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In the ARRL's Antenna Book 21st ed page 24-21, we see that if we
connect the two shields of the coax cables together, we obtain 'Shielded parallel Lines' . In that case, the resultant impedance is simply the sum of the characteristic impedances of each coax. So, there is quite a difference between the two independent coax I mentioned in my first message (we connect the shield to the inner conductor at each of its ends) (A) and the 'Shielded Parallel Lines' case (B). I am trying to understand why and it is the reason I posted my first message... In (A), the Z=276*log(2S/D) applies, so the Zo of each coax does not matter.. but in (B), Z=Zo1+Zo2, so the value of each Zo matters. Am I right? And how to compute matched line loss in case (A) and in case (B) ? |
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