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#1
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In , Bill Sloman wrote
in part: I had to work through the equations many years ago for an experiment intended to monitor the process in which one of the "Dewar benzenes" converted itself to normal - Kekule's - benzene, which is an enormously energetic process, involving about an order of magnitude more energy per molecule than you get out of TNT and PETN. I really didn't want to blast my experimental apparatus to smithereens. When I went through the calculations with my supervisor, he pulled a very long face - the motivation for the experiment had been some unexpected flashes of light seen when a dumb organic chemist had released small drops of liquid "Dewar benzene" into a hot cell, and my calculations made it clear that the flashes of light were just thermal radiation from a hot plasma, rather than fluorsecence from from an electronically excited state of Kekule benezene, which is what my supervisor had been hoping for ... For the difference between Dewar benzene and Kekule benzene see http://www.chemsoc.org/exemplarchem/...enzenering.htm If this produces anything near 10x the energy per weight of TNT or PETN, then a version with controlled reaction rate would make one heck of a rocket propellant. I thought the ultimate energy per mass was magnesium and oxygen (or was it beryllium and oxygen?), just a few times as much energy per mass as TNT and not good like usual rocket propellants for producing gas to use as rocket exhaust. I am surely skeptical of changing one isomer of a molecule to another producing even comparable energy to, let alone more energy than decomposition of a similar or somewhat greater mass molecule of high explosive. - Don Klipstein ) |
#2
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In , Jeff Liebermann wrote
in part: Neon lamp needs about 60 volts to light and 40 volts to stay lit. The 4 watt flourescent tube wants at least 90 volts to start, and I think (i.e. guess) about 50 volts to stay lit. Lower voltage neon lamps do indeed light at 60 volts RMS and stay lit at 40 volts RMS. But these are lowish figures. 4-watt fluorescents need more, except they stay lit at only about 30 volts at full current, and part of that reason is thermionic emission from hot electrodes. I would not worry about RF from a cellphone igniting anything. If a cellphone is going to be found to ignite gasoline vapor, I think more likely ways a * Sparks in the vibration motor * Sparks from failing wires/connections * Sparks in speakers with voice coils with intermittent shorts * Sparks in switches (in whatever few models having switches that actually switch enough current to make a spark) I have already seen the Snopes item months ago when I first heard of cellphones supposedly causing gas station fires, and they make it sound as if cellphone ignition of gasoline vapors may never have actually occurred, evidence that this has indeed happened appears mainly anecdotal, and that this is rare if it does happen. When I refuel my car, I keep my cellphone either far or upwind from the gas inlet of my car. (My cellphone has vibration on.) I also ground myself by touching something far/upwind of the fuel inlet if I let go of the nozzle and have to touch the nozzle or anything near the fuel inlet again before leaving the gas station to avoid the greater danger of static electricity. - Don Klipstein ) |
#4
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I read in sci.electronics.design that Jeff Liebermann
wrote (in mppp50ho4dr08ahkb3dlbqkcfkp0ih ) about 'CB Radios, Cellphones and Gasoline Vapor Ignition', on Sun, 21 Mar 2004: The gap necessary to create an arc with 22 volts is: 22V / 20,000V/in = 0.001 inches Kinda small, but given a microscope, a 1 mil spark gap will arc. But it takes about 350 V to do so. The relationship between voltage and gap length is very non-linear below about 500 V. -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
#5
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John Woodgate wrote in message ...
I read in sci.electronics.design that Jeff Liebermann wrote (in mppp50ho4dr08ahkb3dlbqkcfkp0ih ) about 'CB Radios, Cellphones and Gasoline Vapor Ignition', on Sun, 21 Mar 2004: The gap necessary to create an arc with 22 volts is: 22V / 20,000V/in = 0.001 inches Kinda small, but given a microscope, a 1 mil spark gap will arc. But it takes about 350 V to do so. The relationship between voltage and gap length is very non-linear below about 500 V. In fact the Paschen curve - breakdown voltage plotted against gap - has a minimum at around a couple of hundred volts, and the breakdown voltage starts rising again for very small gaps. The linear right-hand branch of the graph where you might see a slope of 20,000V per inch doesn't extend down to 22V. The theory explaining the conductivity of electricity through gases was worked out around the turn of the last century, and doesn't seem to be all that well known any more. Pity. ------- Bill Sloman, Nijmegen |
#6
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On Sun, 21 Mar 2004 08:47:34 +0000, John Woodgate
wrote: I read in sci.electronics.design that Jeff Liebermann wrote (in mppp50ho4dr08ahkb3dlbqkcfkp0ih ) about 'CB Radios, Cellphones and Gasoline Vapor Ignition', on Sun, 21 Mar 2004: The gap necessary to create an arc with 22 volts is: 22V / 20,000V/in = 0.001 inches Kinda small, but given a microscope, a 1 mil spark gap will arc. But it takes about 350 V to do so. The relationship between voltage and gap length is very non-linear below about 500 V. I didn't know that it wasn't linear. I just assumed that it takes the same amount of energy to peel electrons off of a single atom (ionize) regardless of gap seperation. A wider gap requires more voltage to ionize more atoms to create a longer conduction path, but the energy per atom is the same. I also couldn't find (Google) any useful references that showed this non-linearity. Unless the heat generated by the ionization contributes to assisting furthur ionization, my seat-o-de-pants physics says it should be linear (for DC). There's also the minor detail of RF excitation versus DC. As I vaguely remember from my 35 years ago college welding classes, TIG welding uses RF to strike the arc because it takes less power/energy/whatever to start the arc. We're allegedly talking about striking an arc across 0.001" with a 5 watt, 27MHz transmitter terminated with a 50 ohm load. If it's non-linear in the opposite direction, the calcs are gonna be no fun. I have everything it takes to test this. Microscope slide, with two sewing pins glued with hotmelt goo and seperated by 0.001". Apply RF and watch through the microscope. I'll see if I can throw something together and post photos (time permitting). Also, I've always been tempted to build a low power, QRP spark gap transmitter. Although the mode is illegal, I suspect that operating spark at below Part 15 incidental emission standards, would be tolerated. Getting the arc to start at such low power levels might require some exotics (i.e. piezoelectrics). This could be the start of something interesting (or disgusting). -- Jeff Liebermann 150 Felker St #D Santa Cruz CA 95060 (831)421-6491 pgr (831)336-2558 home http://www.LearnByDestroying.com AE6KS |
#7
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I read in sci.electronics.design that Jeff Liebermann
wrote (in c1tr509eqipks7lt08ttt5cvnpkumu ) about 'CB Radios, Cellphones and Gasoline Vapor Ignition', on Sun, 21 Mar 2004: I didn't know that it wasn't linear. Google for Paschen's Law. For high voltages it is linear enough for calibrated spark gaps to be used as voltmeters in the past. The high- voltage terminals were open and accessible, giving a whole new meaning to the phrase 'Paschen killers'.(;-) -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
#8
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On Sun, 21 Mar 2004 23:00:47 +0000, John Woodgate
wrote: I read in sci.electronics.design that Jeff Liebermann wrote (in c1tr509eqipks7lt08ttt5cvnpkumu ) about 'CB Radios, Cellphones and Gasoline Vapor Ignition', on Sun, 21 Mar 2004: I didn't know that it wasn't linear. Google for Paschen's Law. For high voltages it is linear enough for calibrated spark gaps to be used as voltmeters in the past. The high- voltage terminals were open and accessible, giving a whole new meaning to the phrase 'Paschen killers'.(;-) Yep. That's it. Thanks. Haven't seen that since kollege. Also saw your comments on the topic in other usenet news articles. So much for my simplified view of ionization. Online spark gap calculator: http://www.cirris.com/testing/voltage/arc.html Minimum breakdown voltage in air at STP is about 350VDC. For RF, that would be: 350 * 0.707 = 192 Vrms Into a 50 ohm antenna at the coax connector, P = E^2 / R = 192 * 192 / 50 = 737 watts for any size spark gap. I don't know of any kilowatt cell phones around, but that's the power output needed to arc at the antenna connector. It might be somewhat lower due to the effects of RF vs DC. Also a suitably weird antenna could be fabricated to dramatically increase the voltage at some point. However, those coils are usually up in the air where they cannot get close to a ground suitable for forming a spark gap. -- Jeff Liebermann 150 Felker St #D Santa Cruz CA 95060 (831)421-6491 pgr (831)336-2558 home http://www.LearnByDestroying.com AE6KS |
#9
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In , Jeff Liebermann wrote:
On Sun, 21 Mar 2004 08:47:34 +0000, John Woodgate wrote: I read in sci.electronics.design that Jeff Liebermann wrote (in mppp50ho4dr08ahkb3dlbqkcfkp0ih ) about 'CB Radios, Cellphones and Gasoline Vapor Ignition', on Sun, 21 Mar 2004: The gap necessary to create an arc with 22 volts is: 22V / 20,000V/in = 0.001 inches Kinda small, but given a microscope, a 1 mil spark gap will arc. But it takes about 350 V to do so. The relationship between voltage and gap length is very non-linear below about 500 V. I didn't know that it wasn't linear. I just assumed that it takes the same amount of energy to peel electrons off of a single atom (ionize) regardless of gap seperation. It gets messy. You can see how messy it gets when you see what happens in the cathode area of a "glow discharge". A "glow discharge" is one of two common processes where positive ions of the gas/vapor are accelerated by the cathode-adjacent electric field into the cathode material, and where positive ions bombarding the cathode dislodge electrons from the cathode to maintain the supply of free electrons in the "discharge" (conductive path of glowing gas/vapor). (The other of the two common discharge mechanisms where cathode bombardment by positive ions dislodges electrons is the "cold cathode arc". There is still another cathode process for a discharge known as the "thermionic arc".) The glow discharge cathode process has 5 layers, 3 dim/dark and 2 bright. There is some sort of 'natural spacing' and 'natural thickness' of these layers, which varies with gas/vapor type and pressure and the cathode material. There is also a characteristic voltage drop of the cathode process known as the "cathode fall", and that is normally a few times or several times the ionization potential of the gas/vapor. There is such a thing as "normal glow", where the cathode process occurs at its natural current density (for the gas/vapor type and pressure and cathode material), and the first two dark layers and the two bright layers and some minimal portion of the third dark layer have a tendency to occupy some 'natural distance' (a function of gas/vapor type and pressure and cathode material) between cathode and anode. Then there is "abnormal glow", where the cathode process is forced into a smaller space between electrodes and/or is conducting a current density higher than 'natural' (for the gas/vapor type/pressure and cathode material) due to more current flowing than is "natural" for the available cross section of cathode process. When that happens, the "cathode fall" is even higher than that of "nowmal glow". There's also the minor detail of RF excitation versus DC. As I vaguely remember from my 35 years ago college welding classes, TIG welding uses RF to strike the arc because it takes less power/energy/whatever to start the arc. I don't know about that, but I have heard of RF glow discharges maybe having the cathode process eliminating one bright layer and one dark layer (for "electrodeless discharge" that occurs where insulation exists over the cathode for example), and that may reduce the cathode fall. We're allegedly talking about striking an arc across 0.001" with a 5 watt, 27MHz transmitter terminated with a 50 ohm load. If it's non-linear in the opposite direction, the calcs are gonna be no fun. ![]() I have everything it takes to test this. Microscope slide, with two sewing pins glued with hotmelt goo and seperated by 0.001". Apply RF and watch through the microscope. I'll see if I can throw something together and post photos (time permitting). Please do!!! - Don Klipstein ) |
#10
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Jeff Liebermann wrote in message . ..
On Sun, 21 Mar 2004 08:47:34 +0000, John Woodgate wrote: I read in sci.electronics.design that Jeff Liebermann wrote (in mppp50ho4dr08ahkb3dlbqkcfkp0ih ) about 'CB Radios, Cellphones and Gasoline Vapor Ignition', on Sun, 21 Mar 2004: The gap necessary to create an arc with 22 volts is: 22V / 20,000V/in = 0.001 inches Kinda small, but given a microscope, a 1 mil spark gap will arc. But it takes about 350 V to do so. The relationship between voltage and gap length is very non-linear below about 500 V. I didn't know that it wasn't linear. I just assumed that it takes the same amount of energy to peel electrons off of a single atom (ionize) regardless of gap seperation. A wider gap requires more voltage to ionize more atoms to create a longer conduction path, but the energy per atom is the same. I also couldn't find (Google) any useful references that showed this non-linearity. Unless the heat generated by the ionization contributes to assisting furthur ionization, my seat-o-de-pants physics says it should be linear (for DC). You need to read up on the physics involved. The critical point is that a free electron in the gas has to have a long enough mean free path to pick up enough energy by falling down the electric field to be able to ionise a molecule when it does hit one, generating one more electron in an inelastic collision. If it hits a molecule before it acquires enough energy, in an elastic collision, it will end up travelling in a different direction with the same energy, but with a good chance of losing the energy that it had accumulated. Think "drunkards walk". The minimum in the Paschen curve corresponds to the point where the mean free path is longer than the gap. There's also the minor detail of RF excitation versus DC. As I vaguely remember from my 35 years ago college welding classes, TIG welding uses RF to strike the arc because it takes less power/energy/whatever to start the arc. We're allegedly talking about striking an arc across 0.001" with a 5 watt, 27MHz transmitter terminated with a 50 ohm load. If it's non-linear in the opposite direction, the calcs are gonna be no fun. RF excitation works better than DC becasue it doesn't sweep the electrons out of the gap as they are created (by cosmic rays or local radioactivity) in the way that a DC field does. Like I said earlier, the physics was worked out about a hundred years ago, and the calculations shouldn't be too difficult now that we can use computers for the tedious bits. I have everything it takes to test this. Microscope slide, with two sewing pins glued with hotmelt goo and seperated by 0.001". Apply RF and watch through the microscope. I'll see if I can throw something together and post photos (time permitting). Everything except a sound undertanding of the theory. I've got a copy of a reprint of volume 2 of "Conduction of Electricity Through Gases" - Ionisation byCollision and the Gaseous Discharge - by J.J. Thompson and G.P. Thompson. My copy was published by Dover Press in 1969, and reprints the 1933 third edition. The first - singe volume - edition was published in 1903. I bought it when I was fiddling around building a starter for a xenon arc lamp, back in 1972. It proved quite useful. ------- Bill Sloman, Nijmegen |
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