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Roy Lewallen wrote:
We are not going to get anywhere until you admit there is 68 joules/sec in the feedline that haven't yet made it to the load. Once you admit that fact, everything else will be moot. Let's try again. The source is providing 40 watts, 32 watts of which is delivered to the transmission line. The transmission line is transferring this 32 watts of power to the load. In the transmission line, we can calculate that there's 50 watts of "forward power", and 18 watts of "reverse power". And it is easy to prove that the source has generated 50+18=68 watts that have not been delivered to the load. So I ask you: Where are those 68 joules/sec located during steady-state if not in the forward and reflected power waves? Why will 68 joules/sec be dissipated in the system *after* the source power is turned off? If those 68 joules/sec that have been generated by the source but not delivered to the load are not in the forward and reflected power waves, exactly where are they located? There's really no sense in continuing this discussion until you answer that question. Everything else is just a side argument. The answer to that question will expose the errors in your premises. You are apparently assuming there is not enough energy in the system during steady-state to support the forward and reflected power waves. But that exact amount of energy was supplied during the power-on transient state and will be dissipated during the power-off transient state. If it's not in the forward and reflected power waves, you are going to have to store it somewhere else. Where is that somewhere else? The source has supplied 68 joules/sec that has not reached the load. The forward and reflected power waves require 68 joules/sec. That you don't see the logical connection between those two equal energy values is amazing. But I will get you started on an understanding of the component powers using an S-parameter analysis. How much of that 18 watts of reverse power is going through the source resistor to reach the source to "engage in destructive interference"? reference the S-parameter equation: b1 = s11*a1 + s12*a2 I calculate 11.52 watts. (s12*a2)^2 = 11.52 watts The other 6.48 watts are in (s22*a2)^2 where |a2|^2 = 18 watts What does it interfere with? From the S-parameter equation above, it obviously interferes with s11*a1 . Please reference HP App Note 95-1, available on the web. It should answer most of your questions, in particular pages 16 & 17. |a1|^2 = Power incident on the input of the network |a2|^2 = Power incident on the output of the network |b1|^2 = Power reflected from the input port of the network |b2|^2 = Power reflected from the output port of the network -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
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