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#2
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Don Pearce wrote:
The impedance should be R + jwL + 1/(jwC) 1/j = j/j*j = j/-1 = -j -j/wC = 1/jwC -- Pawel Stobinski Republic of Poland |
#3
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On Tue, 14 Oct 2003 21:30:18 +0200, "Pawel Stobinski"
wrote: Don Pearce wrote: The impedance should be R + jwL + 1/(jwC) 1/j = j/j*j = j/-1 = -j -j/wC = 1/jwC Quite right - the unusual format fooled me. d _____________________________ http://www.pearce.uk.com |
#4
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On Tue, 14 Oct 2003 21:30:18 +0200, "Pawel Stobinski"
wrote: Don Pearce wrote: The impedance should be R + jwL + 1/(jwC) 1/j = j/j*j = j/-1 = -j -j/wC = 1/jwC Quite right - the unusual format fooled me. d _____________________________ http://www.pearce.uk.com |
#5
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Don Pearce wrote:
The impedance should be R + jwL + 1/(jwC) 1/j = j/j*j = j/-1 = -j -j/wC = 1/jwC -- Pawel Stobinski Republic of Poland |
#6
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The impedance should be R + jwL + 1/(jwC)
You sure?, how do the j parts cancel at resonance if they are both added? |
#7
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R + jwL + 1/(jwC)
= R + jwL -j/(wC) so at resonance wL=1/(wC) ie w=1/sqrt(LC) Chris "Michael" wrote in message om... The impedance should be R + jwL + 1/(jwC) You sure?, how do the j parts cancel at resonance if they are both added?+ |
#8
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R + jwL + 1/(jwC)
= R + jwL -j/(wC) so at resonance wL=1/(wC) ie w=1/sqrt(LC) Chris "Michael" wrote in message om... The impedance should be R + jwL + 1/(jwC) You sure?, how do the j parts cancel at resonance if they are both added?+ |
#9
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![]() Don Pearce wrote: On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer) wrote: Hi, Well, I'm really confused. I simulate a simple serial R-C-L-Network (all in series). As far as I know the total (input-)Impedance of the network is: Z = R + jwL - j/(wC) resp. -j/wc= 1/jwc |
#10
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The impedance should be R + jwL + 1/(jwC)
You sure?, how do the j parts cancel at resonance if they are both added? |
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