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Richard Harrison wrote:
Skin-effect causes both currents, forward and reflected, to ride the surface of the conductor. Some quantum electrodynamics might help. The electrons in the conductor are the carriers and move hardly at all at RF frequencies where electrons can be thought of as vibrating in place, absorbing and emitting photons. It is those photons that move at the speed of light and RF photons cannot travel *inside* a conductor. The cloud of photons in the space surrounding the conductor is the same thing as Maxwell's RF electromagnetic field which, as we assume from conventional physics, cannot exist deep inside a conductor because of skin-effect. Seems to me the present argument results from the confusion between DC steady-state which is electron flow not involving RF photons and RF "steady-state" which cannot exist without RF photons. Photons, unlike electrons, do not have a charge and thus do not repel each other. Any number of photons can occupy the same volume including forward and reflected photons which form the standing wave surrounding the conductor. Let's say we have two pieces of coax with a 'T' connector in the middle. If we short the inside conductor to the outside conductor on both ends and apply RF, what would we measure at the center conductor of the 'T' in the middle? -- 73, Cecil http://www.w5dxp.com |
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