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#1
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One more time.
It was a WORST CASE calculation which placed an upper bound on the possible loss from operating into a 1.7:1 SWR as opposed to a 1:1 SWR. In practice most of the power is eventually radiated. sheesh! H. "Cecil Moore" wrote in message ... Fred W4JLE wrote: I would disagree with your statement about SWR being absorbed in the source. The reflected wave is rereflected and aside from losses caused by the 2 way trip is reradiated. Reflected current flowing into the final amp can superpose in phase with the forward current and, without protection circuitry, cause the final amp to exceed its dissipation rating. Another possibility is when the reflected voltage superposes in phase with the forward voltage, and without protection circuitry, exceeds the voltage rating of the final. If all reflected power was always re-reflected, there would be no need for protection circuitry. The generated power is *defined* as the forward power minus the reflected power. That does NOT mean that the reflected power is 100% re-reflected. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#2
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H. Adam Stevens, NQ5H wrote:
One more time. It was a WORST CASE calculation which placed an upper bound on the possible loss from operating into a 1.7:1 SWR as opposed to a 1:1 SWR. In practice most of the power is eventually radiated. sheesh! H. Please give us the conditions (cable Z0, load Z, or whatever you need) that cause this "worst case" to occur. Roy Lewallen, W7EL |
#3
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![]() "Roy Lewallen" wrote in message ... H. Adam Stevens, NQ5H wrote: One more time. It was a WORST CASE calculation which placed an upper bound on the possible loss from operating into a 1.7:1 SWR as opposed to a 1:1 SWR. In practice most of the power is eventually radiated. sheesh! H. Please give us the conditions (cable Z0, load Z, or whatever you need) that cause this "worst case" to occur. Roy Lewallen, W7EL See other post. |
#4
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H. Adam Stevens, NQ5H wrote:
One more time. It was a WORST CASE calculation which placed an upper bound on the possible loss from operating into a 1.7:1 SWR as opposed to a 1:1 SWR. In practice most of the power is eventually radiated. As Roy, W7EL, previously indicated: Power reflection coefficient: rho^2 = [(SWR-1)/(SWR+1)]^2 = 0.067 = Pref/Pfor 1-rho^2 = 0.933 = 93.3% forward power delivered to the load 93.3 watts is 0.3 dB down from 100 watts. The log of the ratio of two SWRs doesn't seem to have much meaning. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#5
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It's called db, Cecil.
"Cecil Moore" wrote in message ... H. Adam Stevens, NQ5H wrote: One more time. It was a WORST CASE calculation which placed an upper bound on the possible loss from operating into a 1.7:1 SWR as opposed to a 1:1 SWR. In practice most of the power is eventually radiated. As Roy, W7EL, previously indicated: Power reflection coefficient: rho^2 = [(SWR-1)/(SWR+1)]^2 = 0.067 = Pref/Pfor 1-rho^2 = 0.933 = 93.3% forward power delivered to the load 93.3 watts is 0.3 dB down from 100 watts. The log of the ratio of two SWRs doesn't seem to have much meaning. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#6
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H. Adam Stevens, NQ5H wrote:
"Cecil Moore" wrote: The log of the ratio of two SWRs doesn't seem to have much meaning. It's called db, Cecil. The IEEE Dictionary says the ratio of power, voltage, and current can be expressed in dB. It specifically states that dB can only be related to power ratios or to parameters that are proportional to the square root of power ratios. SWR1 = [SQRT(Pfor1)+SQRT(Pref1)]/[SQRT(Pfor1)-SQRT(Pref1)] SWR2 = [SQRT(Pfor2)+SQRT(Pref2)]/[SQRT(Pfor2)-SQRT(Pref2)] The ratio of two SWRs will not reduce to a power ratio or to the square root of a power ratio. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#7
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Yes, SWR is a dimensionless quantity. dB is, as far as I know, defined
only for power, voltage and current ratios, as the IEEE Dictionary implies. Since it's defined differently for power than for voltage or current (so that an increase or reduction in one quantity represents the same number of dB increase or decrease in the other), anyone using it for something else would have to clarify how it would be defined in that context. Roy Lewallen, W7EL Cecil Moore wrote: H. Adam Stevens, NQ5H wrote: "Cecil Moore" wrote: The log of the ratio of two SWRs doesn't seem to have much meaning. It's called db, Cecil. The IEEE Dictionary says the ratio of power, voltage, and current can be expressed in dB. It specifically states that dB can only be related to power ratios or to parameters that are proportional to the square root of power ratios. SWR1 = [SQRT(Pfor1)+SQRT(Pref1)]/[SQRT(Pfor1)-SQRT(Pref1)] SWR2 = [SQRT(Pfor2)+SQRT(Pref2)]/[SQRT(Pfor2)-SQRT(Pref2)] The ratio of two SWRs will not reduce to a power ratio or to the square root of a power ratio. |
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