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#1
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In article , I wrote:
A word: synthetic aperture. Drone array, anyone? [...] Or just calculate directly. I think the angular resolution of an array or a telescope in radians is something like 0.22 * wavelength / aperture . Oops. That's 1.22 . Still, I don't think it's too bad considering how long ago I learned about synthetic aperture arrays in 2nd year physics. George |
#3
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On 7/13/2015 10:59 AM, Jeff Liebermann wrote:
On Mon, 13 Jul 2015 13:45:43 +0200, "bilou" wrote: "Jeff Liebermann" wrote in message ... Yep, antennas radiate photons. +1 There is not any proof that RF behaves differently than light. Things are already quite complicated without it :-) One of my not so great ideas was to devise a contraption that would let me "see" RF. It certainly would make troubleshooting RF devices much easier. Essentially, it would be a human eye analog implimented with RF components. According to theory, if it works for light, it should also work for RF. At the time, I was working at about 1GHz. Light is about 400 THz. So, all I need is an eyeball that's 400,000 times larger than the human eye. I'll give myself a -1 for the idea. I think they have that. They are called radio telescope arrays. -- Rick |
#4
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![]() "Jeff Liebermann" wrote in message ... One of my not so great ideas was to devise a contraption that would let me "see" RF. It certainly would make troubleshooting RF devices much easier. Essentially, it would be a human eye analog implimented with RF components. According to theory, if it works for light, it should also work for RF. At the time, I was working at about 1GHz. Light is about 400 THz. So, all I need is an eyeball that's 400,000 times larger than the human eye. I'll give myself a -1 for the idea. Hi As usual others had the same idea .Look here : https://youtu.be/DovunOxlY1k?t=81 |
#5
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On Fri, 21 Aug 2015 00:07:43 +0200, "bilou" wrote:
"Jeff Liebermann" wrote in message .. . One of my not so great ideas was to devise a contraption that would let me "see" RF. It certainly would make troubleshooting RF devices much easier. Essentially, it would be a human eye analog implimented with RF components. According to theory, if it works for light, it should also work for RF. At the time, I was working at about 1GHz. Light is about 400 THz. So, all I need is an eyeball that's 400,000 times larger than the human eye. I'll give myself a -1 for the idea. As usual others had the same idea .Look here : https://youtu.be/DovunOxlY1k?t=81 Nope. The AT&T wave demo is a mechanical analogy of wave phenomenon. That's not what I'm looking for. What I want is the ability to look at a radio, power amp, amplifier, etc and actually see the RF leaking from the circuit, or just standing there in the form of standing waves. Like light, I would not expect to see conducted RF, only radiated RF. However, I think there will be enough of both to make the effort worthwhile. Incidentally, if you're into surfing the waves, this should keep you entertained for days: http://www.falstad.com/mathphysics.html (Java required) (Note: Seems to work better when on controlled substances). -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#6
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On Mon, 13 Jul 2015 13:45:43 +0200, "bilou" wrote:
There is not any proof that RF behaves differently than light. Things are already quite complicated without it :-) Sure there is. After half a century of exposure to RF, my hair is falling out, my hand is shaking, and my bank account depleted. Other people, who were only exposed to light, have not had these things happen. I can only conclude that RF is somehow dangerous and different from light. -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#7
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On 7/14/15 4:13 PM, Jeff Liebermann wrote:
On Mon, 13 Jul 2015 13:45:43 +0200, "bilou" wrote: There is not any proof that RF behaves differently than light. Things are already quite complicated without it :-) Sure there is. After half a century of exposure to RF, my hair is falling out, my hand is shaking, and my bank account depleted. Other people, who were only exposed to light, have not had these things happen. I can only conclude that RF is somehow dangerous and different from light. That's gotta be it, by the infallible principle of Post Hoc Ergo Propter Hoc. |
#8
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On Fri, 17 Jul 2015 12:45:52 -0700, Eric Weaver
wrote: On 7/14/15 4:13 PM, Jeff Liebermann wrote: On Mon, 13 Jul 2015 13:45:43 +0200, "bilou" wrote: There is not any proof that RF behaves differently than light. Things are already quite complicated without it :-) Sure there is. After half a century of exposure to RF, my hair is falling out, my hand is shaking, and my bank account depleted. Other people, who were only exposed to light, have not had these things happen. I can only conclude that RF is somehow dangerous and different from light. That's gotta be it, by the infallible principle of Post Hoc Ergo Propter Hoc. Attributing my premature demise to the effects of RF exposure is nothing new. It's done all the time by those that believe that correlation is sufficient evidence to assign causation: http://www.tylervigen.com/spurious-correlations http://tylervigen.com/discover It's a form of inductive logic. That's where one makes a series of observations, and then contrives a generalized conclusion based upon the available observations. For example, I've noticed that most of the hams in the local radio club are officially senior citizens. Therefore ham radio causes accelerated aging. It's all very logical. The only problem is that inductive logic never really provides a proof as there are always alternative explanations. Fortunately, we have an easy test to identify fallacious correlations called Occam's Razor, where the simplest explanation is usually the correct explanation. In my case, RF exposure is a far more complexicated explanation than simple aging. However, I discarded that explanation due to lack of entertainment value. I also find it easier to offer an intentionally complex theory that is easily refuted, so that the simpler theory will be more readily accepted without contest. Had I initially offered the simple theory, it would surely have been met by opposition. I hope this helps. -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#9
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"Wayne" wrote in message
... "The antenna, like the eye, is a transformation device converting electromagnetic photons into circuit currents; but, unlike the eye, the antenna can also convert energy from a circuit into photons radiated into space. In simplest terms an antenna converts photons to currents or vice versa." Antennas, Second Edition, 1988, by John D. Kraus. Page 19. IMHO, antennae do not radiate photons. and the misunderstanding arises from the photons that are generated from electrons shifting to lower energy orbits around atoms. In tha case of currents within antennae, the energy is the potential energy brought about by compressing electrons against each other, against their inherent mutual repulsion, and is a different mechanism than that which generates photons. |
#10
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gareth wrote:
"Wayne" wrote in message ... "The antenna, like the eye, is a transformation device converting electromagnetic photons into circuit currents; but, unlike the eye, the antenna can also convert energy from a circuit into photons radiated into space. In simplest terms an antenna converts photons to currents or vice versa." Antennas, Second Edition, 1988, by John D. Kraus. Page 19. IMHO, antennae do not radiate photons. and the misunderstanding arises from the photons that are generated from electrons shifting to lower energy orbits around atoms. In tha case of currents within antennae, the energy is the potential energy brought about by compressing electrons against each other, against their inherent mutual repulsion, and is a different mechanism than that which generates photons. You come a little late to this discussion. Perhaps you would like to explain, on the basis of your theory that there are two kinds of electromagnetic radiation based on the means of their generation, how you tell which kind of em radiation you are observing, the one which also exists as photons or the one that doesn't? Preferably show the answer mathematically. -- Roger Hayter |
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