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Where does it go? (mismatched power)
On Jun 11, 11:32*am, Richard Fry wrote:
On Jun 11, 6:16*am, Owen Duffy wrote: *... The transmitter output power is probably different ... Thank you, Owen. Do your comments apply to a transmitter designed/adjusted for, and expecting a 50 + j 0 ohm load? IOW, if the net output power of such a transmitter (which equals that dissipated in the load) probably is different with such a mismatch, do you expect the reason for that to be related to "reflected power?" RF NO! NO! NO! the difference is not due to 'reflected power'... any difference is due to the impedance change seen by the transmitter at its terminals. A VERY important method of analyzing sinusoidal steady state response of a system like a transmission line with a load on the end takes the load impedance and transforms it using the transmission line equations (with or without loss) back to the source terminals and then replacing it with an equivalent impedance. as long as the load is constant and linear this is a well known and easily proved substitution. you can then solve for conditions seen by the source ignoring the length of the line and load and using only a lumped impedance, therefore any reflected wave is irrelevant when analyzing the response of the source. |
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