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#81
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Learn How VoiceMax Increases Your Transmission Range...
On Wed, 11 Jul 2007 13:24:07 -0700, Telstar Electronics
wrote in om: Brian, I have just been to your site and, according to that... In over 5 years of business, only three products appear to have been created... two of which have been discontinued (already). Between discontinuing previous products, and offering this latest, there appears to have been no products for sale - no income, no business. A business with just one $60 product (when it becomes available), two discontinued items, and large gaps in trading. You may not be using kits, but just what do you think your Web site and it's figures say about you and your business? Right or wrong, he is saying what people see when they view your site... and what will they think if they ever see these newsgroup threads. They'll know that I have a very small company. I don't see a thing wrong with that. If they don't like that... nothing I can do about it. Items are often discontinued by a manufacturer when their profit margin becomes unacceptable in the marketplace. Why should I continue to offer a product that I can't make a reasonable profit on? Do you run a business? I do. And part of running a business is catering to the market. Trying to manipulate the market to suit the product (pet rocks, white salmon) might net you a few bucks at the beginning, but the market eventually wises up. Looking at your business history, it appears the market was smarter than you from the beginning, Brian. "LOL" |
#82
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Learn How VoiceMax Increases Your Transmission Range...
On Jul 11, 5:24 pm, Frank Gilliland
wrote: I do. And part of running a business is catering to the market. Trying to manipulate the market to suit the product (pet rocks, white salmon) might net you a few bucks at the beginning, but the market eventually wises up. Looking at your business history, it appears the market was smarter than you from the beginning, Brian. Frank, you sure know a lot about running a business... and you never even had one... lol The real issue as I see it is... does anyone really care about what you have to say? I sure don't. I hope others do... or you're wasting a lot of time here. |
#83
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Learn How VoiceMax Increases Your Transmission Range...
On Wed, 11 Jul 2007 16:21:32 -0700, Telspam Electronics
wrote in .com: On Jul 11, 5:24 pm, Frank Gilliland wrote: I do. And part of running a business is catering to the market. Trying to manipulate the market to suit the product (pet rocks, white salmon) might net you a few bucks at the beginning, but the market eventually wises up. Looking at your business history, it appears the market was smarter than you from the beginning, Brian. Frank, you sure know a lot about running a business... and you never even had one... lol Do you have a reading deficiency along with your MPD? The real issue as I see it is... does anyone really care about what you have to say? Of course they do. All these posts are archived on google and elsewhere. Go ahead and google "Telspam Electronics" and tell me what you see. Do you really think people won't check your credentials when buying something that is relatively unknown, with no reputation or testimonials, and can't be found in any reference material beyond your website and your spam? They look at the posts and see that, even when you don't avoid the tough questions altogether, all you can quote is either techno-babble or "it's a gray world". Yep, people really do care about what I have to say. I sure don't. I hope others do... or you're wasting a lot of time here. That's my choice. Whether or not to buy one of your hack-jobs is the choice that people who google your name and product must make. |
#84
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Learn How VoiceMax Increases Your Transmission Range...
"james" wrote...
Partially correct in your formulae. It is printed as I gave it on pages 147 & 148 in... Electrical principles and measurements Level 2 By I. McKenzie Smith (B.Sc., Dip.A.Ed., C. Eng., M.I.E.E., M.I.E.R.E., F.I.T.E) Head of the Department of Electrical Engineering, Stow Colledge, Glasgow. The words of the noted lecturers, one of whom also worked for the Ministry of Defence, are incredibly clear... the waveform does not change. So I think that what we have here is a perception issue. Try this... You say that the waveform changes so tell me: If you amplify a sinusoidal waveform, what waveform does it become? At what level does a sinusoidal waveform become some other waveform? Or, at what level is it a sinusoidal waveform? Can you see where I am going with this? To say that a large sinewave is not still a sinewave is like saying a large circle is no longer a circle. With pure amplification, the signal may have altered in amplitude, but a sinusoidal waveform will still be a sinusoidal waveform on the output. The sine, angular frequency and phase shift are all unchanged. I am not saying that the signal is unaltered, but that the waveform is still whatever waveform was put in. Now I don't like to disagree with you but, if you really believe that an amplified sinewave is not a sinewave, then I really must stick with the named lecturers and Heads of Departments. Nothing personal, you understand, but they do have a sh1tload of letters after their names :~) BTW: Sometimes I may take a while to reply to messages, it's just that I have other things to do and just fit this and other groups in where possible. Regards, Peter. http://www.citizensband.radiouk.com/ |
#85
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Learn How VoiceMax Increases Your Transmission Range...
On Thu, 12 Jul 2007 05:23:51 +0100, " Peter"
wrote: +++With pure amplification, the signal may have altered in amplitude, +++but a sinusoidal waveform will still be a sinusoidal waveform on +++the output. The sine, angular frequency and phase shift are +++all unchanged. ************* Wrong Depending on how the amplifier is configured there is a phase shift. In a Common emmiter configured transistor amp there is a 180 degree shift in the pahse. So the waveform is altered by phase. Only the emitter(source) follower in a semiconductor amplifier will not cause a phase shift. Correct that the angular frequency is not changed and that a sine wave is a sine wave, but still the amplitude has changed. Therefore they are not identical weaveforms. Therefore they do change, if only in amplitude. james |
#86
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Learn How VoiceMax Increases Your Transmission Range...
On Thu, 12 Jul 2007 17:39:01 GMT, james wrote
in : On Thu, 12 Jul 2007 05:23:51 +0100, " Peter" wrote: +++With pure amplification, the signal may have altered in amplitude, +++but a sinusoidal waveform will still be a sinusoidal waveform on +++the output. The sine, angular frequency and phase shift are +++all unchanged. ************* Wrong Depending on how the amplifier is configured there is a phase shift. In a Common emmiter configured transistor amp there is a 180 degree shift in the pahse. So the waveform is altered by phase. Only the emitter(source) follower in a semiconductor amplifier will not cause a phase shift. Correct that the angular frequency is not changed and that a sine wave is a sine wave, but still the amplitude has changed. Therefore they are not identical weaveforms. Therefore they do change, if only in amplitude. I think the key word here is 'waveform', where 'form' is the issue and scale or phase are not. Because ANY device, active or passive, will introduce some phase delay and amplitude variation to the signal. So be practical or be a purist, but you're both really just saying the same thing. Now if you wanted to take this to a philosophical level, no two signals can EVER be identical for the simple reason that they can always be differentiated, if not by amplitude or phase then by temporal location (one is the input, the other is the output) or by physical location (you measure this one here and that one there). But by the same rule of identity I guess that means no two opinions will ever be identical either, so argue away..... |
#87
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Learn How VoiceMax Increases Your Transmission Range...
On Thu, 12 Jul 2007 12:18:59 -0700, Frank Gilliland
wrote: +++On Thu, 12 Jul 2007 17:39:01 GMT, james wrote +++in : +++ +++On Thu, 12 Jul 2007 05:23:51 +0100, " Peter" +++wrote: +++ ++++++With pure amplification, the signal may have altered in amplitude, ++++++but a sinusoidal waveform will still be a sinusoidal waveform on ++++++the output. The sine, angular frequency and phase shift are ++++++all unchanged. +++************* +++ +++Wrong +++ +++Depending on how the amplifier is configured there is a phase shift. +++In a Common emmiter configured transistor amp there is a 180 degree +++shift in the pahse. So the waveform is altered by phase. +++ +++Only the emitter(source) follower in a semiconductor amplifier will +++not cause a phase shift. +++ +++Correct that the angular frequency is not changed and that a sine wave +++is a sine wave, but still the amplitude has changed. Therefore they +++are not identical weaveforms. Therefore they do change, if only in +++amplitude. +++ +++ +++I think the key word here is 'waveform', where 'form' is the issue and +++scale or phase are not. Because ANY device, active or passive, will +++introduce some phase delay and amplitude variation to the signal. So +++be practical or be a purist, but you're both really just saying the +++same thing. +++ +++Now if you wanted to take this to a philosophical level, no two +++signals can EVER be identical for the simple reason that they can +++always be differentiated, if not by amplitude or phase then by +++temporal location (one is the input, the other is the output) or by +++physical location (you measure this one here and that one there). But +++by the same rule of identity I guess that means no two opinions will +++ever be identical either, so argue away..... +++ ********* In a way this could be considered nit picking. I agree that the overall form is a sinusoid. I just don't like the implication that all sinusiods are unchanged by amplification, positve or negative. Granted the amplitude of the form is alterd and little on none of the rest of the function is not. Yet the amplitude is a partt of a sinusoidal waveform. again it is a minor point. james |
#88
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Learn How VoiceMax Increases Your Transmission Range...
On Sat, 14 Jul 2007 20:06:09 GMT, james wrote
in : snip In a way this could be considered nit picking. I agree that the overall form is a sinusoid. I just don't like the implication that all sinusiods are unchanged by amplification, positve or negative. Granted the amplitude of the form is alterd and little on none of the rest of the function is not. Yet the amplitude is a partt of a sinusoidal waveform. again it is a minor point. True, and your point is perfectly valid. You are technically correct that amplification, inversion and phase shift are types of distortion. But for the purpose of -this- discussion (audio distortion caused by Brian's noise-board), it seems you are trying to sand the table-top before cutting down the tree. Now if this were carried over to a new thread it might be fun.... |
#89
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Learn How VoiceMax Increases Your Transmission Range...
"james" wrote...
First of all, I should point out that I have not seen any messages posted since my last reply, they will be downloaded as this is sent... When your mathematics appear to disagree with so many well qualified engineers, lecturers, heads of educational departments and technical authors, it's time to check for some little error... something that can slip through or seem insignificant. The frequency component of the function, sin(2*PI*f*t),remains the same in both equation. It will always appear constant, it is not an absolute value... f*t Through a complete cycle, the maximum result will be 1, regardless of the actual frequency. The amplitude does not. Of course not, *you* are using an absolute value. The waveform is the relationship between changes in amplitude and time. By putting in an absolute value, peak voltage, you are now comparing signal levels rather than waveform. The amplitude should have a maximum value of 1... quote ref=1 The maximum voltage of a sine is 1, thus Vm is the maximum or peak value of the alternating voltage. /quote Diagrams in the book show exactly that. But, as you may not have the book collection that I have, check out the diagram here... http://upload.wikimedia.org/wikipedi...ine_Cosine_Gra ph.png/300px-Sine_Cosine_Graph.png (NOTE: URL wrapped to two lines) Now, v = Vm sin 2pi*f*t = sin 2pi*f*t So, as said before... quote ref=2 Amplification This essential process involves an increase in the amplitude or size of a signal without any change to the waveform. /quote Now I can believe the mathematics that I have been taught or accept your hypothesis. Those are the words of well respected and qualified engineers, lecturers, heads of educational departments and technical authors. Regards, Peter. http://www.citizensband.radiouk.com/ ref1: Electrical and electronic principles Level 2 I. McKenzie Smith. (pages 144 - 148) ref2: Electronics For Engineers. R. J. Maddock (Former principle lecturer, Southampton Institute of Higher Education) D. M. Calcutt (Senior Lecturer, School of Systems Engineering, University of Portsmouth). (page 11) |
#90
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Learn How VoiceMax Increases Your Transmission Range...
Peter
Have a nice day. I think there is little more that can be accomplished continuing this banter. You can believe what you wish. james On Sun, 15 Jul 2007 20:23:12 +0100, " Peter" wrote: +++"james" wrote... +++ +++ +++First of all, I should point out that I have not seen any messages +++posted since my last reply, they will be downloaded as this is sent... +++ +++ +++When your mathematics appear to disagree with so many well +++qualified engineers, lecturers, heads of educational departments +++and technical authors, it's time to check for some little +++error... something that can slip through or seem insignificant. +++ +++ +++ The frequency component of the function, sin(2*PI*f*t),remains the +++ same in both equation. +++ +++It will always appear constant, it is not an absolute value... +++ f*t +++Through a complete cycle, the maximum result will be 1, regardless +++of the actual frequency. +++ +++ +++ The amplitude does not. +++ +++ +++Of course not, *you* are using an absolute value. +++ +++The waveform is the relationship between changes in amplitude +++and time. By putting in an absolute value, peak voltage, you +++are now comparing signal levels rather than waveform. +++ +++The amplitude should have a maximum value of 1... +++ +++quote ref=1 +++ The maximum voltage of a sine is 1, thus Vm is the +++ maximum or peak value of the alternating voltage. +++/quote +++ +++Diagrams in the book show exactly that. But, as you may +++not have the book collection that I have, check out the +++diagram here... +++http://upload.wikimedia.org/wikipedi...ine_Cosine_Gra +++ph.png/300px-Sine_Cosine_Graph.png +++ +++ (NOTE: URL wrapped to two lines) +++ +++Now, +++ v = Vm sin 2pi*f*t +++ = sin 2pi*f*t +++ +++So, as said before... +++ +++quote ref=2 +++ Amplification This essential process involves an increase +++ in the amplitude or size of a signal without any change +++ to the waveform. +++/quote +++ +++ +++ Now I can believe the mathematics that I +++ have been taught or accept your hypothesis. +++ +++ +++Those are the words of well respected and qualified engineers, +++lecturers, heads of educational departments and technical +++authors. +++ +++ +++ +++Regards, +++Peter. +++ http://www.citizensband.radiouk.com/ +++ +++ ref1: Electrical and electronic principles Level 2 +++ I. McKenzie Smith. +++ (pages 144 - 148) +++ +++ ref2: Electronics For Engineers. +++ R. J. Maddock (Former principle lecturer, +++ Southampton Institute of Higher Education) +++ D. M. Calcutt (Senior Lecturer, School of Systems +++ Engineering, University of Portsmouth). +++ (page 11) +++ +++ |
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