Reply
 
LinkBack Thread Tools Search this Thread Display Modes
  #1   Report Post  
Old February 9th 05, 05:52 PM
John
 
Posts: n/a
Default Angle of Radiation

Can someone tell me please an easy way to calculate the optimum angle of
radiation from a transmitting antenna over a given path on the HF bands
(160m - 10m)?

OK, I guess its all to do with the height of the reflective layer in play
and the distance of the QSO but I'd really appreciate some clues as to how
to work this out.

Thanks

John



  #2   Report Post  
Old February 7th 05, 06:04 PM
Richard Clark
 
Posts: n/a
Default

On Wed, 09 Feb 2005 17:52:37 GMT, "John" wrote:
Can someone tell me please an easy way to calculate the optimum angle of
radiation from a transmitting antenna over a given path on the HF bands
(160m - 10m)?


Hi John

Use a propagation modeler and tailor the antenna characteristics to
observe the results.

73's
Richard Clark, KB7QHC
  #3   Report Post  
Old February 9th 05, 06:37 PM
Caveat Lector
 
Posts: n/a
Default

Maybe check ON4UN's book -- "Low Band DXing"
He has info on this
Too lengthy to quote here

--
Caveat Lector (Reader Beware)
Help The New Hams
Someone Helped You
Or did You Forget That ?



"John" wrote in message
...
Can someone tell me please an easy way to calculate the optimum angle of
radiation from a transmitting antenna over a given path on the HF bands
(160m - 10m)?

OK, I guess its all to do with the height of the reflective layer in play
and the distance of the QSO but I'd really appreciate some clues as to how
to work this out.

Thanks

John





  #4   Report Post  
Old February 9th 05, 07:35 PM
Roy Lewallen
 
Posts: n/a
Default

Get W6ELProp - it's easy to use, and free. http://www.qsl.net/w6elprop/.

Roy Lewallen, W7EL

John wrote:
Can someone tell me please an easy way to calculate the optimum angle of
radiation from a transmitting antenna over a given path on the HF bands
(160m - 10m)?

OK, I guess its all to do with the height of the reflective layer in play
and the distance of the QSO but I'd really appreciate some clues as to how
to work this out.

Thanks

John



  #5   Report Post  
Old February 9th 05, 08:35 PM
Reg Edwards
 
Posts: n/a
Default

The elevation angle of a radio wave is not related to antenna construction.

It is calculated by trigonometry and is geometrically related to the
distance between two points on the Earth's surface, the height of the
ionospheric reflecting layers involved, and the number of hops.

If a radio wave leaves the Earth at one end of the path and returns to Earth
at the other end, then the elevation angles of the path taken are the same
at both ends. And the same in the other direction. (To forestall
nitpickers let it be said things can vary around averages.)

The optimum angle at which to point a radio antenna, either for transmit or
receive, is obviously the same as the elevation angle of the radio path.

BUT NO AMOUNT OF WAVING THE ANTENNA ABOUT WILL AFFECT THE ELEVATION ANGLE OF
THE RADIO PATH.

For given points on the Earth's surface, height of reflecting layer, and
number of hops, the angle of elevation of the radio path is fixed.

The angle at which the radiation from an antenna is a maximum is an entirely
different matter.

Calculation of a path elevation angle on a curved Earth not very difficult
but is a little too complicated to be written here.

Up to 1500 groundpath miles the Earth can be considered to be flat. Trig
calculation is then schoolkids stuff.

Full formulae can be found in maths books under "Spherical Trigonometry" or
in practical radio engineering books.

Calculations can be interesting but are invariably roughly approximate
because layer height involves guesswork. And by the time you've finished a
calculation the height has shifted. Or the number of hops has changed from 2
to 3. The only things which remain static are your own latitude and
longitude.

To calculate propagation statistics of one and two hop radio paths,
including elevation angles, download simple program TWOHOPS in a few seconds
from website below and run immediately.
----
.................................................. ..........
Regards from Reg, G4FGQ
For Free Radio Design Software go to
http://www.btinternet.com/~g4fgq.regp
.................................................. ..........




  #6   Report Post  
Old February 9th 05, 11:46 PM
W9DMK
 
Posts: n/a
Default

On Wed, 9 Feb 2005 20:35:14 +0000 (UTC), "Reg Edwards"
wrote:

The elevation angle of a radio wave is not related to antenna construction.

It is calculated by trigonometry and is geometrically related to the
distance between two points on the Earth's surface, the height of the
ionospheric reflecting layers involved, and the number of hops.

If a radio wave leaves the Earth at one end of the path and returns to Earth
at the other end, then the elevation angles of the path taken are the same
at both ends. And the same in the other direction. (To forestall
nitpickers let it be said things can vary around averages.)

The optimum angle at which to point a radio antenna, either for transmit or
receive, is obviously the same as the elevation angle of the radio path.

BUT NO AMOUNT OF WAVING THE ANTENNA ABOUT WILL AFFECT THE ELEVATION ANGLE OF
THE RADIO PATH.

For given points on the Earth's surface, height of reflecting layer, and
number of hops, the angle of elevation of the radio path is fixed.

The angle at which the radiation from an antenna is a maximum is an entirely
different matter.

Calculation of a path elevation angle on a curved Earth not very difficult
but is a little too complicated to be written here.

Up to 1500 groundpath miles the Earth can be considered to be flat. Trig
calculation is then schoolkids stuff.

Full formulae can be found in maths books under "Spherical Trigonometry" or
in practical radio engineering books.

Calculations can be interesting but are invariably roughly approximate
because layer height involves guesswork. And by the time you've finished a
calculation the height has shifted. Or the number of hops has changed from 2
to 3. The only things which remain static are your own latitude and
longitude.

To calculate propagation statistics of one and two hop radio paths,
including elevation angles, download simple program TWOHOPS in a few seconds
from website below and run immediately.


The original poster, John, had already indicated the answer to his own
question - but Reg was the only one who recognized that and had the
correct follow up. Congrats, Reg.


Bob, W9DMK, Dahlgren, VA
Replace "nobody" with my callsign for e-mail
http://www.qsl.net/w9dmk
http://zaffora/f2o.org/W9DMK/W9dmk.html

  #7   Report Post  
Old February 12th 05, 01:43 AM
Reg Edwards
 
Posts: n/a
Default


"Reg Edwards" wrote
The elevation angle of a radio wave is not related to antenna

construction.

It is calculated by trigonometry and is geometrically related to the
distance between two points on the Earth's surface, the height of the
ionospheric reflecting layers involved, and the number of hops.

If a radio wave leaves the Earth at one end of the path and returns to

Earth
at the other end, then the elevation angles of the path taken are the same
at both ends. And the same in the other direction. (To forestall
nitpickers let it be said things can vary around averages.)

The optimum angle at which to point a radio antenna, either for transmit

or
receive, is obviously the same as the elevation angle of the radio path.

BUT NO AMOUNT OF WAVING THE ANTENNA ABOUT WILL AFFECT THE ELEVATION ANGLE

OF
THE RADIO PATH.

For given points on the Earth's surface, height of reflecting layer, and
number of hops, the angle of elevation of the radio path is fixed.

The angle at which the radiation from an antenna is a maximum is an

entirely
different matter.

Calculation of a path elevation angle on a curved Earth not very difficult
but is a little too complicated to be written here.

Up to 1500 groundpath miles the Earth can be considered to be flat. Trig
calculation is then schoolkids stuff.

Full formulae can be found in maths books under "Spherical Trigonometry"

or
in practical radio engineering books.

Calculations can be interesting but are invariably roughly approximate
because layer height involves guesswork. And by the time you've finished a
calculation the height has shifted. Or the number of hops has changed from

2
to 3. The only things which remain static are your own latitude and
longitude.

To calculate propagation statistics of one and two hop radio paths,
including elevation angles, download simple program TWOHOPS in a few

seconds
from website below and run immediately.
----
.................................................. .........
Regards from Reg, G4FGQ
For Free Radio Design Software go to
http://www.btinternet.com/~g4fgq.regp
.................................................. .........

=========================================

Why should my answer to the question be altogether different to everybody
else's? Especially as I'm right.
---
Reg.


  #8   Report Post  
Old February 16th 05, 12:43 AM
 
Posts: n/a
Default


"Reg Edwards" wrote in message
...

"Reg Edwards" wrote
The elevation angle of a radio wave is not related to antenna

construction.

It is calculated by trigonometry and is geometrically related to the
distance between two points on the Earth's surface, the height of the
ionospheric reflecting layers involved, and the number of hops.

If a radio wave leaves the Earth at one end of the path and returns to

Earth
at the other end, then the elevation angles of the path taken are the
same
at both ends. And the same in the other direction. (To forestall
nitpickers let it be said things can vary around averages.)




Reg.
You asre concentrating on things that you can do nothing about
i.e.the ionisphere and trivialising the things that you CAN do something
about
which is TOA, the subject of this thread.

If the transmitting station TOA is low enough to make the QSO in one hop
and the receiving station antenna has a higher take off angle that requires
exactly two hops to reply then the paths are NOT the same.
I would also doubt that the paths taken when being bent by the reflecting
layers
would be the same as the density is subject to change
.. The real discussion regarding TOA is to achieve a QSO
with one hop instead of two so as to cut down on travel losses and that is
where
the importance of TOA and associated angles that follow the +/- 3 db takes
place.
Regardless of the physical position of the antenna the elevation angle of
the radio wave
IS related to antenna construction.
Just a different view point Reg, the antenna I CAN do something about.
Natures actions
I can do NOTHING about except to have the correct equipment when good
conditions occur
and that is where TOA gains it importance.
In my designs I try to have the lowest contour of the bottom lobe even tho
it may mean
a loss of a db in gain at the actual TOA.and I do not concern myself with
the technical data
that your posting revolves about, which tho it may be interesting to some,
as I cannot change it
Nothing personal nor am I nitpicking
Cheers
Art





The optimum angle at which to point a radio antenna, either for transmit

or
receive, is obviously the same as the elevation angle of the radio path.

BUT NO AMOUNT OF WAVING THE ANTENNA ABOUT WILL AFFECT THE ELEVATION ANGLE

OF
THE RADIO PATH.

For given points on the Earth's surface, height of reflecting layer, and
number of hops, the angle of elevation of the radio path is fixed.

The angle at which the radiation from an antenna is a maximum is an

entirely
different matter.

Calculation of a path elevation angle on a curved Earth not very
difficult
but is a little too complicated to be written here.

Up to 1500 groundpath miles the Earth can be considered to be flat. Trig
calculation is then schoolkids stuff.

Full formulae can be found in maths books under "Spherical Trigonometry"

or
in practical radio engineering books.

Calculations can be interesting but are invariably roughly approximate
because layer height involves guesswork. And by the time you've finished
a
calculation the height has shifted. Or the number of hops has changed
from

2
to 3. The only things which remain static are your own latitude and
longitude.

To calculate propagation statistics of one and two hop radio paths,
including elevation angles, download simple program TWOHOPS in a few

seconds
from website below and run immediately.
----
.................................................. .........
Regards from Reg, G4FGQ
For Free Radio Design Software go to
http://www.btinternet.com/~g4fgq.regp
.................................................. .........

=========================================

Why should my answer to the question be altogether different to everybody
else's? Especially as I'm right.
---
Reg.




  #9   Report Post  
Old February 16th 05, 07:27 AM
Reg Edwards
 
Posts: n/a
Default

Aunwin, we are talking about two different things.

If I want to communicate (optimally) with another station it is important
that I know the direction and elevation angle at which to point my antenna
such that the radio beam preferentially returns to Earth in the vicinity of
the other station.

Direction is found from a map of the Earth's surface plus a magnetic
compass.

The ONLY way to find the elevation angle is to CALCULATE it from the ground
path distance between the two stations, the height of the reflecting layer,
and the number of hops along the path.

It's purely a matter of Spherical Geometry. It has nothing to do with where
your antenna happens to be pointing. Or even whether or not you have an
antenna.

All good radio engineers do it that way. Caculating formulae can be found in
practical radio engineering books. Eznec won't tell you.

Use simple program TWOHOPS to do common calculations. Results are as
accurate as the inevitably uncertain input data.
---
.................................................. ..........
Regards from Reg, G4FGQ
For Free Radio Design Software go to
http://www.btinternet.com/~g4fgq.regp
.................................................. ..........


  #10   Report Post  
Old February 16th 05, 05:49 PM
Richard Harrison
 
Posts: n/a
Default

Reg, G4FGQ wrote:
"It`s purely a matter of Spherical Geometry"

Edmund A. Laport agrees with Reg in his book "Radio Antenna
Engineering". On page 227 Ed writes:
"If, for example, the computed vertical beam angle for a one-hop circuit
uses 6 degrees at an azimuth of 332 degrees and the horizon in this
direction consisted of a mountain range with a height of 8 degrees, the
performance of the circuit would be greatly compromised by the
obstruction of the mountains. In such a case it might be better to work
this circuit with two hops. Then a vertical beam angle of 20 degrees can
be used instead, with adequate horizon clearance for the wave path. Or
if the circuit required 6 degrees for a two-hop circuit 5400 kilometers
long, with the same obstruction cited, one could change to a three-hop
circuit which for the same layer height would permit the use of a beam
at 14 degrees."

Best regards, Richard Harrison, KB5WZI



Reply
Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules

Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
Radiation angle vs turns count in a coil W4JLE Antenna 9 December 20th 04 09:35 PM
Electromagnetic radiation Mike Terry Shortwave 0 August 24th 04 10:23 PM
Serious radiation questin [email protected] Antenna 45 August 22nd 04 11:42 PM
The Apollo Hoax FAQ darla General 0 July 22nd 04 12:14 PM
Cardiod radiation pattern - 70 cm phased vertical dipoles Ray Gaschk Antenna 3 February 21st 04 12:26 AM


All times are GMT +1. The time now is 11:05 PM.

Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
Copyright ©2004-2025 RadioBanter.
The comments are property of their posters.
 

About Us

"It's about Radio"

 

Copyright © 2017