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#1
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Richard,
A radio amateur, by an easy mistake, uses a 75-ohm plug and socket in a 50-ohm coaxial transmission system. The total length of the plug plus socket is 1" As a result of the mismatch what is the SWR produced on the 50-ohm line at 2 MHz. At 30 MHz? At 150 MHz? Is the amateur, or anyone else, likely to be aware of any difference in performance? No need to make measurements. If you are unable to make a simple calculation and answer the question then you are not qualified to continue the discussion. ---- Reg, G4FGQ |
#2
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"Reg Edwards" wrote
No need to make measurements. If you are unable to make a simple calculation and answer the question then you are not qualified to continue the discussion. __________________ How convenient. Why _would_ you want to make measurements, and prove yourself wrong? |
#3
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On Mon, 17 May 2004 15:02:19 -0500, "Richard Fry"
wrote: "Reg Edwards" wrote No need to make measurements. If you are unable to make a simple calculation and answer the question then you are not qualified to continue the discussion. __________________ How convenient. Why _would_ you want to make measurements, and prove yourself wrong? Ah Richard! Confrontation? Feeble at best when I doubt you could even get his recipe for RF Mud. ;-) Poor Reggie can quote Dead White Scientists like Lord Kelvinator with high dudgeon and still ignore the tenet of the plagiarized message. 73's Richard Clark, KB7QHC |
#4
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Reg,
You sent the 2nd post below within ten minutes of the 1st one below. Exactly WHAT is your position on this subject? - RF _______________________ "Reg Edwards" wrote first: No need to make measurements. If you are unable to make a simple calculation and answer the question then you are not qualified to continue the discussion. AND THEN, quoting Lord Kelvin: "When you can measure what you are speaking about and express it in numbers you know something about it. But when you cannot measure it, when you cannot express it in numbers, your knowledge is of a meagre and unsatisfactory kind. It may be the beginning of knowledge but you have scarcely in your thoughts advanced to the state of science." |
#5
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Reg Edwards wrote:
Richard, A radio amateur, by an easy mistake, uses a 75-ohm plug and socket in a 50-ohm coaxial transmission system. The total length of the plug plus socket is 1" As a result of the mismatch what is the SWR produced on the 50-ohm line at 2 MHz. At 30 MHz? At 150 MHz? Is the amateur, or anyone else, likely to be aware of any difference in performance? The practical answer for amateurs is somewhere between the two extreme positions that Richard and Reg are taking. Richard quotes a case where even very small impedance bumps do matter; but it's in full-quality TV broadcasting, not amateur radio. Reg, on the other hand, wants to dumb it down too far. There *are* cases in amateur radio where small impedance bumps are at least noticeable. At 2MHz or 30MHz, the effect is so small that no amateur would notice it. Even using professional test equipment, you'd be hard-pressed to measure the effect of a single connector of the wrong impedance. At 150(144)MHz, even a single connector is noticeable... but that's not the problem. The real problem is that if people believe a simple slogan like "connector impedances don't matter", they will probably go ahead and use *several* mismatched connectors, at various places along the line. Then they start to find bewildering problems at 144MHz and above, such as indicated SWR and power output values that vary according to the length of the coax jumpers that they use. It still may not matter in terms of the contacts they can make, but they are completely unable to understand what is happening - and that *does* matter! (What is happening, by the way, is that the lengths of the line sections between the mismatched connectors will determine how the small reflections from each one combine together. If you're lucky with the line lengths, they may tend to cancel; if you're not, they may tend to add... and usually it's somewhere in between.) No need to make measurements. In this particular case, that's true. When the impedance bump is small, it is easier and more accurate to calculate the effect than to measure it. -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) http://www.ifwtech.co.uk/g3sek |
#6
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Let's do what nobody has ever done before, not even in the ARRL handbooks or
in Terman, and get an idea of the magnitudes involved. Examine two cases over a range of frequencies. Case (1). In a 50-ohm system, use of a poor connector having an impedance deviating 10 percent from its nominal value of 50 ohms. Case (2). Making the mistake of using a 75-ohm connector in a 50-ohm system. In both cases the connector, plug and socket, is 1" (25.4mm) long. We first calculate the input impedance of a 75-ohm transmission line, 1" long, terminated with 50 ohms. Zin will not be very much different from 50 ohms. We then calculate the SWR on a 50-ohm line which is terminated by the afore-mentioned input impedance. RESULTS of calculation MHz SWR Case 1 SWR Case 2 ------ ----------------- ---------------- 2 1.0002 1.0009 30 1.0028 1.0146 150 1.014 1.073 300 1.029 1.145 1000 1.105 1.524 It is seen that results do not become significant to a radio amateur, and almost everybody else, until he has made the serious mistake of using the wrong impedance connector, and the frequency has risen to 1000 MHz for which he hasn't an SWR meter anyway. Below 300 MHz the results are submerged well beneath the uncertainty of an SWR meter. Now we can take a balanced view of the situation. ---- Reg, G4FGQ |
#7
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![]() "Reg Edwards" wrote in message ... Let's do what nobody has ever done before, not even in the ARRL handbooks or in Terman, and get an idea of the magnitudes involved. Examine two cases over a range of frequencies. Case (1). In a 50-ohm system, use of a poor connector having an impedance deviating 10 percent from its nominal value of 50 ohms. Case (2). Making the mistake of using a 75-ohm connector in a 50-ohm system. In both cases the connector, plug and socket, is 1" (25.4mm) long. We first calculate the input impedance of a 75-ohm transmission line, 1" long, terminated with 50 ohms. Zin will not be very much different from 50 ohms. We then calculate the SWR on a 50-ohm line which is terminated by the afore-mentioned input impedance. RESULTS of calculation MHz SWR Case 1 SWR Case 2 ------ ----------------- ---------------- 2 1.0002 1.0009 30 1.0028 1.0146 150 1.014 1.073 300 1.029 1.145 1000 1.105 1.524 It is seen that results do not become significant to a radio amateur, and almost everybody else, until he has made the serious mistake of using the wrong impedance connector, and the frequency has risen to 1000 MHz for which he hasn't an SWR meter anyway. Below 300 MHz the results are submerged well beneath the uncertainty of an SWR meter. Now we can take a balanced view of the situation. ---- Reg, G4FGQ Reg, I suspect your 1 inch length is overly pessimistic. Clearly, for an F connector, it is more like 1/2 inch. Lastly, if the load at the end is not 50.0, then any small deviation in the feedline could just as well improve things, as make it worse; this is probably not true for pulses or video. Think of an antenna tuner. It does nothing to the SWR on the main piece of line. Tam/WB2TT |
#8
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Reg,
Your math example does not illustrate the reality that the impedance change produced by a ~5/8" OD brass pin inserted radially into the dielectric space of coaxial transmission line can match that line into an adjacent termination of fairly high SWR (1.3:1 or so), at frequencies as low as 54MHz. As I wrote earlier, this technique is widely and successfully used to match the main transmission line of broadcast TV and FM stations to the net input impedance of their antenna (including its input elbows). - RF |
#9
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![]() Your math example does not illustrate the reality that the impedance change produced by a ~5/8" OD brass pin inserted radially into the dielectric space of coaxial transmission line can match that line into an adjacent termination of fairly high SWR (1.3:1 or so), at frequencies as low as 54MHz. ============================= It's not intended to. But I'm sure you are right. Try not to worry about it. |
#10
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I won't "worry about it," as long as you refrain from posting absolute
statements about this that are demonstrably untrue. - RF "Reg Edwards" wrote in message ... Your math example does not illustrate the reality that the impedance change produced by a ~5/8" OD brass pin inserted radially into the dielectric space of coaxial transmission line can match that line into an adjacent termination of fairly high SWR (1.3:1 or so), at frequencies as low as 54MHz. ============================= It's not intended to. But I'm sure you are right. Try not to worry about it. |
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