this puts the dipole in! It has suddenly collapsed into a shielded, dummy load. ;-) Sorry, the dipole standing waves are only about 80% of the energy on the antenna. The other 20% of the energy is radiated (or lost to heat). If the waves on the 1/2WL dipole were 100% standing waves, the antenna would have a zero feedpoint impedance, but it doesn't -- 73, Cecil, w5dxp.com .. |
#6
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On Thu, 10 Jan 2008 17:35:42 -0800 (PST), Cecil Moore
wrote: dipole standing waves are only about Ah, yes! The devil is in the "about" where Cecil can prove a new fundamental law with errors of only 50%. Naturally, we will have to subscribe to newsletters to find the data. Let me anticipate the next burst of evidence: "But you MUST admit that 1 amp through 1 ohm is 1 volt. Denying this makes you a liar!" 73's Richard Clark, KB7QHC |
#7
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On 10 Jan, 11:25, Jim Kelley wrote:
Cecil Moore wrote: An RF standing wave does not behave like an EM wave nor does it meet the definition of an EM wave which can be represented by a Poynting vector. The Poynting vector for an RF standing wave has a magnitude of zero and no direction. So much for the Poynting vector of a position envelope. *What are your thoughts regarding the Poynting vector for a time varying envelope of an electromagnetic wave? *:-) ac6xg Keep going guys. You are nearly at the end. Must be! Richard has already started on "I knew that all the time" in an effort to take all the credit. Mohammed has come to the mountain and found that Richard the bard was already there.LOL Art Unwin...KB9MZ...XG(uk) |
#8
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On Jan 10, 2:25 pm, Jim Kelley wrote:
So much for the Poynting vector of a position envelope. What are your thoughts regarding the Poynting vector for a time varying envelope of an electromagnetic wave? :-) If the wire runs in the 'x' direction, the standing wave phasors rotate only in the 'yz' plane. Since the Poynting vector is always normal to the E-field and H-field, seems the instantaneous value of the Poynting vector for a standing wave is still zero. -- 73, Cecil, w5dxp.com |
#9
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![]() Cecil Moore wrote: On Jan 10, 2:25 pm, Jim Kelley wrote: So much for the Poynting vector of a position envelope. What are your thoughts regarding the Poynting vector for a time varying envelope of an electromagnetic wave? :-) If the wire runs in the 'x' direction, the standing wave phasors rotate only in the 'yz' plane. A standing wave is an amplitude vs position envelope. An amplitude vs time envelope is modulation! :-) ac6xg |
#10
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On Jan 10, 9:23 pm, Jim Kelley wrote:
A standing wave is an amplitude vs position envelope. Sorry, that is a false statement. Please reference "Fields and Waves in Communication Electronics" by Ramo, Whinnery, and Van Duzer, page 343. The equation for the standing wave voltage is: Ez = Efor*e^j(wt- Bz) + Eref*e^j(wt+Bz) The equation for a standing wave *envelope* does not contain an (omega*t) term. The equation for the *standing wave* indeed does obviously contain (omega*t) terms since the equation for a standing wave is the sum of the two component traveling waves each containing an (omega*t) term. If the (omega*t) term is omitted it is an envelope equation, not a wave equation. -- 73, Cecil, w5dxp.com |
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