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#1
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On Dec 28, 8:36*pm, Telamon
wrote: In article , *John Smith wrote: SNIP I never even commented on where the placement of the matchbox would be, and, as everyone knows, anywhere along the line you can place it. *The best place would be between the coax (feedline) and the antenna- Right. That's because you are to stupid to understand a concept until someone rubes your nose in it. This would not even occur to you until someone else brought it up. -that is, taking for granted that the match from your rig to the feedline is perfect. SNIP You are really worried about the match of 50 ohm *coax to your radios 50 ohm output? Now that's funny. -- Telamon Ventura, California IIRC - The Characteristically 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal . . . Until you attach something to it. -IF- You attach the nominal 50 Ohm Impedance of a Transmitter to one end of the Coax Cable the 'other' end will still be about 50 Ohms. - - - What the Antenna will see. However -if- You attach an Unknown "Z" Antenna and Ground to one end of the Coax Cable then the 'other' end may will be near or far from 50 Ohms. - - - What the Transmitter will see. Unknown "Z" Antenna = Random Wire Antenna as always . . . i may be 'w-r-o-n-g' - iane ~ RHF |
#2
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In article
, RHF wrote: On Dec 28, 8:36*pm, Telamon wrote: In article , *John Smith wrote: SNIP I never even commented on where the placement of the matchbox would be, and, as everyone knows, anywhere along the line you can place it. *The best place would be between the coax (feedline) and the antenna- Right. That's because you are to stupid to understand a concept until someone rubes your nose in it. This would not even occur to you until someone else brought it up. -that is, taking for granted that the match from your rig to the feedline is perfect. SNIP You are really worried about the match of 50 ohm *coax to your radios 50 ohm output? Now that's funny. IIRC - The Characteristically 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal . . . Until you attach something to it. SNIP Nope. The cable itself has a characteristic impedance of some design value. The spacing and size of the conductors along with the dielectric constant of the insulator between them dictates the impedance of the coax. You are confusing the characteristic impedance of the coax with its ability to be an effective transmission line. The coax only behaves as an effective transmission line when both ends of it are terminated at its characteristic impedance. -- Telamon Ventura, California |
#3
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In message
, Telamon writes In article , RHF wrote: On Dec 28, 8:36*pm, Telamon wrote: In article , *John Smith wrote: SNIP I never even commented on where the placement of the matchbox would be, and, as everyone knows, anywhere along the line you can place it. *The best place would be between the coax (feedline) and the antenna- Right. That's because you are to stupid to understand a concept until someone rubes your nose in it. This would not even occur to you until someone else brought it up. -that is, taking for granted that the match from your rig to the feedline is perfect. SNIP You are really worried about the match of 50 ohm *coax to your radios 50 ohm output? Now that's funny. IIRC - The Characteristically 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal . . . Until you attach something to it. SNIP Nope. The cable itself has a characteristic impedance of some design value. The spacing and size of the conductors along with the dielectric constant of the insulator between them dictates the impedance of the coax. You are confusing the characteristic impedance of the coax with its ability to be an effective transmission line. The coax only behaves as an effective transmission line when both ends of it are terminated at its characteristic impedance. Are you really sure about this sweeping statement? For starters, please define 'effective'. And are you sure that transmitter output impedances are 50 ohms (or whatever)? -- Ian |
#4
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In article ,
Ian Jackson wrote: In message , Telamon writes In article , RHF wrote: On Dec 28, 8:36*pm, Telamon wrote: In article , *John Smith wrote: SNIP I never even commented on where the placement of the matchbox would be, and, as everyone knows, anywhere along the line you can place it. *The best place would be between the coax (feedline) and the antenna- Right. That's because you are to stupid to understand a concept until someone rubes your nose in it. This would not even occur to you until someone else brought it up. -that is, taking for granted that the match from your rig to the feedline is perfect. SNIP You are really worried about the match of 50 ohm *coax to your radios 50 ohm output? Now that's funny. IIRC - The Characteristically 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal . . . Until you attach something to it. SNIP Nope. The cable itself has a characteristic impedance of some design value. The spacing and size of the conductors along with the dielectric constant of the insulator between them dictates the impedance of the coax. You are confusing the characteristic impedance of the coax with its ability to be an effective transmission line. The coax only behaves as an effective transmission line when both ends of it are terminated at its characteristic impedance. Are you really sure about this sweeping statement? Yes. It is basic transmission line theory. RF energy entering or leaving a coax line has to be at the same impedance or energy is reflected. That is a basic rule. For starters, please define 'effective'. The word effective was used in the context of the coax meeting its specifications within reason. And are you sure that transmitter output impedances are 50 ohms (or whatever)? If it is specified to be 50 ohms and it is not then it should find its way back to the manufacturer for repair or redesign. -- Telamon Ventura, California |
#5
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In message
, Telamon writes In article , Ian Jackson wrote: In message , Telamon writes In article , RHF wrote: On Dec 28, 8:36*pm, Telamon wrote: You are confusing the characteristic impedance of the coax with its ability to be an effective transmission line. The coax only behaves as an effective transmission line when both ends of it are terminated at its characteristic impedance. Are you really sure about this sweeping statement? Yes. It is basic transmission line theory. RF energy entering or leaving a coax line has to be at the same impedance or energy is reflected. That is a basic rule. For starters, please define 'effective'. The word effective was used in the context of the coax meeting its specifications within reason. If the source and load impedances are NOT the same as the characteristic impedance of the coax, any 'ineffectiveness' as a transmission line will not as a result of the coax not meeting its specifications. You simply haven't used coax with the RIGHT specifications. And are you sure that transmitter output impedances are 50 ohms (or whatever)? If it is specified to be 50 ohms and it is not then it should find its way back to the manufacturer for repair or redesign. Indeed, the specs for transmitters do sometimes say that the output impedance is 50 ohms. This is almost certainly wrong. What it really means is that the transmitter is designed to work into a 50 ohm load. The two are rarely the same. Transmitters are designed for best efficiency and/or linearity. The actual output impedance is not really relevant. [Signal generators are different. They SHOULD be 50 ohms. This subject has been discussed ad nauseam in several NGs.] -- Ian |
#6
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In article ,
Ian Jackson wrote: In message , Telamon writes In article , Ian Jackson wrote: In message , Telamon writes In article , RHF wrote: On Dec 28, 8:36*pm, Telamon wrote: You are confusing the characteristic impedance of the coax with its ability to be an effective transmission line. The coax only behaves as an effective transmission line when both ends of it are terminated at its characteristic impedance. Are you really sure about this sweeping statement? Yes. It is basic transmission line theory. RF energy entering or leaving a coax line has to be at the same impedance or energy is reflected. That is a basic rule. For starters, please define 'effective'. The word effective was used in the context of the coax meeting its specifications within reason. If the source and load impedances are NOT the same as the characteristic impedance of the coax, any 'ineffectiveness' as a transmission line will not as a result of the coax not meeting its specifications. You simply haven't used coax with the RIGHT specifications. OK. I don't understand your point though. My original reply is that coax has a characteristic impedance based on its design not what it has for terminations on either end. And are you sure that transmitter output impedances are 50 ohms (or whatever)? If it is specified to be 50 ohms and it is not then it should find its way back to the manufacturer for repair or redesign. Indeed, the specs for transmitters do sometimes say that the output impedance is 50 ohms. This is almost certainly wrong. What it really means is that the transmitter is designed to work into a 50 ohm load. I have to disagree with you here. I work with a lot of test equipment and if this was true good luck getting anything to work. Signal generators and amplifiers have to have output impedances that match the coax impedance or you would not be able to predict how test setups would work. The two are rarely the same. Transmitters are designed for best efficiency and/or linearity. The actual output impedance is not really relevant. [Signal generators are different. They SHOULD be 50 ohms. This subject has been discussed ad nauseam in several NGs.] I don't want to get nauseated then. The arguments to the contrary make no sense. Signal generators, amplifiers, or transmitters all have to have the same system impedance or the RF just gets reflected back at the source, which has to dissipate that additional energy as heat usually. So you would have to beef up the output devices in the source and you would be wasting a portion of the RF generated. -- Telamon Ventura, California |
#7
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On Dec 29, 12:37*pm, Telamon
wrote: In article , *RHF wrote: On Dec 28, 8:36*pm, Telamon wrote: In article , *John Smith wrote: SNIP I never even commented on where the placement of the matchbox would be, and, as everyone knows, anywhere along the line you can place it. *The best place would be between the coax (feedline) and the antenna- Right. That's because you are to stupid to understand a concept until someone rubes your nose in it. This would not even occur to you until someone else brought it up. -that is, taking for granted that the match from your rig to the feedline is perfect. SNIP You are really worried about the match of 50 ohm *coax to your radios 50 ohm output? Now that's funny. IIRC - The Characteristically 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal . . . Until you attach something to it. SNIP Nope. The cable itself has a characteristic impedance of some design value. The spacing and size of the conductors along with the dielectric constant of the insulator between them dictates the impedance of the coax. You are confusing the characteristic impedance of the coax with its ability to be an effective transmission line. The coax only behaves as an effective transmission line when both ends of it are terminated at its characteristic impedance. -- Telamon Ventura, California Telamon, OK -restatement- The "Measured" {by You} 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal* * Until you attach something to it. -IF- You then attach a Transmitters Output that is a Nominal 50 Ohms to one end of the Coax Cable and then the 'other' end will still "Measure*" about 50 Ohms. * This is what the Antenna will see. However -if- You attach an Unknown "Z" Antenna and Ground to one end of the Coax Cable; then the 'other' end may "Measure*" near or far from 50 Ohms. * This is what the Transmitter will see. Unknown "Z" Antenna = Random Wire Antenna as always . . . i may be 'w-r-o-n-g' - iane ~ RHF |
#8
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RHF wrote:
On Dec 29, 12:37 pm, Telamon wrote: In article , RHF wrote: On Dec 28, 8:36 pm, Telamon wrote: In article , John Smith wrote: SNIP I never even commented on where the placement of the matchbox would be, and, as everyone knows, anywhere along the line you can place it. The best place would be between the coax (feedline) and the antenna- Right. That's because you are to stupid to understand a concept until someone rubes your nose in it. This would not even occur to you until someone else brought it up. -that is, taking for granted that the match from your rig to the feedline is perfect. SNIP You are really worried about the match of 50 ohm coax to your radios 50 ohm output? Now that's funny. IIRC - The Characteristically 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal . . . Until you attach something to it. SNIP Nope. The cable itself has a characteristic impedance of some design value. The spacing and size of the conductors along with the dielectric constant of the insulator between them dictates the impedance of the coax. You are confusing the characteristic impedance of the coax with its ability to be an effective transmission line. The coax only behaves as an effective transmission line when both ends of it are terminated at its characteristic impedance. -- Telamon Ventura, California Telamon, OK -restatement- The "Measured" {by You} 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal* * Until you attach something to it. -IF- You then attach a Transmitters Output that is a Nominal 50 Ohms to one end of the Coax Cable and then the 'other' end will still "Measure*" about 50 Ohms. * This is what the Antenna will see. However -if- You attach an Unknown "Z" Antenna and Ground to one end of the Coax Cable; then the 'other' end may "Measure*" near or far from 50 Ohms. * This is what the Transmitter will see. That depends on the length of the transmission line. |
#9
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In article
, RHF wrote: On Dec 29, 12:37*pm, Telamon wrote: In article , *RHF wrote: On Dec 28, 8:36*pm, Telamon wrote: In article , *John Smith wrote: SNIP I never even commented on where the placement of the matchbox would be, and, as everyone knows, anywhere along the line you can place it. *The best place would be between the coax (feedline) and the antenna- Right. That's because you are to stupid to understand a concept until someone rubes your nose in it. This would not even occur to you until someone else brought it up. -that is, taking for granted that the match from your rig to the feedline is perfect. SNIP You are really worried about the match of 50 ohm *coax to your radios 50 ohm output? Now that's funny. IIRC - The Characteristically 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal . . . Until you attach something to it. SNIP Nope. The cable itself has a characteristic impedance of some design value. The spacing and size of the conductors along with the dielectric constant of the insulator between them dictates the impedance of the coax. You are confusing the characteristic impedance of the coax with its ability to be an effective transmission line. The coax only behaves as an effective transmission line when both ends of it are terminated at its characteristic impedance. Telamon, OK -restatement- The "Measured" {by You} 50 Ohm Impedance Coax Cable is 'only' 50 Ohms nominal* * Until you attach something to it. -IF- You then attach a Transmitters Output that is a Nominal 50 Ohms to one end of the Coax Cable and then the 'other' end will still "Measure*" about 50 Ohms. * This is what the Antenna will see. However -if- You attach an Unknown "Z" Antenna and Ground to one end of the Coax Cable; then the 'other' end may "Measure*" near or far from 50 Ohms. * This is what the Transmitter will see. Unknown "Z" Antenna = Random Wire Antenna as always . . . i may be 'w-r-o-n-g' - iane ~ RHF You are just confusing a few things. You need to understand that at RF all parts of a circuit are not "seen" by the RF energy "at the same time." The energy has to propagate through the circuit. This is different from DC where the whole circuit "is seen" by the energy source at once. I'm sure that at DC you are familiar with adding up resistor networks or loads into a total load resistance where you can figure out what the total current would be if you applied a certain voltage. This is also know as a lump sum circuit. At RF since it takes time for the energy to propagate through parts of the circuit so they are not seen at the same time and you have to use vector math that has magnitude and phase components, instead of just magnitude, to describe the current that results from an applied voltage. Now with this vector math representing the circuit impedance as opposed to just magnitude resistance you can make transformations similar to an equivalent DC total load resistance for RF current calculations but you have to keep in mind that these are time or phase dependent. A complication of this is some of the energy can even go backward depending on the circuit so these time dependent voltages and currents need to be summed as vectors with magnitude and phase, which represent a voltage or current at a spot in the circuit. The practical upshot of this is that RF paths like coax have to be viewed as transmission lines where the RF energy only "sees" a part of the coax at any one moment in time and after a short period of time the energy "sees" the next part of the coax and so on until it reaches the end. With this understanding it is the "environment" of the coax that causes it to represent an "impedance" or how it reacts to the RF energy as a complex resistance to its flow. This reactive environment is created by the size, spacing, and DC resistance of the two conductors along with the dielectric value of the insulator between them. Now with that said you can still make the R total type of RF impedance calculation with a resistor or a reactive load on the far end of a coax cable as a total transformed circuit impedance value but it does not change in any way the intrinsic impedance of the coax itself, which is fully dependent on its physical construction. Now, if you are still with me, the coax will only function properly as a transmission line when the source impedance at one end and the load impedance at the other end are the same value. In this state all the RF energy is internal to the coax and if the load or source impedance is not the same currents start to flow on the outside of the coax so it will not shield properly. All the energy will not even enter the coax at the source end and energy will be reflected at the load end creating standing waves of energy on the coax, which is the sum of the forward and reverse waves at any one point. Where these waves sum the voltages can be many times higher than the source causing excessive heating or even breakdown of the dielectric at that point or arcing at the connectors. Under these conditions the coax specifications will not be met. The coax will not meet its isolation, insertion loss, or VSWR specifications even though there is nothing wrong with it. -- Telamon Ventura, California |
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