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On Wed, 10 Mar 2004 13:43:05 -0800, Jim Kelley wrote:
Reg Edwards wrote: Cecil Moore wrote: Reg, we have a clear example of where the high voltage part of the antenna is not allowed to radiate (much). That would be a balanced top hat. Not allowing the high voltage part of the antenna to radiate leaves the high current part to do most of the radiating. Cecil, Reg makes a good point. We know that the same amplitude (less ohmic losses) of current travels the entire length of the antenna in both directions. The relative phase of forward and reverse currents simply makes the superposition of the two currents greater at one end than another. We might measure the standing wave current with an ammeter, but it is the traveling wave currents which radiate. 73, Jim AC6XG ============================ Jim, are you one of the crackpots who think that it's the voltage parts of the antenna which do the radiating which is proved by replacing the top portion of the antenna with a top hat which has a large capacitance so that the voltage has a greater effect. ;o) --- Reg, G4FGQ Hi Reg, Were it not for this group, I would never have known the full extent of my crackpottedness! My colleagues and associates have been keeping it a secret from me all these years evidently. With that in mind, yes. Nevermind Farady. The size of the hat should indeed determine the size of the effect. I wear a 7 3/4. 73, Jim AC6XG Have you guys ever considered that since the infinitesimally short dipole radiates only 4 percent less than a resonant dipole, the only reason for having any longer length than infinitesimally short is to make it resonant? So what do you think the relation between voltage and current is in the short dipole? Does that bring to mind whether the max radiation occurs at the max voltage or max current portion of the dipole? Walt, W2DU |