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#11
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On 16 Nov, 07:06, (Richard Harrison) wrote:
Art wrote: "I am trying to deduce an alternative to the thinking current can hurdle a capacitor and retain its time variation." An early demonstration of electroostatic repulsion was via an instrument called the electroscope. Put a charge on its plates and it opened like a book. It proved like charges repelled and that repulsion was proportional to charge. From that it can be imagined that if you put a charge on one insulated plate and like charges on an insulated plate nearby have an avenue of escape to the outside world, you may have produced a capacitor useful for ac coupling or bypass. It isn`t a hurdle. It is a device capable of a displacement current which blocks dc but passes ac. It`s a device formerly called a condenser, now called a capacitor. Best regards, Richard Harrison, KB5WZI I assume you are not trying to be funny and are using the dictates of Terman to make a point. So I will respond. The antenna am referring to consists of a tank circuit where the distributed capacitance is the capacitor in the circuit. The capacitor stores energy from the time varying current and then releases the energy when the terminals are shorted. This energy is not released with the same properties that the capacitor but in a similar way that a battery does when the terminals are shorted. Thus the time variant that one sees on the energy release is not the same as the time varient possesed when delivered to the capacitor but I could be in error. I have most of Termans books so if you can point to a section that confirms your position and contradicts mine I would apreciate if you would share that section with me. Regards Art |
#12
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On 16 Nov, 07:06, (Richard Harrison) wrote:
Art wrote: "I am trying to deduce an alternative to the thinking current can hurdle a capacitor and retain its time variation." An early demonstration of electroostatic repulsion was via an instrument called the electroscope. Put a charge on its plates and it opened like a book. It proved like charges repelled and that repulsion was proportional to charge. From that it can be imagined that if you put a charge on one insulated plate and like charges on an insulated plate nearby have an avenue of escape to the outside world, you may have produced a capacitor useful for ac coupling or bypass. It isn`t a hurdle. It is a device capable of a displacement current which blocks dc but passes ac. It`s a device formerly called a condenser, now called a capacitor. Best regards, Richard Harrison, KB5WZI What you must understand is t5he circuit that constitutes a capacitor part of which is a resister that is seen in parallel. So yes, a portion of energy can bypass the capacitor. However the time varient that one must measure is at best, a superinposed expellation of energy from the capacitor which changes the original time varient required for radiation. Cecil makes the point he can measure the current along the radiator, but in fact he has a measuring problem by what he is using to measure current with respect to time. Regards Art |
#13
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Art wrote:
"What you nust understand is the circuit that constitutes a capacitor part of which is a resistor that is seen in parallel." That would be equivalent to a leaky capacitor. There is no time delay in a pure resistor. Its voltage drop is in-phase with the current through it. I don`t have a complete equivalent circuit in mind. Best regards, Richard Harrison, KB5WZI |
#14
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On 17 Nov, 16:57, (Richard Harrison) wrote:
Art wrote: "What you nust understand is the circuit that constitutes a capacitor part of which is a resistor that is seen in parallel." That would be equivalent to a leaky capacitor. There is no time delay in a pure resistor. Its voltage drop is in-phase with the current through it. I don`t have a complete equivalent circuit in mind. Best regards, Richard Harrison, KB5WZI Right. The the sino soidal shape will go thru with its time varient which is the condition applied by programmers for EVERY segment. But that is only half the story for a TANK circuit. The capacitor stores energy just like charging a battery, it will not NOT thru. When the situation is right the capacitor/battery releases all its energy like connecting a terminal to ground or shorting it.This allows the energy to flow in dc format at a rate decides by its time constant ot time varient required for radiation. This energy release is imposed on the leakage current thus forming a new time varient rquirede for radiation. Thus at different segment points the time varient is not a reflection of a sino soidal leakage current but the summation of that PLUS the capacitor dicharge time constant. Look up a tank circuit and all will become clear when you follow the phase changes of the voltage and the current first in forward direction and then the reverse direction. Regards Art |
#15
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Art wrote:
"When the situation is right the capacitor/battery releases all its energy like connecting a terminal to ground or shorting it." Not quite. The inductance, whose reactance equals the capacitance`s reactance at resonance, opposes any change in current. It only allows current to grow exponentially during the cycle by simultaneously generating a counter emf to oppose the current imposed on the inductance from outside. The impressed current will lag the voltage across a pure inductance by 90 degrees. The voltage builds across a pure capacitance with a 90 degree lag of the current through the capacitance. This is basic electricity 101. Best regards, Richard Harrison, KB5WZI |
#16
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On 18 Nov, 19:00, (Richard Harrison) wrote:
Art wrote: "When the situation is right the capacitor/battery releases all its energy like connecting a terminal to ground or shorting it." Not quite. The inductance, whose reactance equals the capacitance`s reactance at resonance, opposes any change in current. It only allows current to grow exponentially during the cycle by simultaneously generating a counter emf to oppose the current imposed on the inductance from outside. The impressed current will lag the voltage across a pure inductance by 90 degrees. The voltage builds across a pure capacitance with a 90 degree lag of the current through the capacitance. This is basic electricity 101. Maybe in America! Since it is resonant then it is a tank circuit where you have to rethink the 90 degree lag Art Best regards, Richard Harrison, KB5WZI |
#17
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Richard Harrison wrote:
Art wrote: "When the situation is right the capacitor/battery releases all its energy like connecting a terminal to ground or shorting it." Not quite. The inductance, whose reactance equals the capacitance`s reactance at resonance, opposes any change in current. It only allows current to grow exponentially during the cycle by simultaneously generating a counter emf to oppose the current imposed on the inductance from outside. The impressed current will lag the voltage across a pure inductance by 90 degrees. The voltage builds across a pure capacitance with a 90 degree lag of the current through the capacitance. This is basic electricity 101. A little too basic, I'm afraid. The 90 degree current lag applies only to a steady state sinusoidal voltage. For other waveforms (like ones you'd get connecting batteries or capacitors) you have to resort to the more general time relationship v = L * di/dt. (Or, if inductance is changing with time, v = d/dt (L * i).) Roy Lewallen, W7EL |
#18
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Roy Lewallen wrote:
"S little too basic, I`m afraid. The 90 degree current lag applies only to a steady state sinusoidal voltage." A steady state sinusoidal voltage is exactly what I would expect on a resonant antenna in the absence of modulation when a carrier has been applied to the antenna for a short but not too short period of time. Best regards, Richard Harrison, KB5WZI |
#19
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On 20 Nov, 00:07, "Jimmie D" wrote:
"Richard Harrison" wrote in message ... Roy Lewallen wrote: "S little too basic, I`m afraid. The 90 degree current lag applies only to a steady state sinusoidal voltage." A steady state sinusoidal voltage is exactly what I would expect on a resonant antenna in the absence of modulation when a carrier has been applied to the antenna for a short but not too short period of time. Best regards, Richard Harrison, KB5WZI The peril of trying to actualy answer Art's questions. Richard can be excused for making this error. This is the same fundamental reason that Ted Hart, Professor Underhill and lately Vincent failed to design a radiator that actually works efficiently. And to this day they and the ham world are totally oblivious as to why. This is a direct effect of memorizing facts in college without regard to first principles to obtain a degree. Pretty much all examinations I had to take in Europe demanded a response to a question using only first principles to avoid failure. Where failure in any subject during the year required a repeat of all subjects taken that year, even those where a pass was obtained, where one has to be successfull, or thrown out! Art Unwin KB9MZ....xg (UK) |
#20
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Art wrote:
"Richard can be excused for making this error." Prove I erred! Put a sine wave in an antenna and you get a sine wave out. Kraus says: "The currents on the transmission line flow out on the antenna and end there, but the fields associated with them keep on going." Art in a previous posting said I should quote "Lady Chatterley`s Lover" as people were tiring of Terman. I read it before it was even printed in the U.K. (1960) but this is an antenna newsgroup and Terman is more appropriate. If people want something other than Terman, he gives a terrific bibliography at the bottom of page 864 in his 1955 opus. Art also said in a previous posting that Terman did not credit Maxwell with defining radiation. Let me put the lie to that. On page 864 of his 1955 opus, Terman writes: "The laws governing such radiation are obtained by using Maxwell`s equations to express the fields associated with the wire; when this is done there is found to be a component, termed the radiated field having a strength that varies inversely with the distance." Best regards, Richard Harrison, KB5WZI |
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