On May 21, 11:30*am, wrote:
....
I was expecting that this only happens in the Netherlands. *I have
some (modern) software where the default plot method is Schmit
Chart...

I agree with the contour plot on a Smith Chart showing losses (and
power handling) for Antenna Tuners.

Best regards,

Wim
PA3DJSwww.tetech.nl
forget first three letters of the alphabet in the PM

Since the points plotted on a Smith chart are simply complex
reflection coefficient plotted on a linear grid, it would be fine with
me if they'd just plot the range of complex reflection coefficient
over which the tuner will operate (perhaps plus contours of constant
loss and power handling ability). The graphs would look identically
the same, except for the grid. I don't suppose any more hams
understand complex reflection coefficient than understand Smith
charts, though.

The Smith chart, to me, remains a very valuable _visualization_ tool.
It matters not how the points on it were calculated or measured. I
think it will always be the case that information properly presented
graphically will generally be easier to understand and easier to draw
conclusions from than information presented in text in tabular form.
Some graphical tools, such as the Smith chart, are worth getting to
know, even if you don't use the chart itself to do calculations,
deferring instead to other calculators for that part. Pictures,
often, are worth much more than 1000 words.

Cheers,
Tom

K7ITM wrote:
The Smith chart, to me, remains a very valuable _visualization_ tool.

Here's a recent posting of mine from eHam.net:

someone wrote: There are very few people out there that
use the Smith Chart.

I'm not suggesting that they actually use a Smith Chart - just that they
learn how to use one and keep the Smith Chart in their heads as a
conceptual tool. With a conceptual image of a Smith Chart in their
heads, they not only know what the input and output impedances are but
also the path the impedance took to get from one point to another. Did
the SWR spiral cross the 50 ohm circle or the 1/50 mho circle during its
transition? If so, matching to 50 ohms is a one component piece of cake.
--
73, Cecil, IEEE, OOTC, http://www.w5dxp.com