October's QST has an article "Designing a Shortened Antenna" pp 28-32. It
gives an example of a shortened dipole for 40 meters at 7007 khz. Dipole
length of the half-sized dipole [p30 "a second example"] is 10.61 meters.
This is 20 feet off ground using #12 wire. The formulas give a solution of
XL= +j1776 ohms or an inductance of 40 microhenries at 30 degrees from each
leg.


I tried to simulate this antenna on EZNEC. A 10.61 meter antenna at 7007 khz
gives impedance =11.33 - j 881.2 ohms.

If EZNEC is correct wouldn t I need an inductance of +j881.2 on each leg of
the dipole, rather than +j1776?

--
Jerry