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#1
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Art wrote:
"What you nust understand is the circuit that constitutes a capacitor part of which is a resistor that is seen in parallel." That would be equivalent to a leaky capacitor. There is no time delay in a pure resistor. Its voltage drop is in-phase with the current through it. I don`t have a complete equivalent circuit in mind. Best regards, Richard Harrison, KB5WZI |
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#2
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On 17 Nov, 16:57, (Richard Harrison) wrote:
Art wrote: "What you nust understand is the circuit that constitutes a capacitor part of which is a resistor that is seen in parallel." That would be equivalent to a leaky capacitor. There is no time delay in a pure resistor. Its voltage drop is in-phase with the current through it. I don`t have a complete equivalent circuit in mind. Best regards, Richard Harrison, KB5WZI Right. The the sino soidal shape will go thru with its time varient which is the condition applied by programmers for EVERY segment. But that is only half the story for a TANK circuit. The capacitor stores energy just like charging a battery, it will not NOT thru. When the situation is right the capacitor/battery releases all its energy like connecting a terminal to ground or shorting it.This allows the energy to flow in dc format at a rate decides by its time constant ot time varient required for radiation. This energy release is imposed on the leakage current thus forming a new time varient rquirede for radiation. Thus at different segment points the time varient is not a reflection of a sino soidal leakage current but the summation of that PLUS the capacitor dicharge time constant. Look up a tank circuit and all will become clear when you follow the phase changes of the voltage and the current first in forward direction and then the reverse direction. Regards Art |
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#3
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Art wrote:
"When the situation is right the capacitor/battery releases all its energy like connecting a terminal to ground or shorting it." Not quite. The inductance, whose reactance equals the capacitance`s reactance at resonance, opposes any change in current. It only allows current to grow exponentially during the cycle by simultaneously generating a counter emf to oppose the current imposed on the inductance from outside. The impressed current will lag the voltage across a pure inductance by 90 degrees. The voltage builds across a pure capacitance with a 90 degree lag of the current through the capacitance. This is basic electricity 101. Best regards, Richard Harrison, KB5WZI |
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#4
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On 18 Nov, 19:00, (Richard Harrison) wrote:
Art wrote: "When the situation is right the capacitor/battery releases all its energy like connecting a terminal to ground or shorting it." Not quite. The inductance, whose reactance equals the capacitance`s reactance at resonance, opposes any change in current. It only allows current to grow exponentially during the cycle by simultaneously generating a counter emf to oppose the current imposed on the inductance from outside. The impressed current will lag the voltage across a pure inductance by 90 degrees. The voltage builds across a pure capacitance with a 90 degree lag of the current through the capacitance. This is basic electricity 101. Maybe in America! Since it is resonant then it is a tank circuit where you have to rethink the 90 degree lag Art Best regards, Richard Harrison, KB5WZI |
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#5
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Richard Harrison wrote:
Art wrote: "When the situation is right the capacitor/battery releases all its energy like connecting a terminal to ground or shorting it." Not quite. The inductance, whose reactance equals the capacitance`s reactance at resonance, opposes any change in current. It only allows current to grow exponentially during the cycle by simultaneously generating a counter emf to oppose the current imposed on the inductance from outside. The impressed current will lag the voltage across a pure inductance by 90 degrees. The voltage builds across a pure capacitance with a 90 degree lag of the current through the capacitance. This is basic electricity 101. A little too basic, I'm afraid. The 90 degree current lag applies only to a steady state sinusoidal voltage. For other waveforms (like ones you'd get connecting batteries or capacitors) you have to resort to the more general time relationship v = L * di/dt. (Or, if inductance is changing with time, v = d/dt (L * i).) Roy Lewallen, W7EL |
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#6
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Roy Lewallen wrote:
"S little too basic, I`m afraid. The 90 degree current lag applies only to a steady state sinusoidal voltage." A steady state sinusoidal voltage is exactly what I would expect on a resonant antenna in the absence of modulation when a carrier has been applied to the antenna for a short but not too short period of time. Best regards, Richard Harrison, KB5WZI |
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#7
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I wrote:
"The impressed current will lag the voltage across a pure inductance by 90 degrees." Roy wrote: "For other waveforms (like the ones you`d get connecting batteries or capacitors) you have to resort to the more general time relationship L*di/dt. Roy is correct for connecting batteries or capacitors but Art was working wih a lengthy antenna, not a lone elementary segment. He also had no step functions, just a sine wave driving his antenna. Best regards, Richard Harrison, KB5WZI |
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#8
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On 20 Nov, 16:02, (Richard Harrison) wrote:
I wrote: "The impressed current will lag the voltage across a pure inductance by 90 degrees." Roy wrote: "For other waveforms (like the ones you`d get connecting batteries or capacitors) you have to resort to the more general time relationship L*di/dt. Roy is correct for connecting batteries or capacitors but Art was working wih a lengthy antenna, not a lone elementary segment. He also had no step functions, just a sine wave driving his antenna. Best regards, Richard Harrison, KB5WZI Oh Richard, you may deny my antenna but that is what I was alluding to. Again it is the LC ratio thatmust be kept for resonance. The importance of these are their characteristics as storage containers of energy the release of which is determined by their time constant. Both release their energy in turn to remove static particles from the surface of the radiator in a similar way to a battery at the time of explosion.( Note the battery comment which is what you responded to} This is the time varient required for radiation that the masters disclosed but without pertinent details. This started when the Gaussian law of statics was shown by me to equate to the laws founded by Maxwell. SO WHAT was the thread that then dominated. But for me it was not the marrying of Gauss to Maxwell it was the journey taken in pursuit of knoweledge that could only be revealed by walking in the same shoes that Gauss would have done if he had not deserted mathematics. The journey shows evidence that static particles are at rest on a radiators surface. It also provides evidence that radiators with respect to Maxwells teachings are a wavelength long and in equilibrium when placed with static particles in a arbitary border. It then points to the logic of the time varient mentioned by the masters was NOT the sino soidal current provided but instead the explosion type release of energy from the inherrent storage containers. True sino soidal current runs around the circuit but only because a bypass resister is present with all capacitors. This bypass current is extremely small compared to the energy blast from a energy container. By the same token for equilibrium to be maintained the LC ratio must be kept to simulate the action of a pendulum and its occillations. Now the above is revealed not by the proof of the final calculations but from all that is observed during the required journey., From the above it becomes obvious that the condition added by programmers was not only a fraud but also incorrect when the condition was added to existing law (which is fraudulent. When this inaccurate condition is removed and Maqxwells laws adhered to the errors generated by this false addition will disappear. From the above it can now be said that a radiator can be any shape or variety of elevation as long as it is in equilibrium (ala a wavelength long) where it can provide a lossless means of radiation when disregarding frictional losses of the circuit. It is also impotant to note that if the inductive energy level container is made larger at the same time holding to the LC ratio then the time constant required for radiation will increase. So think again when you wish to say "So What" since the above will become a lasting acceptance of science regardless of the baying crowd of this newsgroup that want to depart to newer aproaches that describe the Universe. Oh, and another side comment, I have a rotatable top band antenna on the top of by tower using the nsame principles alluded to above and yes it is directional and does not require a ground plain to attain equilibrium. Have a happy day Art Unwin ....KB9MZ..XG (uk) |
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#9
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Art wrote:
"Oh Richard, you may deny my antenna but that is what I was alluding to. Again it is the LC ratio that must be kept for resonance." I don`t know enough about Art`s antenna to deny it. I do know that resonance depends on the reciprocal of the sq. rt. of the product of LC, not its quotient. Explosive results from an inductor were introduced by Kettering, I believe, through interruption of battery current through an inductor to generate a very high voltage spark to ignite the fuel air mixture within the cylinder of an internal combustion engine for automobiles. Just as I doubt the inclusion of a pendulum in Art`s antenna, I also doubt the presence of an interruptor to discharge either the capacitance or inductance in the resonant antenna. If Art`s antenna is novel, useful, and not completely obvious from prior knowlege, he may profit from it. I wish him all the best. Best regards, Richard Harrison, KB5WZI |
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#10
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On 20 Nov, 16:02, (Richard Harrison) wrote:
I wrote: "The impressed current will lag the voltage across a pure inductance by 90 degrees." Roy wrote: "For other waveforms (like the ones you`d get connecting batteries or capacitors) you have to resort to the more general time relationship L*di/dt. Roy is correct for connecting batteries or capacitors but Art was working wih a lengthy antenna, not a lone elementary segment. He also had no step functions, just a sine wave driving his antenna. Best regards, Richard Harrison, KB5WZI I am afraid it is more than that. Without an understanding of changing phase angles of both voltage and current you will never understand antennas. Look back at the comment you made with respect to phase angle and then re read Roy's comment where he corrected you with respect to phase angles. You will just have to refresh yourself with respect to voltage and current phase angles especially when they have the SAME phase angle . My guess is you will find it in books by Bailey, Kraus and ofcourse "you know who". And yes, I feed my antenna with a sine wave which by passes a capacitor but what on earth has that got to do with the subject of batteries e.t.c.? That sino soidal bypass is often termed "leakage" which is extremely small compared to the total energy fed to a radiator that creats radiation tho necessary for relative phase angles to change. You made a reference to" 101" for those who went to college well if you did,then refresh yourself with notes taken Art Unwin |
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