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#2
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#3
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On Mon, 15 Oct 2018 10:43:09 -0400, Ralph Mowery
wrote: In article , says... Consider a 2 tone signal at the 9MHz USB IF, comprising 900Hz and 1300Hz tones. The components will be 9.0009 and 9.0013 Subtract the VFO at 5.5MHz: 9.0009 - 5.5 = 3.50009 9.0013 - 5.5 = 3.50013 Nothing has been inverted. The 80m signal is still upper sideband. GB3BERNIE Ralph is posting from rec.radio.amateur.antenna and google groups strips the crosspost - without a repeater, he's not going to answer you. Try it the other way around and use a ssb generated at 5 mhz and the vfo at 9 mhz. It is difficult for me to remember which was used for the vfo and ssb generator. I'm fairly sure the SSB was generated at 9MHz. Googling for a reminder, I find a large number of 9MHz sideband crystal filters available, while nothing for 5MHz. Presumably, the 9MHz sideband crystal filter is use for both the receiver IF filter and in the exciter SSB generator to strip off the unwanted sideband. https://www.google.com/search?q=9+mhz+crystal+filter -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#4
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On 16/10/2018 08:08, Jeff wrote:
I'm fairly sure the SSB was generated at 9MHz. Googling for a reminder, I find a large number of 9MHz sideband crystal filters available, while nothing for 5MHz. Presumably, the 9MHz sideband crystal filter is use for both the receiver IF filter and in the exciter SSB generator to strip off the unwanted sideband. You are correct 9MHzwas a common IF for both tx & rx. A common way of generating both usb and lsb was to have 2 switched crystals with frequencies just above and below 9MHz in the oscillator, feeding a balanced mixer, before the xtal filter, and switch depending on which sideband you required. Is there a mathematician on here that can explain the maths of sideband inversion/retention? -- Spike "Nearly all men can stand adversity, but if you want to test a man's character, give him an internet group to manage" |
#5
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On 16/10/2018 09:14, Jeff wrote:
A common way of generating both usb and lsb was to have 2 switched crystals with frequencies just above and below 9MHz in the oscillator, feeding a balanced mixer, before the xtal filter, and switch depending on which sideband you required. Is there a mathematician on here that can explain the maths of sideband inversion/retention? No inversion is required with this method. If you feed a ~9MHz signal and audio into a balanced mixer the output will be both sidebands plus a suppressed carrier. Your xtal filter is ~2.4kHz wide centred on 9MHz, so if you move the frequency of the ~9Mhz signal (switch a crystal) going into the balanced mixer either above or below 9MHz you can select which side band goes through your filter. Simples. Wasn't a similar system used in the Yaesu FT-200 (9MHz IF, 5 MHz VFO)? IIRC the set had a NORM/INV sideband switch. -- Spike "Nearly all men can stand adversity, but if you want to test a man's character, give him an internet group to manage" |
#6
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On Tue, 16 Oct 2018, Spike wrote:
On 16/10/2018 09:14, Jeff wrote: A common way of generating both usb and lsb was to have 2 switched crystals with frequencies just above and below 9MHz in the oscillator, feeding a balanced mixer, before the xtal filter, and switch depending on which sideband you required. Is there a mathematician on here that can explain the maths of sideband inversion/retention? No inversion is required with this method. If you feed a ~9MHz signal and audio into a balanced mixer the output will be both sidebands plus a suppressed carrier. Your xtal filter is ~2.4kHz wide centred on 9MHz, so if you move the frequency of the ~9Mhz signal (switch a crystal) going into the balanced mixer either above or below 9MHz you can select which side band goes through your filter. Simples. Wasn't a similar system used in the Yaesu FT-200 (9MHz IF, 5 MHz VFO)? IIRC the set had a NORM/INV sideband switch. That wasn't uncommon, the conversion scheme allowing for the "default" sideband to be one switch position, so the only time you needed to switch sidebands was if you needed the "wrong" sideband". Michael |
#7
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On Mon, 15 Oct 2018, Ralph Mowery wrote:
In article , says... Consider a 2 tone signal at the 9MHz USB IF, comprising 900Hz and 1300Hz tones. The components will be 9.0009 and 9.0013 Subtract the VFO at 5.5MHz: 9.0009 - 5.5 = 3.50009 9.0013 - 5.5 = 3.50013 Nothing has been inverted. The 80m signal is still upper sideband. GB3BERNIE Ralph is posting from rec.radio.amateur.antenna and google groups strips the crosspost - without a repeater, he's not going to answer you. Try it the other way around and use a ssb generated at 5 mhz and the vfo at 9 mhz. It is difficult for me to remember which was used for the vfo and ssb generator. I think the origins are with a 5MHz IF. This has come up before, the same explanation given, yet if I wasn't sick and did the figuring, I think it's that the 9Mhz one wasn't it, but a 5MHz IF does do the inversion. But I can't remember what rig had a 5MHz IF. THey existed, but the ones I can think of came later. So maybe it was a phasing rig, but which did conversion rather than generate the SSB signal on the signal frequency. The Central Electronics 10 transmitter maybe, reinforced by their later 20, but I havent' checked. There was a popular rig in QST that worked out the figures so the low IF was converted up to an intermediate frequency with one crystal, one caused no inversion, but if you multiplied the crystal frequency by three, it was high side and inverted the sideband. But since it did both sidebands, it wouldn't have been a standard for LSB below a certain frequency, There were early ssb rigs that didn't have selectable sideband, they just picked conversion frequency properly so below 10MHz, it was LSB, and above was USB. Since nobody used the opposite sideband, no need for a switch. Michael |
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