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#1
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Tom Donaly wrote:
VSWR stands for Voltage Standing Wave Ratio. It's supposed to be the ratio of the greatest voltage on a transmission line to the least voltage on the same line. On the line with a 72 ohm Z0, and a 50 ohm load, there exists a standing wave, and the ratio of maximum to minimum is 1.44 whether you measure it with a 50 ohm bridge at the beginning or not. If you define SWR as what a 50 ohm SWR bridge measures, you haven't quite grasped the concept. And Fred didn't ask what an SWR bridge would measure. He asked: "What would the SWR be ... ?" You're right. The SWR would be 1.44:1. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#2
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OK CECIL!!!
Leave it up to you to pull the rug out from under me... If I have a transmitter that has 50 ohm out, and it is going to hook to a 50 ohm cable (and I can't see how this coax is terminated) why would I ever choose anything other than a 50 ohm calibrated swr meter to measure it with? Is that what I have seen on FS meters before (a rise in apparent radiation from the coax shield--and yet match looks good) and the 1/2 wave coax is really now part of the antenna? And, if the meter didn't give me the right reading, and cooked my "BEEG LEENEAIR" could I sue the manufacturer, buy a yacht and live in the Bahamas, drinking Peter Vella Merlot? grin Warmest regards, John "Cecil Moore" wrote in message ... Tom Donaly wrote: VSWR stands for Voltage Standing Wave Ratio. It's supposed to be the ratio of the greatest voltage on a transmission line to the least voltage on the same line. On the line with a 72 ohm Z0, and a 50 ohm load, there exists a standing wave, and the ratio of maximum to minimum is 1.44 whether you measure it with a 50 ohm bridge at the beginning or not. If you define SWR as what a 50 ohm SWR bridge measures, you haven't quite grasped the concept. And Fred didn't ask what an SWR bridge would measure. He asked: "What would the SWR be ... ?" You're right. The SWR would be 1.44:1. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#3
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Cecil:
I screwed that up... in the above, should have been... "If I have a transmitter that has 50 ohm out, and it is going to hook to a 72 ohm cable..." The 72 ohm cable being t he only difference... and point being--don't I only care I am presenting a 50 ohm load to the transmitter? Warmest regards, John "John Smith" wrote in message ... OK CECIL!!! Leave it up to you to pull the rug out from under me... If I have a transmitter that has 50 ohm out, and it is going to hook to a 50 ohm cable (and I can't see how this coax is terminated) why would I ever choose anything other than a 50 ohm calibrated swr meter to measure it with? Is that what I have seen on FS meters before (a rise in apparent radiation from the coax shield--and yet match looks good) and the 1/2 wave coax is really now part of the antenna? And, if the meter didn't give me the right reading, and cooked my "BEEG LEENEAIR" could I sue the manufacturer, buy a yacht and live in the Bahamas, drinking Peter Vella Merlot? grin Warmest regards, John "Cecil Moore" wrote in message ... Tom Donaly wrote: VSWR stands for Voltage Standing Wave Ratio. It's supposed to be the ratio of the greatest voltage on a transmission line to the least voltage on the same line. On the line with a 72 ohm Z0, and a 50 ohm load, there exists a standing wave, and the ratio of maximum to minimum is 1.44 whether you measure it with a 50 ohm bridge at the beginning or not. If you define SWR as what a 50 ohm SWR bridge measures, you haven't quite grasped the concept. And Fred didn't ask what an SWR bridge would measure. He asked: "What would the SWR be ... ?" You're right. The SWR would be 1.44:1. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#4
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John Smith wrote:
The 72 ohm cable being t he only difference... and point being--don't I only care I am presenting a 50 ohm load to the transmitter? I won't presume to know what you care about. I care about the SWR on my feedline. I have homebrew SWR meters calibrated for 300, 450, and 600 ohms. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#5
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Cecil:
Darn!!! I was hoping ya cared... just kidding I think you took that the wrong way... I didn't mean to insinuate there was nothing to worry about... or that I would not be interested in the long run about losses... but either way, the answer is just as appreciated... grin Warmest regards, John "Cecil Moore" wrote in message ... John Smith wrote: The 72 ohm cable being t he only difference... and point being--don't I only care I am presenting a 50 ohm load to the transmitter? I won't presume to know what you care about. I care about the SWR on my feedline. I have homebrew SWR meters calibrated for 300, 450, and 600 ohms. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#6
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John Smith wrote:
Cecil: Darn!!! I was hoping ya cared... just kidding I didn't say I didn't care. I said I didn't presume. :-) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#7
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John Smith wrote:
Leave it up to you to pull the rug out from under me... If I have a transmitter that has 50 ohm out, and it is going to hook to a 50 ohm cable (and I can't see how this coax is terminated) why would I ever choose anything other than a 50 ohm calibrated swr meter to measure it with? Some of us want to know what the SWR on the feedline is. That's how we calculate feedline losses. I get a kick out of some ham saying, "I'm running a 66' dipole on 75m and my SWR is 1.1:1." All that means is that the virtual impedance at the tuner input is probably 45 ohms or 55 ohms. But what is the SWR at the output of the tuner where it matters the most? -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#8
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My question was totally answered by Walt W2DU. Thank you for the detailed
explaination. |
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