Home |
Search |
Today's Posts |
#11
![]() |
|||
|
|||
![]()
W5DXP wrote:
Jim Kelley wrote: I've never disputed the solutions produce the same number. I disputed the validity of the approach you took to arrive at the equation. Here's a question for you, Jim. How much power is transferred from the mismatched load rearward by Pref2? First I have to know where it is being transferred. I don't see two ends of a path. Is there a load resistor hiding in a circulator somewhere? Is the 33.33 watts extra power that I could drive another antenna with, but is otherwise going unused? Or is it instead, simply a field that is excited by the boundary conditions at the load that is being measured. source---50 ohm feedline---+---150 ohm feedline---load Pfwd1=200W -- Pfwd2=133.33W -- -- Pref1=100W -- Pref2=33.33W If, as you have asserted, Pref2 can transfer zero watts when it measures 33.33W, can it also transfer 100W when it measures 33.33W? The meter measures voltage, assumes a transfer of energy, and displays power based on that assumption. 73, ac6xg |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Cecil's Math a Blunder? | Antenna | |||
Cecil's Math | Antenna |