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#21
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New antenna
On Oct 11, 6:45 pm, John Smith wrote:
JIMMIE wrote: ... I dont have EZNEC, But I will trust you if you care to model a 1/4wl monopole and compare it to an 1/8wl monople operating against a perfect counterpoise. Fine enginneer that Art is he should have no trouble in calculating field intensity at a receiving antenna 1 mile away. I have total respect for the integrity of your work as long as you show your math. Jimmie No. We are talking about a small antenna ~25% of full 1/4 wave length which performs as well or outperforms its full length 1/4 wave version. We are talking about a 1/2 wave antenna which is only 20-30% the length of its full length 1/2 wave version which performs as well or even out performs its' full 1/2 wave length ... Show me an EZNEC model of what the Navy tested for Mr. Vincent--indeed, show me where anyone before Mr. Vincent was able to demonstrate a working model capable of the above characteristics? JS http://www.fi.uba.ar/materias/6654/d...FMFAntenna.pdf Probably more than you ever wanted to know about short antennas. Jimmie |
#22
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New antenna
On 11 Oct, 18:58, JIMMIE wrote:
On Oct 11, 6:45 pm, John Smith wrote: JIMMIE wrote: ... I dont have EZNEC, But I will trust you if you care to model a 1/4wl monopole and compare it to an 1/8wl monople operating against a perfect counterpoise. Fine enginneer that Art is he should have no trouble in calculating field intensity at a receiving antenna 1 mile away. I have total respect for the integrity of your work as long as you show your math. Jimmie No. We are talking about a small antenna ~25% of full 1/4 wave length which performs as well or outperforms its full length 1/4 wave version. We are talking about a 1/2 wave antenna which is only 20-30% the length of its full length 1/2 wave version which performs as well or even out performs its' full 1/2 wave length ... Show me an EZNEC model of what the Navy tested for Mr. Vincent--indeed, show me where anyone before Mr. Vincent was able to demonstrate a working model capable of the above characteristics? JS http://www.fi.uba.ar/materias/6654/d...FMFAntenna.pdf Probably more than you ever wanted to know about short antennas. Jimmie- Hide quoted text - - Show quoted text - Now a bunch of erronious information He states for short antennas a good ground field is paramount which is false. It is correct for a fractional wavelength antenna but not for a short antenna. Then he goes on to relate a top hat with efficiency so the question is does the top hat make radiation per unit length the same terminology as efficiency since the top hat does not increase height? Basically, if you have a fractional wavelength antenna then a ground plane is paramount to provide a low resistance to ground (power loss)for the the ANTENNA circuit. If a low resistance path to ground is not there then the system is closed by the outside of the feed sheathing to transmitter ground which closes the ANTENNA system providing combination radiation as well as system loss. I say again, one must have equilibrium for maximum efficiency and that requires a full wave length radiator and at the same time holding to the LC ratio for that length. These are cardinal rules as shown by Gauss. Regards Art KB9MZ |
#23
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New antenna
On Oct 11, 4:25 pm, Roy Lewallen wrote:
Gene Fuller wrote: . . . What I found was interesting, but not surprising. When the wires were treated as lossless, there was virtually no difference in bandwidth or any other parameter. The parasitic winding had essentially no impact. When I changed the wires to copper, the bandwidth increased in both cases. However, in the case with the parasitic winding the new bandwidth was 2.5 times as large as the case without the extra winding. The resonant input impedance was also about 2.5 times larger. There is only one plausible explanation for this observation. The parasitic winding adds loss to the antenna system. I won't claim this is "bad". Depends on the characteristics desired. You can easily verify this by noting the change in gain as the extra winding is added and deleted. You should also see a corresponding change in feedpoint resistance, assuming that the extra winding doesn't change the current distribution. A couple of additional interesting experiments would be: 1. Increase the loss of the coil in a model without the extra winding until the gain is the same as the model with copper loss and no extra winding. Then see how the bandwidth compares to the original model with extra winding. 2. Instead of increasing the loss of the coil, add a resistor to the base of the copper loss non-extra winding antenna and adjust it so the gain is the same as for the model with copper loss and extra winding. How does the bandwidth compare to the original model with the extra winding? The bottom line is that there is no wondrous invention here. Either Vincent knew about this effect and chose to ignore it, or he did not understand what was happening. The capacitance explanation is just baloney. I'm afraid that's probably true. With antennas, you can choose any two of efficient, and broadband, and electrically small. This antenna claims all three, so I'm very skeptical. Roy Lewallen, W7EL- Hide quoted text - - Show quoted text - Maybe it not the wire but the insulation on the wire, A little dielectric heating would surely make it more broadbanded. Jimmie |
#24
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New antenna
"art" wrote in message oups.com... If he understood Gaussian law then he could have made the Gaussian antenna which requires an element in equilibrium which means a FULL WAVELENGTH. I know you dislike the meaning of the term equilibrium b ut here it is indispesable. you contradict yourself now... you told us before that you used half wavelength elements for you 'gaussian' antenna???? Even without the knoweledge of Gauss he came very close to Gauss or the biggest discovery of the century If one winds a half wave length in a clockwise direction starting at the top going down and then repeating with another halfwave length but winding it in a counterclockwise direction( preferably winding both wires at the same time) and then joining together the two wires at the top he would then have a copy of my Gaussian antenna. Another contradiction. earlier you have said that the 'gaussian' elements were simple straight halfwave elements???? and ONE MORE TIME.... define 'equilibrium'. write the equations. just what is in 'equilibrium' with what?? |
#25
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New antenna
On 13 Oct, 03:55, "Dave" wrote:
"art" wrote in message oups.com... If he understood Gaussian law then he could have made the Gaussian antenna which requires an element in equilibrium which means a FULL WAVELENGTH. I know you dislike the meaning of the term equilibrium b ut here it is indispesable. you contradict yourself now... you told us before that you used half wavelength elements for you 'gaussian' antenna???? Hi David, back to your old tricks again eh? If you go up a halfwave length and then come down a halfwaveleng you then have 2 x 1/2 so you don't have a half wave length anymore. Watch the childrens hour on TV for the answer Even without the knoweledge of Gauss he came very close to Gauss or the biggest discovery of the century If one winds a half wave length in a clockwise direction starting at the top going down and then repeating with another halfwave length but winding it in a counterclockwise direction( preferably winding both wires at the same time) and then joining together the two wires at the top he would then have a copy of my Gaussian antenna. Another contradiction. earlier you have said that the 'gaussian' elements were simple straight halfwave elements???? You have just got to watch childrens hour to get up to speed for your mathematics, new math that is. A gaussian antenna can be any shape, size or configuration as long as it is in a state of equilibrium and ONE MORE TIME.... define 'equilibrium'. write the equations. just what is in 'equilibrium' with what?? No David I am not going to go thru all that again,get yourself a physics book or Google around Art |
#26
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New antenna
"Dave" wrote
and ONE MORE TIME.... define 'equilibrium'. write the equations. just what is in 'equilibrium' with what?? __________ Art posted his definition in this thread on Oct 11. But no math to support it. \\ If he understood Gaussian law then he could have made the Gaussian antenna which requires an element in equilibrium which means a FULLWAVELENGTH. I know you dislike the meaning of the term equilibrium but here it is indispesable. // What I get from his comments is that Art believes fractional wavelength radiators are inefficient because they are not in equilibrium, ie, they are not a full wave length and therefore don't act like a tank circuit (he says) -- which he believes is necessary for efficient radiation. I've sent Art several emails with NEC results and math-based discussion showing that a 1/4-wave monopole working against a 2-ohm r-f ground plane radiates about 95% of the power applied by a matched source between it base feedpoint and r-f ground. This is the configuration used by virtually all commercial AM broadcast stations, and its very high system radiation efficiency has been proven thousands of times since the earliest days of broadcasting. Of course that is at odds with the beliefs Art continues to post here and elsewhere. In a response to my emails Art seemed to understand, and even thanked me for "sticking with it." But I guess he was not convinced, because he started this thread _after_ our email exchange. Since my discussions with Art I put together a chart showing the groundwave field generated at 1 km by several, fractional wavelength monopoles at applied powers from 1-10 kW (see link below). I used a perfect ground plane in preparing the chart, but the values would be only slightly less with a 2-ohm r-f ground. ART: Note that the 1 kW field for the 1/4-wave monopole is exactly the peak field of a 1/2-wave dipole in free space (about 313 mV/m). Taller monopoles generate more groundwave field, given the same applied power and r-f ground, because their radiation patterns have more gain in the horizontal plane and less gain in other directions -- not because they are more "efficient." All of the monopoles in this chart radiate all of the power applied to them (100% efficient). Also note, Art, that a 1/2-wave monopole and its ground image comprise a full-wave antenna (eg, having your "equilibrium"), yet the 195-degree and 225-degree monopoles produce higher groundwave fields, even though they are NOT by your definition "in equilibrium." http://i62.photobucket.com/albums/h8...Radiator10.gif RF |
#27
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New antenna
On 13 Oct, 06:28, "Richard Fry" wrote:
"Dave" wrote and ONE MORE TIME.... define 'equilibrium'. write the equations. just what is in 'equilibrium' with what?? __________ Art posted his definition in this thread on Oct 11. But no math to support it. \\ If he understood Gaussian law then he could have made the Gaussian antenna which requires an element in equilibrium which means a FULLWAVELENGTH. I know you dislike the meaning of the term equilibrium but here it is indispesable. // What I get from his comments is that Art believes fractional wavelength radiators are inefficient because they are not in equilibrium, ie, they are not a full wave length and therefore don't act like a tank circuit (he says) -- which he believes is necessary for efficient radiation. I've sent Art several emails with NEC results and math-based discussion showing that a 1/4-wave monopole working against a 2-ohm r-f ground plane radiates about 95% of the power applied by a matched source between it base feedpoint and r-f ground. This is the configuration used by virtually all commercial AM broadcast stations, and its very high system radiation efficiency has been proven thousands of times since the earliest days of broadcasting. Of course that is at odds with the beliefs Art continues to post here and elsewhere. In a response to my emails Art seemed to understand, and even thanked me for "sticking with it." But I guess he was not convinced, because he started this thread _after_ our email exchange. Since my discussions with Art I put together a chart showing the groundwave field generated at 1 km by several, fractional wavelength monopoles at applied powers from 1-10 kW (see link below). I used a perfect ground plane in preparing the chart, but the values would be only slightly less with a 2-ohm r-f ground. ART: Note that the 1 kW field for the 1/4-wave monopole is exactly the peak field of a 1/2-wave dipole in free space (about 313 mV/m). Taller monopoles generate more groundwave field, given the same applied power and r-f ground, because their radiation patterns have more gain in the horizontal plane and less gain in other directions -- not because they are more "efficient." All of the monopoles in this chart radiate all of the power applied to them (100% efficient). Also note, Art, that a 1/2-wave monopole and its ground image comprise a full-wave antenna (eg, having your "equilibrium"), yet the 195-degree and 225-degree monopoles produce higher groundwave fields, even though they are NOT by your definition "in equilibrium." http://i62.photobucket.com/albums/h8...veFieldvsPower... RF When you said if the Gaussian antenna was real it would have been invented long ago or something like that and yet they are still giving out patents and Nobel prizes out for things that are newly discovered I lost interest in your musings. When you added things like an image is real I have to walk away because you are just not on my wavelength. I fed the half wave image and also hooked it up to a receiver and I heard nothing, let me know when you make a contact or maybe I should dig a little bit deeper! Art Art |
#28
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New antenna
"art" wrote in message ups.com... On 13 Oct, 06:28, "Richard Fry" wrote: "Dave" wrote and ONE MORE TIME.... define 'equilibrium'. write the equations. just what is in 'equilibrium' with what?? __________ Art posted his definition in this thread on Oct 11. But no math to support it. \\ If he understood Gaussian law then he could have made the Gaussian antenna which requires an element in equilibrium which means a FULLWAVELENGTH. I know you dislike the meaning of the term equilibrium but here it is indispesable. // What I get from his comments is that Art believes fractional wavelength radiators are inefficient because they are not in equilibrium, ie, they are not a full wave length and therefore don't act like a tank circuit (he says) -- which he believes is necessary for efficient radiation. I've sent Art several emails with NEC results and math-based discussion showing that a 1/4-wave monopole working against a 2-ohm r-f ground plane radiates about 95% of the power applied by a matched source between it base feedpoint and r-f ground. This is the configuration used by virtually all commercial AM broadcast stations, and its very high system radiation efficiency has been proven thousands of times since the earliest days of broadcasting. Of course that is at odds with the beliefs Art continues to post here and elsewhere. In a response to my emails Art seemed to understand, and even thanked me for "sticking with it." But I guess he was not convinced, because he started this thread _after_ our email exchange. Since my discussions with Art I put together a chart showing the groundwave field generated at 1 km by several, fractional wavelength monopoles at applied powers from 1-10 kW (see link below). I used a perfect ground plane in preparing the chart, but the values would be only slightly less with a 2-ohm r-f ground. ART: Note that the 1 kW field for the 1/4-wave monopole is exactly the peak field of a 1/2-wave dipole in free space (about 313 mV/m). Taller monopoles generate more groundwave field, given the same applied power and r-f ground, because their radiation patterns have more gain in the horizontal plane and less gain in other directions -- not because they are more "efficient." All of the monopoles in this chart radiate all of the power applied to them (100% efficient). Also note, Art, that a 1/2-wave monopole and its ground image comprise a full-wave antenna (eg, having your "equilibrium"), yet the 195-degree and 225-degree monopoles produce higher groundwave fields, even though they are NOT by your definition "in equilibrium." http://i62.photobucket.com/albums/h8...veFieldvsPower... RF When you said if the Gaussian antenna was real it would have been invented long ago or something like that and yet they are still giving out patents and Nobel prizes out for things that are newly discovered I lost interest in your musings. When you added things like an image is real I have to walk away because you are just not on my wavelength. I fed the half wave image and also hooked it up to a receiver and I heard nothing, let me know when you make a contact or maybe I should dig a little bit deeper! Art Art the basic problem is art that you forget we had a long conversation about what a 'gaussian' antenna in your dream was. and you specifically said a single halfwave dipole was a 'gaussian' antenna. you can go back and search if you like, but i doubt that you will since you have now changed your imaginary antenna. please art, go take a long walk... a very long walk, the fresh air may do you good. |
#29
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New antenna
On 13 Oct, 06:28, "Richard Fry" wrote:
"Dave" wrote and ONE MORE TIME.... define 'equilibrium'. write the equations. just what is in 'equilibrium' with what?? __________ snip commercial AM broadcast stations, and its very high system radiation efficiency has been proven thousands of times since the earliest days of broadcasting. Of course that is at odds with the beliefs Art continues to post here and elsewhere. In a response to my emails Art seemed to understand, and even thanked me for "sticking with it." But I guess he was not convinced, because he started this thread _after_ our email exchange. RF When a person E mails me in private he is suggesting an element of trust ie that it is private. When you betray that trust you can forget about any future discussion, private by E mail or public via the group Art Since my discussions with Art I put together a chart showing the groundwave field generated at 1 km by several, fractional wavelength monopoles at applied powers from 1-10 kW (see link below). I used a perfect ground plane in preparing the chart, but the values would be only slightly less with a 2-ohm r-f ground. ART: Note that the 1 kW field for the 1/4-wave monopole is exactly the peak field of a 1/2-wave dipole in free space (about 313 mV/m). Taller monopoles generate more groundwave field, given the same applied power and r-f ground, because their radiation patterns have more gain in the horizontal plane and less gain in other directions -- not because they are more "efficient." All of the monopoles in this chart radiate all of the power applied to them (100% efficient). Also note, Art, that a 1/2-wave monopole and its ground image comprise a full-wave antenna (eg, having your "equilibrium"), yet the 195-degree and 225-degree monopoles produce higher groundwave fields, even though they are NOT by your definition "in equilibrium." http://i62.photobucket.com/albums/h8...veFieldvsPower... RF |
#30
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New antenna
"art" wrote
Back to the Vincent antenna, he has designed an antenna that is shorter than that known before. .... The input impedance is an advantage over similar antennas and at the same time not requiring a ground plain without being a problem to the transmitter. He is also radiating well in comparison to the height of antenna and the radiating system has the appearance of being efficient. ___________ Probably you'll agree that good, new antenna designs need more than "the appearance of being efficient." Let's expand on this.. The link below leads to a calculation of the system radiation efficiency and r-f bandwidth of a conventional, 30-degree, base-loaded monopole, using the equations found in standard antenna engineering texts. This is the physical height used for the "standard DLM" antennas tested by the Navy for the University of Rhode Island. The coil and r-f ground loss was set to 2 ohms, total, to approximate the conditions in the U-RI test. This non-DLM configuration of a short monopole has a system radiation efficiency of about 59%, and for 1 kW of applied power generates an inverse distance groundwave field of 241 mV/m at 1 km. A standard, 1/4-wave vertical monopole with a matching network and r-f ground loss of 2 ohms, total, is about 95% efficient, and for 1 kW of applied power generates an inverse distance groundwave field of about 306 mV/m at 1 km. So the field of the 30-degree radiator is about 2.07 dB below that of the 90-degree radiator -- and that is due mostly to the much lower radiation resistance of the 30-degree radiator (about 2.9 ohms vs about 36 ohms) against the 2 ohms of other losses in each system. The March 31, 2005 U-RI test report states that the 3.5 MHz standard DLM had a measured groundwave field at 1 mile that was 2.33 dB less than the Navy's reference monopole (whose electrical height is not stated, but presumably is 90 degrees). So the measured h-plane gain of that DLM was about 0.26 dB _less_ than a conventional, base-loaded, 30-degree monopole -- although that difference could be within the range of measurement and/or modeling error. Also note, Art, that the DLM needs a good r-f ground, just as do all monopoles, and especially short ones. The Navy went to great effort to provide a very good r-f ground and propagation path for the range where the DLM was tested. http://i62.photobucket.com/albums/h8...rtMonopole.gif RF |
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