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#1
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From page 22.2 of the 2005 ARRL Handbook
"CONDUCTOR SIZE" "The impedance of the antenna also depends on the diameter of the conductor in relation to the wavelength. If the diameter of the conductor is increased, the capacitance per unit length increases and the inductance per unit length decreases. Since the radiation resistance is affected relatively little, the decreased L/C ratio causes the Q of the antenna to decrease so that the resonance curve becomes less sharp with change in frequency. This effect is greater as the diameter is increased, and is a property of some importance at the very high frequencies where the wavelength is small." Lots of interesting graphs and charts in the ARRL Antenna Handbook as well. Roger |
#2
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![]() wrote in message ups.com... From page 22.2 of the 2005 ARRL Handbook "CONDUCTOR SIZE" "The impedance of the antenna also depends on the diameter of the conductor in relation to the wavelength. If the diameter of the conductor is increased, the capacitance per unit length increases and the inductance per unit length decreases. Since the radiation resistance is affected relatively little, the decreased L/C ratio causes the Q of the antenna to decrease so that the resonance curve becomes less sharp with change in frequency. This effect is greater as the diameter is increased, and is a property of some importance at the very high frequencies where the wavelength is small." Lots of interesting graphs and charts in the ARRL Antenna Handbook as well. ====================================== A nice summary. But to be more precise, it is the ratio of conductor diameter over length which matters. Inductance and capacitance change very slowly with diameter/length. The changes are hardly noticeable. L = 0.2 * Length * ( Ln( 4 * Length / Dia ) -1 ) microhenrys. C = 55.55 * Length / ( Ln( 4 * Length / Dia ) -1 ) picofarads. Zo = Sqrt( L / C ) = 60 * Ln( 4 * Length / Dia ) -1 ) ohms. Antenna Q = 2 * Pi * Freq * L / (Distributed Radiation Resistance). For a half-wave dipole the distributed radiation resistance is 146 ohms, or twice the feedpoint resistance. ---- Reg. |
#3
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Reg Edwards wrote:
wrote in message ups.com... From page 22.2 of the 2005 ARRL Handbook "CONDUCTOR SIZE" "The impedance of the antenna also depends on the diameter of the conductor in relation to the wavelength. If the diameter of the conductor is increased, the capacitance per unit length increases and the inductance per unit length decreases. Since the radiation resistance is affected relatively little, the decreased L/C ratio causes the Q of the antenna to decrease so that the resonance curve becomes less sharp with change in frequency. This effect is greater as the diameter is increased, and is a property of some importance at the very high frequencies where the wavelength is small." Lots of interesting graphs and charts in the ARRL Antenna Handbook as well. ====================================== A nice summary. But to be more precise, it is the ratio of conductor diameter over length which matters. Inductance and capacitance change very slowly with diameter/length. The changes are hardly noticeable. L = 0.2 * Length * ( Ln( 4 * Length / Dia ) -1 ) microhenrys. C = 55.55 * Length / ( Ln( 4 * Length / Dia ) -1 ) picofarads. So, if Length / Dia equals e / 4 (about 2.7183), then C = infinite? Zo = Sqrt( L / C ) = 60 * Ln( 4 * Length / Dia ) -1 ) ohms. Antenna Q = 2 * Pi * Freq * L / (Distributed Radiation Resistance). For a half-wave dipole the distributed radiation resistance is 146 ohms, or twice the feedpoint resistance. ---- Reg. John |
#4
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John - KD5YI wrote:
Reg Edwards wrote: wrote in message ups.com... From page 22.2 of the 2005 ARRL Handbook "CONDUCTOR SIZE" "The impedance of the antenna also depends on the diameter of the conductor in relation to the wavelength. If the diameter of the conductor is increased, the capacitance per unit length increases and the inductance per unit length decreases. Since the radiation resistance is affected relatively little, the decreased L/C ratio causes the Q of the antenna to decrease so that the resonance curve becomes less sharp with change in frequency. This effect is greater as the diameter is increased, and is a property of some importance at the very high frequencies where the wavelength is small." Lots of interesting graphs and charts in the ARRL Antenna Handbook as well. ====================================== A nice summary. But to be more precise, it is the ratio of conductor diameter over length which matters. Inductance and capacitance change very slowly with diameter/length. The changes are hardly noticeable. L = 0.2 * Length * ( Ln( 4 * Length / Dia ) -1 ) microhenrys. C = 55.55 * Length / ( Ln( 4 * Length / Dia ) -1 ) picofarads. So, if Length / Dia equals e / 4 (about .67957), then C = infinite? Zo = Sqrt( L / C ) = 60 * Ln( 4 * Length / Dia ) -1 ) ohms. Antenna Q = 2 * Pi * Freq * L / (Distributed Radiation Resistance). For a half-wave dipole the distributed radiation resistance is 146 ohms, or twice the feedpoint resistance. ---- Reg. John |
#5
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So, if Length / Dia equals e / 4 (about .67957), then C = infinite?
==================================== C even goes negative for smaller values of Length/Dia. I'll let you into a secret - the formulae are approximate and don't apply when antenna length is less than about 5 times its diameter. When was the last time you saw an antenna wire only 5 times longer than its diameter? |
#6
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Reg Edwards wrote:
So, if Length / Dia equals e / 4 (about .67957), then C = infinite? ==================================== C even goes negative for smaller values of Length/Dia. I'll let you into a secret - the formulae are approximate and don't apply when antenna length is less than about 5 times its diameter. When was the last time you saw an antenna wire only 5 times longer than its diameter? You should supply your "secrets" along with your formulae. |
#7
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You should supply your "secrets" along with your formulae.
===================================== At my time of life I don't have time to write a book! You'll just have to read between the lines. ;o) ---- Reg. |
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