Richard Clark wrote:

wrote:
For lossless transmission lines, |rho| = Sqrt(Pref/Pfwd). You don't
even need to know the load and/or source impedances.

How did you get a -1 out of your |rho|?

I probably should have said rho^2 = Pref/Pfwd. When Pref = Pfwd,
rho can be plus or minus one. I used |rho| to indicate a magnitude,
sans phase angle, not an absolute value.
--
73, Cecil http://www.qsl.net/w5dxp



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