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![]() "Jerry Stuckle" wrote in message ... On 9/27/2015 9:46 PM, Wayne wrote: "John S" wrote in message ... On 9/27/2015 1:20 PM, Wayne wrote: "rickman" wrote in message ... On 9/27/2015 10:41 AM, kg7fu wrote: Matching the antenna won't make the Return Loss go away but it will make the transmitter happy. Can you explain this? I thought matching the antenna would *exactly* make the return loss go away because it would eliminate the mismatch. Not wanting to put words in his mouth.... I read that to mean that the high SWR between the ATU and the antenna would remain, but the transmitter would be happy with the SWR on the transmitter/ATU coax. # Rick is correct. If the antenna (load) is matched to the line, there is # no return loss, hence no SWR. The ATU will be adjusted (hopefully) to # make the transmitter operate properly with the impedance as seen at the # transmitter end of the line. # Yes, the SWR due to mismatch of the antenna (load) and line will remain. # Even if the real part of your load impedance is matched to the line, you # will still have a high SWR if the reactance remains. # Does this make sense? Yes. That's what I was trying to say using SWR instead of return loss. Return loss numbers get bigger with lower SWR. For example: SWR 1:1 = infinite return loss. # Incorrect. Return loss increases with an increased SWR. An SWR of 1:1 # has no return loss because there is no returned signal to lose. 100% of # the signal is radiated. Return loss is the difference in dB between the forward power and reflected power. Less reflected makes a bigger difference and the return loss goes up. I did a very quick Google and came up with this page that will calculate SWR, return loss, and reflection coefficient. Give it a try with SWR of 3, 2, and 1. http://cgi.www.telestrian.co.uk/cgi-....co.uk/vswr.pl |
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