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#1
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![]() Cecil Moore wrote: Jim Kelley wrote: One should also carefully consider the more interesting variation of the problem: an open transmission line. In the steady state we have 100 watts forward, 100 watts reflected, 200 Joules in the line, and 0 watts being sourced by the generator. :-) Expanding on my earlier response - For the first two seconds, the source doesn't know it is looking into an open transmission line so a 100 watt source would faithfully output 200 joules into a one second long open circuit transmission line. That 200 joules cannot be destroyed. Is it mere coincidence that the forward and reflected waves are 100 joules/sec*(one second), exactly equal to the 200 joules supplied by the source? But you're missing, or trying to circumvent, the most interesting aspect of the problem. It's the one which highlights the very core of our disagreement. The energy stored in the line, remains stored in the line as long as steady state is maintained without a single Joule of additional energy moving into or out of the line. To me, this illustrates clearly how the fields at the impedance interfaces of a matching transformer can be maintained without requiring multiple rereflections of energy. I'm hoping some day you'll see it too. 73, ac6xg |
#2
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On Thu, 25 May 2006 22:04:12 GMT, Cecil Moore
wrote: But what about the people who say there's no energy in the reflected wave? Reckon how they sweep all those joules, whose energy must be conserved, under the rug? :-) with a jouler's brush? -- 73 for now Buck N4PGW |
#3
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Buck wrote:
Cecil Moore wrote: But what about the people who say there's no energy in the reflected wave? Reckon how they sweep all those joules, whose energy must be conserved, under the rug? :-) with a jouler's brush? All kidding aside, whatever number of joules of energy are required to support the forward power and reflected power is provided by the source during the transient condition following power up. If the source power is 100 watts, the forward power is 200 watts, the reflected power is 100 watts, and the load power is 100 watts, all the joules per second needed to support that forward and reflected power was supplied by the source before steady-state was reached. Anything else would violate the conservation of energy principle. This is easily proven using a one second long lossless transmission line as a conceptual training aid for the uninitiated. -- 73, Cecil http://www.qsl.net/w5dxp |
#4
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On Fri, 26 May 2006 03:16:38 GMT, Cecil Moore
wrote: If the source power is 100 watts, the forward power is 200 watts, the reflected power is 100 watts, and the load power is 100 watts, all the joules per second needed to support that forward and reflected power was supplied by the source before steady-state was reached. Anything else would violate the conservation of energy principle. This is easily proven using a one second long lossless transmission line as a conceptual training aid for the uninitiated. I gathered that from an earlier post, but I think the confusion comes in the second second, doesn't it? 100 watts of power is generated from the generator for two seconds. the first second, 100 watts travels to the antenna and only 100 watts is in the transmission line. Then for the second second, 100 forward watts is moving towards the antenna and 50 reflected watts are returning to the transmitter for a total of 150 watts in the transmission line? Of course, since the transmitter isn't matched to the antenna, the reflected power is reflected again for 25 watts being reflected back to the antenna bringing the power from 100 forward watts to 125 watts (the reason power meters go up in wattage when SWR rises) thus the antenna reflects 62.5 watts which adds to the 125 for a total of 187.5 watts in the transmission line. Sooner or later one will have a meltdown that will make Chernoble look like a firecracker compared to a fireworks display. lol -- 73 for now Buck N4PGW |
#5
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Richard,
I'm pretty sure steady state isn't achieved in that short a time when there are significant reflections on a line that long. Consider this. Initially, forward power from a 100 Joule per second source is, naturally, just 100 Joules per second. After one second, (the first second in particular), there should be 100 Joules on the line. It follows that the initial reflection would be 50 watts. When we assume that everything is re-reflected from the source, then at two seconds the forward power at the front of the line would be 150 watts. At four seconds, 175 watts; six seconds, 187.5; eight seconds, 193.75, and so on. When the number finally reaches 200 Joules per second at the load, the reflected power would have become 100 Joules per second back at the source one second earlier. At that point we can multiply the sum of forward and reflected power by the length of the line in seconds and gleefully announce that 300 Joules are being/have been stored in/on/at the xmission line. 73, ac6xg Richard Harrison wrote: I`ll speculate that after one second, 200 joules are contained in the forward wave on that line. Then, after two seconds, another 100 joules has been reflected back toward the line feedpoint where it opposes growth of power input to the line. Total joules on the line is 300. Forward power minus the reflected power equals 100 watts being supplied by the generator to the load with 200 watts forward power and 100 watts reflrcted power in the line. Best regards, Richard Harrison, KB5WZI |
#6
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"Jim Kelley" wrote:
I'm pretty sure steady state isn't achieved in that short a time when there are significant reflections on a line that long. I'm glad you brought that up. Here is the EXCEL spread sheet for that same signal generator equipped with an auto-tuner. You are right in that it takes a longer time to achieve steady-state but everything becomes completely clear after 30 seconds and the results are exactly the same (using a 100 watt signal generator). http://www.qsl.net/w5dxp/1secsgat.gif -- 73, Cecil, W5DXP |
#7
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Very nice, Cecil. It would be also
useful to know how you obtained these numbers. 73, ac6xg Cecil Moore wrote: "Jim Kelley" wrote: I'm pretty sure steady state isn't achieved in that short a time when there are significant reflections on a line that long. I'm glad you brought that up. Here is the EXCEL spread sheet for that same signal generator equipped with an auto-tuner. You are right in that it takes a longer time to achieve steady-state but everything becomes completely clear after 30 seconds and the results are exactly the same (using a 100 watt signal generator). http://www.qsl.net/w5dxp/1secsgat.gif -- 73, Cecil, W5DXP |
#8
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"Jim Kelley" wrote:
Very nice, Cecil. It would be also useful to know how you obtained these numbers. The same way you obtained your numbers, Jim, when you said: It follows that the initial reflection would be 50 watts. When we assume that everything is re-reflected from the source, then at two seconds the forward power at the front of the line would be 150 watts. At four seconds, 175 watts; six seconds, 187.5; eight seconds, 193.75, and so on. Please note that your numbers and mine agree exactly. Also please note that I posted those numbers days ago on qrz.com under a brainteaser thread. I have the EXCEL file if you or anyone else would like to have it. (In a one second long transmission line, when the load reflects 50 watts, it has essentially reflected 50 joules because nothing changes during the following second.) In fact, I'll present a challenge for you and everyone else. In any one second long lossless transmission line with any forward power and any reflected power, I defy you to come up with an example where the number of joules stored in the line is not equal to the forward power plus the reflected power. Those joules are the joules sourced by the generator that have not made it to the load. The conservation of energy principle will have it no other way. The laws of physics win once again. -- 73, Cecil http://www.qsl.net/w5dxp |
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