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#1
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afcsman wrote:
spamhog wrote: Dull, black, heat resistant paints have been used to help cool engines for ages. It is not done to cool the engine, it is done to make the engine look cool. It would be cool (literally) if one could spray and heat-cure unshielded tubes and improve their heat-shedding Is there any indication that such paints, or some vacuum-tube specific types, would help keeping tubes cool by improving heat radiation? I'd love some factual info, if it exists, or educated guesses, rather than uninformed blind guesses, as I am awfully good at doing uninformed blind guesses already! :-) One might think that the metal shields would "catch" the radiated heat after it has left the tube. I feel that the black paint would act as a heat insulator, preventing efficient transfer of the filament heat to the outside. Empirical evidence that most everyone has witnessed, shows that black objects absorb light from the sun, and get hot. So, that is exactly what you should expect to happen with painting a tube's envelope black. The paint will absorb the radiant heat from the plate, and conduct it to the glass envelope. The glass envelope will then get much hotter than it would have if the radiant heat had been allowed to escape through the glass and radiate out into space. The black EMC tube shields cool the tube envelope by conducting the glass's heat to the metal shield. This is done not to make an unshielded tube cooler, but rather to make a tube that must be shielded less hot than it would be in a conventional shield that lacks the heat conducting structure. Unless you can put a thermocouple in the tube, it will be hard to know how hot it gets Inside. It is a hard vacuum, vacuum doesn't get hot or cold. You could measure the temperature of some of the tube's elements, but why would you care if they get hot? As long as they don't get hotter then the yellow heat they were heated to when they were evacuated, there is nothing to be concerned about. (Yes, it can be done, despite the "how to build a triode" nonsense. Tubes were fabricated and evacuated with mercury pumps by amateurs in the 19 'teens and 20's). True, but I would bet that you can't do it! Building a triode requires a wide variety of knowledge and capabilities. The French guy that did it in one of the videos built every piece of equipment that he used in making the triodes, and successfully built a nice little hard sealed glass triode too. It was impressive, whether or not it impressed you. And will it make any difference? Most equipment was designed to operate over a rather wide range of ambient temperature. Heat dispersion might be important with power tubes (rectifiers, audio/rf amplifiers), but most of that is due to the power inefficiencies of operating the tube,(see the red or white-hot plates!), not from mere filament heat. In that case fans or liquid cooling would be a better alternative. Try painting a 3-500 tube black and fire it up! It would melt the pyrex glass envelope, particularly around the already highly stressed filament pins. -Chuck |
#2
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All this is very interesting.... There's a bunch of things I find
confusing. 1) Radiation vs conduction On one hand it's obvious that a layer of dull, IR-black paint has a thermal insulation effect. But the same may be said of ANYTHING surrounding a tube. Even one of the "good" IERC shields must have an insulating effect of sorts. Moreover, the copper "fingers" are metal- shiny, obviously designed to sink heat by conduction, not by absorbing radiation. 2) Terminal filament temperature The issue here isn't avoiding failures as much as increasing tube life. The heat issue in low power devices was much disregarded till close to the end of the tube era, due to engineering, commercial, and I believe psychological effects. In the end, microtubes used in the NORAD systems reached 500k h MTBF, and even before that, repeater amps in transatlantic underwater phone cables had already made major advances in reliability. There is a DoD or Collins study on the matter, claiming that IERC shields improved MTBF over unshielded tubes, if I remember correctly. As in all stable thermal systems, once equilibrium is reached the terminal temperature of cathode and filament can't be independent of what happens at the tube surface. I know how to scrounge up a Wiener bridge or a shunt and measure small deltas in heater current - but where do I look up some ideas on how current is related to temperature, whence what deltas to expect, at least in order of magnitude? Without a theory, even a rough one, as Popper pointed out, there's not much to test.... :-( 3) Cooling effect of going black-body in the IR range Granted, if 90% of the exchange surface eg in an aircooled engine faces . . . itself (think deep cooling fins facing each other) most cooling must come from conduction to a moving ambient medium (aka air). So blackening should not make much difference there. But what about situation where there IS open space around a hot device? Right now, I remember that I know a guy who makes heating systems, including a successful line of radiation heaters: http://www.sabiana.it/download_pubblici/catgen_en.pdf, see the 1st product, called Duck-Strip. The name's an inside joke: they were designed by a Mr. Anatrella - Italian for "cute duckling". The things run on hot water. At a Volkswagen plant those radiators heat people from a vertical distance of over 20m. From an economic standpoint I am not sure it's totally in the company interest to maximize per- surface-unit radiation, but I believe they took a look at paints. They also used to have a gas-fired radiation heater running at a much higher temperature than the water type. I'll ask him... stay tuned. Moreover, some things I found by googling words that came up in this thread: overclocking & paints (uh...) http://www.overclockers.com/tips684/ irrelevant but funny http://members.optusnet.com.au/mcdjim/100_4062s.jpg http://forums.bit-tech.net/showthrea...2a61& t=53048 read what Dampney writes on improving IR absorbtion with "visible and IR" black paint http://thurmalox.com/Upload/Products/Products28.pdf teacher's guide to experiment :-) http://www.ed.psu.edu/ci/Papers/STS/gac-3/in05.htm (no word on measuring temperatures in unreachable recesses) |
#3
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![]() On Sat, 19 Jan 2008, spamhog wrote: All this is very interesting.... There's a bunch of things I find confusing. 1) Radiation vs conduction On one hand it's obvious that a layer of dull, IR-black paint has a thermal insulation effect. But at very thin layers, it is negligible. Look at house insulation. R-30 is 1-1/2 feet thick plus. A single pane window (single strength) is more like R-1. Glass is a great insulator (compared to, say, copper) but at 1/8 inch thickness its almost not there. Vacuum tube glass is even thinner. But the same may be said of ANYTHING surrounding a tube. Even one of the "good" IERC shields must have an insulating effect of sorts. Moreover, the copper "fingers" are metal- shiny, obviously designed to sink heat by conduction, not by absorbing radiation. You have to compare conduction, convection, and all the mechanisms. 2) Terminal filament temperature The issue here isn't avoiding failures as much as increasing tube life. The heat issue in low power devices was much disregarded till close to the end of the tube era, due to engineering, commercial, and I believe psychological effects. In the end, microtubes used in the NORAD systems reached 500k h MTBF, and even before that, repeater amps in transatlantic underwater phone cables had already made major advances in reliability. There is a DoD or Collins study on the matter, claiming that IERC shields improved MTBF over unshielded tubes, if I remember correctly. As in all stable thermal systems, once equilibrium is reached the terminal temperature of cathode and filament can't be independent of what happens at the tube surface. I know how to scrounge up a Wiener bridge or a shunt and measure small deltas in heater current - but where do I look up some ideas on how current is related to temperature, whence what deltas to expect, at least in order of magnitude? Without a theory, even a rough one, as Popper pointed out, there's not much to test.... :-( There may be some small effects, and it might be more tied to how many times a tube is warmed up from cold, cooled off to cold than actual temperature (in many applications, folks would turn them on and leave everything running [eg. computer monitors, even today]). 3) Cooling effect of going black-body in the IR range Granted, if 90% of the exchange surface eg in an aircooled engine faces . . . itself (think deep cooling fins facing each other) most cooling must come from conduction to a moving ambient medium (aka air). So blackening should not make much difference there. But what about situation where there IS open space around a hot device? That black-body radiation works in both directions, not just absorption. And, it may also be spectrum-dependent so that would have to be measured with instruments, not our (human) eyes. Right now, I remember that I know a guy who makes heating systems, including a successful line of radiation heaters: http://www.sabiana.it/download_pubblici/catgen_en.pdf, see the 1st product, called Duck-Strip. The name's an inside joke: they were designed by a Mr. Anatrella - Italian for "cute duckling". The things run on hot water. At a Volkswagen plant those radiators heat people from a vertical distance of over 20m. From an economic standpoint I am not sure it's totally in the company interest to maximize per- surface-unit radiation, but I believe they took a look at paints. They also used to have a gas-fired radiation heater running at a much higher temperature than the water type. I'll ask him... stay tuned. Moreover, some things I found by googling words that came up in this thread: Its good that you did some google searching, but on the whole I think you are worrying too much about cooling. And, if you do manage to cool the cathode, then emmission would surely suffer. As the ultimate wacky suggestion, you could immerse the tubes in liquid air/nitrogen and really keep them cool (cost a lot of money), but then I'll bet you couldn't "light up the tubes" (with filament voltage) at all. ===== no change to below, included for reference and context ===== overclocking & paints (uh...) http://www.overclockers.com/tips684/ irrelevant but funny http://members.optusnet.com.au/mcdjim/100_4062s.jpg http://forums.bit-tech.net/showthrea...2a61& t=53048 read what Dampney writes on improving IR absorbtion with "visible and IR" black paint http://thurmalox.com/Upload/Products/Products28.pdf teacher's guide to experiment :-) http://www.ed.psu.edu/ci/Papers/STS/gac-3/in05.htm (no word on measuring temperatures in unreachable recesses) |
#4
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![]() On Thu, 17 Jan 2008, spamhog wrote: Dull, black, heat resistant paints have been used to help cool engines for ages. It would be cool (literally) if one could spray and heat-cure unshielded tubes and improve their heat-shedding Is there any indication that such paints, or some vacuum-tube specific types, would help keeping tubes cool by improving heat radiation? I'd love some factual info, if it exists, or educated guesses, rather than uninformed blind guesses, as I am awfully good at doing uninformed blind guesses already! :-) I'm not sure that a layer of black paint (as in exploiting what physicists call "black body radiation" [or rate of heat transfer is proportional to wavelenght raised to a power greater than one, and I don't remember the power]) of is going to help you very much. Yes, mirrors, white surface, black surface reflect, respectively, high, medium, or low amounts of impinging radiation but at some point down the time scale, it will all come to equilibrium anyway. Several additional thoughts: 1. The layer of paint probably won't act as much of an insulator (silicon grease, an insulator at high thicknesses, is used in thin layers between computer CPUs and heatsinks and nobody gets worries about this). 2. A question about heat dissipation would have to involve knowing that most heat is dissipated (from the plate) as infra red (unless the tube plate is warm enough to start glowing red). Black paint would have to be examined in terms of its spectral absorbtion as a function of visible-IR wavelengths and compared with how well glass (which, IIRC, passes IR but not UV) passes a given quantity of heat at the same operating temperature. The passband and transmission spectrum may also be dependent on any doping (dyes with bandpass absorptions, etc) but I certainly recall no writings about this in terms of tube cooling. 3. Some tube sheilds were shiny, some were blackened. Good question as to whether the difference helped or hurt temperature, but some tube sheilds were advertised as helping with heat transfer (had some kind of slots). However, all of the metal enveloped tubes had a dull black surface and there may have been a minor component of contribution to surface cooling through black body radiation, or it was simply the cheapest surface to make. 4. Personally, an opaque tube envelope means I can't tell by looking at the tube if the filaments are lighting up when I turn on the power. Its not clear to me that you need to worry much about running tubes at a lower bulb temperature since glass (and even the metal covered glass tubes) won't melt until you get a way much quite a bit hotter than they usually run. If you are worried about heat causing a variety of accellerations of temperature-based aging processes in other components (transformers, capacitors, etc), then put a small fan somewhere to draw out the heat or blow in cooler air. If you are thinking about pushing tubes beyond spec limits, then I'd suggest just not doing that (or, to get more power, or whatever, put more tubes in parallel or use bigger tubes, but that did not seem to be part of yor goal). |
#5
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On Thu, 17 Jan 2008 04:27:06 -0800, spamhog wrote:
Dull, black, heat resistant paints have been used to help cool engines for ages. It would be cool (literally) if one could spray and heat-cure unshielded tubes and improve their heat-shedding Is there any indication that such paints, or some vacuum-tube specific types, would help keeping tubes cool by improving heat radiation? I'd love some factual info, if it exists, or educated guesses, rather than uninformed blind guesses, as I am awfully good at doing uninformed blind guesses already! :-) What I know is that the glass will pass a proportion of the IR energy being generated by the outside surfaces of the plate. Depending on just how great a percentage, you may get more heating of the glass from the paint capturing the radiation from inside than you get cooling from the paint re-radiating it to the outside. What I don't know is what will actually be the case. -- Tim Wescott Control systems and communications consulting http://www.wescottdesign.com Need to learn how to apply control theory in your embedded system? "Applied Control Theory for Embedded Systems" by Tim Wescott Elsevier/Newnes, http://www.wescottdesign.com/actfes/actfes.html |
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