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#11
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redhat wrote:
i have made a modification to it, it is now 1/4 wavelength monopole. the simulation output is : source voltage= 3092 at -89.79 deg. and impedance= 11.08-j3092 ohm . what is the meaning of this source voltage? i have placed a source with amplitude 1v at 0% from E1 because it is a monopole, the ground type is free space. Sounds like the source is one amp, not one volt. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#12
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On 12 Jun 2005 06:01:21 -0700, "redhat" wrote:
i have made a modification to it, it is now 1/4 wavelength monopole. the simulation output is : source voltage= 3092 at -89.79 deg. and impedance= 11.08-j3092 ohm . what is the meaning of this source voltage? i have placed a source with amplitude 1v at 0% from E1 because it is a monopole, the ground type is free space. Something must be wrong with your model. A resonate 1/4-wave monopole should have the resistance component around 20-ohms or so. Additionally, it would appear by the high reactive component you give that you do not have a ground plane included in you model. A 1/4-wave monopole requires something to work against. Danny, K6MHE |
#13
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Do you have your ground planes separated from the radiator in the model?
Do you have the source placed at the bottom end of the radiator? Perhaps one more versed in EZNEC would take a look if you would post/offer the antenna file you have created here... John "redhat" wrote in message ups.com... i have made a modification to it, it is now 1/4 wavelength monopole. the simulation output is : source voltage= 3092 at -89.79 deg. and impedance= 11.08-j3092 ohm . what is the meaning of this source voltage? i have placed a source with amplitude 1v at 0% from E1 because it is a monopole, the ground type is free space. |
#14
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the ground was set to "free space" and when i selected "perfect" ground
an error occured "one or more wires extended into or lying on the ground", the problem was that in the wire coordinates z was set to 0 ,when i selected a different z the problem was solved but the voltage is still high, the antenna will be placed 90 deg. to the ground plane so what should be z value? the source is placed 0% from E1 (monopole).note: i can't upload the file rightnow |
#15
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redhat:
I don't want Roy jumping me about giving advice on his application... However, you need to give the starting height of your elements some distance above ground... actually, you would be wise to really make this a "real" value, like the actual height the antenna will be... .... for example, say you have an eight foot long vertical radiator at ten feet above ground--then one x,y value will be 10.0 and the ending x,y value will be 18.0... I hope that is clear enough, Roy Lewellan would best be consulted on EZNEC's exact workings... John "redhat" wrote in message oups.com... the ground was set to "free space" and when i selected "perfect" ground an error occured "one or more wires extended into or lying on the ground", the problem was that in the wire coordinates z was set to 0 ,when i selected a different z the problem was solved but the voltage is still high, the antenna will be placed 90 deg. to the ground plane so what should be z value? the source is placed 0% from E1 (monopole).note: i can't upload the file rightnow |
#16
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the ground was set to "free space" and when i selected "perfect" ground
an error occured "one or more wires extended into or lying on the ground", the problem was that in the wire coordinates z was set to 0 ,when i selected a different z the problem was solved but the voltage is still high, the antenna will be placed 90 deg. to the ground plane so what should be z value?should it be the same length of the antenna? the source is placed 0% from E1 (monopole). the pattern of the antenna shows a gain of 1.5dbi ,if i have a circuit that outputs 2db for example then the output from the antenna should be 3.5db, right? or because dbi is referenced to isotropic source there is a conversion? note: i can't upload the file rightnow |
#17
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On 12 Jun 2005 15:58:04 -0700, "redhat" wrote:
an error occured Hi OM, As I pointed out some time ago, your work is very far off track. It would be far simpler to start with a working design and change it slightly to observe how your input effects the results. Simply hit the Open button and select: VERT1.EZ and look at ALL the characteristics. This may mean starting a notebook (standard Engineering discipline) and logging those values. Make a change (like shorten or lengthen the ONLY wire) and look at ALL the characteristics. Log those values and compare to the first. Keep doing this and eventualy you will find that the velocity factor of the wire is not very significant - or better yet, discover what significance it has (it will eventually become significant, but not practically so) and report your results here. 73's Richard Clark, KB7QHC |
#18
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Richard:
That was uncommonly decent of you, it is good to see one man giving another a "hand up." Also, it is excellent advice I failed to even think of telling him... Warmest regards, John "Richard Clark" wrote in message ... On 12 Jun 2005 15:58:04 -0700, "redhat" wrote: an error occured Hi OM, As I pointed out some time ago, your work is very far off track. It would be far simpler to start with a working design and change it slightly to observe how your input effects the results. Simply hit the Open button and select: VERT1.EZ and look at ALL the characteristics. This may mean starting a notebook (standard Engineering discipline) and logging those values. Make a change (like shorten or lengthen the ONLY wire) and look at ALL the characteristics. Log those values and compare to the first. Keep doing this and eventualy you will find that the velocity factor of the wire is not very significant - or better yet, discover what significance it has (it will eventually become significant, but not practically so) and report your results here. 73's Richard Clark, KB7QHC |
#19
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in designing a monopole should i use the velocity factor of the wire
in the equation or not? No...It's silly...Do you check the VF of wire when you build a dipole? It's overkill worrying....The VF of straight wire is in the 95+ range...Not enough to worry about... and if i want its impedance to be 50ohm should i use a matching network or is there another way? There is no other way. If you want to build a 1/8 wave vertical, build it the same way you would build a mobile vertical. If not top loaded with a hat, you should use a loading coil at 1/2 to 3/4 up the vertical for best efficiency. You would use a matching device of the same type used for most mobiles. If you want to tinker with vertical design, I'd try something like Reg's "vertload" to design the antenna. It will tell the appx efficiency of the design, and also give you the values needed for a matching device, which can be a simple coil or cap depending how you set it up. Then, after that is done, you can try modeling it. Short vertical design is quite mature...You are not going to be able to reinvent the wheel... MK |
#20
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On 12 Jun 2005 15:37:32 -0700, "redhat" wrote:
the ground was set to "free space" and when i selected "perfect" ground an error occured "one or more wires extended into or lying on the ground", the problem was that in the wire coordinates z was set to 0 ,when i selected a different z the problem was solved but the voltage is still high, the antenna will be placed 90 deg. to the ground plane so what should be z value? the source is placed 0% from E1 (monopole).note: i can't upload the file rightnow Why don't you move the source to the bottom (ground) end of the monopole? I'm guessing that E1 is the top of the vertical. Use "View Antenna" to see for sure. You can use Z=0 if you use MiniNEC ground. |
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