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#1
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![]() "Reg Edwards" wrote The elevation angle of a radio wave is not related to antenna construction. It is calculated by trigonometry and is geometrically related to the distance between two points on the Earth's surface, the height of the ionospheric reflecting layers involved, and the number of hops. If a radio wave leaves the Earth at one end of the path and returns to Earth at the other end, then the elevation angles of the path taken are the same at both ends. And the same in the other direction. (To forestall nitpickers let it be said things can vary around averages.) The optimum angle at which to point a radio antenna, either for transmit or receive, is obviously the same as the elevation angle of the radio path. BUT NO AMOUNT OF WAVING THE ANTENNA ABOUT WILL AFFECT THE ELEVATION ANGLE OF THE RADIO PATH. For given points on the Earth's surface, height of reflecting layer, and number of hops, the angle of elevation of the radio path is fixed. The angle at which the radiation from an antenna is a maximum is an entirely different matter. Calculation of a path elevation angle on a curved Earth not very difficult but is a little too complicated to be written here. Up to 1500 groundpath miles the Earth can be considered to be flat. Trig calculation is then schoolkids stuff. Full formulae can be found in maths books under "Spherical Trigonometry" or in practical radio engineering books. Calculations can be interesting but are invariably roughly approximate because layer height involves guesswork. And by the time you've finished a calculation the height has shifted. Or the number of hops has changed from 2 to 3. The only things which remain static are your own latitude and longitude. To calculate propagation statistics of one and two hop radio paths, including elevation angles, download simple program TWOHOPS in a few seconds from website below and run immediately. ---- .................................................. ......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. ......... ========================================= Why should my answer to the question be altogether different to everybody else's? Especially as I'm right. --- Reg. |
#2
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![]() "Reg Edwards" wrote in message ... "Reg Edwards" wrote The elevation angle of a radio wave is not related to antenna construction. It is calculated by trigonometry and is geometrically related to the distance between two points on the Earth's surface, the height of the ionospheric reflecting layers involved, and the number of hops. If a radio wave leaves the Earth at one end of the path and returns to Earth at the other end, then the elevation angles of the path taken are the same at both ends. And the same in the other direction. (To forestall nitpickers let it be said things can vary around averages.) Reg. You asre concentrating on things that you can do nothing about i.e.the ionisphere and trivialising the things that you CAN do something about which is TOA, the subject of this thread. If the transmitting station TOA is low enough to make the QSO in one hop and the receiving station antenna has a higher take off angle that requires exactly two hops to reply then the paths are NOT the same. I would also doubt that the paths taken when being bent by the reflecting layers would be the same as the density is subject to change .. The real discussion regarding TOA is to achieve a QSO with one hop instead of two so as to cut down on travel losses and that is where the importance of TOA and associated angles that follow the +/- 3 db takes place. Regardless of the physical position of the antenna the elevation angle of the radio wave IS related to antenna construction. Just a different view point Reg, the antenna I CAN do something about. Natures actions I can do NOTHING about except to have the correct equipment when good conditions occur and that is where TOA gains it importance. In my designs I try to have the lowest contour of the bottom lobe even tho it may mean a loss of a db in gain at the actual TOA.and I do not concern myself with the technical data that your posting revolves about, which tho it may be interesting to some, as I cannot change it Nothing personal nor am I nitpicking Cheers Art The optimum angle at which to point a radio antenna, either for transmit or receive, is obviously the same as the elevation angle of the radio path. BUT NO AMOUNT OF WAVING THE ANTENNA ABOUT WILL AFFECT THE ELEVATION ANGLE OF THE RADIO PATH. For given points on the Earth's surface, height of reflecting layer, and number of hops, the angle of elevation of the radio path is fixed. The angle at which the radiation from an antenna is a maximum is an entirely different matter. Calculation of a path elevation angle on a curved Earth not very difficult but is a little too complicated to be written here. Up to 1500 groundpath miles the Earth can be considered to be flat. Trig calculation is then schoolkids stuff. Full formulae can be found in maths books under "Spherical Trigonometry" or in practical radio engineering books. Calculations can be interesting but are invariably roughly approximate because layer height involves guesswork. And by the time you've finished a calculation the height has shifted. Or the number of hops has changed from 2 to 3. The only things which remain static are your own latitude and longitude. To calculate propagation statistics of one and two hop radio paths, including elevation angles, download simple program TWOHOPS in a few seconds from website below and run immediately. ---- .................................................. ......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. ......... ========================================= Why should my answer to the question be altogether different to everybody else's? Especially as I'm right. --- Reg. |
#3
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Aunwin, we are talking about two different things.
If I want to communicate (optimally) with another station it is important that I know the direction and elevation angle at which to point my antenna such that the radio beam preferentially returns to Earth in the vicinity of the other station. Direction is found from a map of the Earth's surface plus a magnetic compass. The ONLY way to find the elevation angle is to CALCULATE it from the ground path distance between the two stations, the height of the reflecting layer, and the number of hops along the path. It's purely a matter of Spherical Geometry. It has nothing to do with where your antenna happens to be pointing. Or even whether or not you have an antenna. All good radio engineers do it that way. Caculating formulae can be found in practical radio engineering books. Eznec won't tell you. Use simple program TWOHOPS to do common calculations. Results are as accurate as the inevitably uncertain input data. --- .................................................. .......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. .......... |
#4
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Reg, G4FGQ wrote:
"It`s purely a matter of Spherical Geometry" Edmund A. Laport agrees with Reg in his book "Radio Antenna Engineering". On page 227 Ed writes: "If, for example, the computed vertical beam angle for a one-hop circuit uses 6 degrees at an azimuth of 332 degrees and the horizon in this direction consisted of a mountain range with a height of 8 degrees, the performance of the circuit would be greatly compromised by the obstruction of the mountains. In such a case it might be better to work this circuit with two hops. Then a vertical beam angle of 20 degrees can be used instead, with adequate horizon clearance for the wave path. Or if the circuit required 6 degrees for a two-hop circuit 5400 kilometers long, with the same obstruction cited, one could change to a three-hop circuit which for the same layer height would permit the use of a beam at 14 degrees." Best regards, Richard Harrison, KB5WZI |
#5
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![]() "Richard Harrison" wrote in message ... Reg, G4FGQ wrote: "It`s purely a matter of Spherical Geometry" Edmund A. Laport agrees with Reg in his book "Radio Antenna Engineering". On page 227 Ed writes: "If, for example, the computed vertical beam angle for a one-hop circuit uses 6 degrees at an azimuth of 332 degrees and the horizon in this direction consisted of a mountain range with a height of 8 degrees, the performance of the circuit would be greatly compromised by the obstruction of the mountains. In such a case it might be better to work this circuit with two hops. Then a vertical beam angle of 20 degrees can be used instead, with adequate horizon clearance for the wave path. Or if the circuit required 6 degrees for a two-hop circuit 5400 kilometers long, with the same obstruction cited, one could change to a three-hop circuit which for the same layer height would permit the use of a beam at 14 degrees." Best regards, Richard Harrison, KB5WZI OR ....... you take advantage of diffraction abilities of physical parts such as mountain edges or other physical parts that can deflect the rays AFTER it leaves the FEED POINT which does NOT exclude an antenna array of which the feed point is part. The point of confusion emanates from.calculating hop distance on the basis of a :"standard:". TOA The "magic" of a stacked antenna exposes the difference :that occurs with a different TOA. I suppose you could use Reg's program so that when the ideal conditions do occur maybe after several hours of waiting , when one can say that the upper layers are now exactly such or such a height and the assumption used in formulating the program are now correct. The fact is that ham radio is about formulating an array that will provide the hop distance required by the operator since that is something he can change. I am quite sure that LaPorte does NOT say that no amount of shaking an antenna can change the hop distance which is what TOA is all about and the subject of this thread. Maybe we need another thread to clarify the question that Reg and yourself are apparently addressing. Art |
#6
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Reg, G4FGQ wrote:
"It`s purely a matter of Spherical Geometry." The ARRL agrees with Reg. The 19th edition of the ARRL Antenna Book on page 23-24 gives path distance versus vertical wave angle for a one-hop transmission using the F2 layer in Fig 23. Of course these are only based on a variable reflecting layer height. For 500 miles, 40 to 70 degrees. For 1000 miles, 20 to 35 degrees. For 1500 miles, 10 to 22 degrees. For 2000 miles, 4 to 15 degrees. For 2500 miles, less than 8 degrees. Neither elevation nor azimuth angles are exact as the wave is subject to detours but it helps to have an idea of the usual best angles. Best regards, Richard Harrison, KB5WZI |
#7
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Reg, when I penned the thread beginnings I was trying to evoke
fresh thinking about the subject so as to challenge ideas that are spread by plagurism in a similar way that the ballon is shown to demonstrate how directivity /gain occurs. Ham radio operators are lead to believe that the height above ground of a beam's feed point determines the take off angle. It is true that it does have an effect on the TOA, say 75 percent, when other actions are taken to change the angle and 95 percent or so if no other actions are taken. Thus if actions are taken to lower the TOA one can take advantage of physical hops that were not available for a similar feed point height. This is why I returned to the thread to dispute the statement that you made regarding no amount of antenna waving can change the facts. Regards from another indentured apporentice from the school of Engineering and Navigation along side of the East India Docks which was attended by many from the cable company further down the river Art Edwards" wrote in message ... "Reg Edwards" wrote The elevation angle of a radio wave is not related to antenna construction. snip BUT NO AMOUNT OF WAVING THE ANTENNA ABOUT WILL AFFECT THE ELEVATION ANGLE OF THE RADIO PATH. snip. ---- .................................................. ......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. ......... ========================================= Why should my answer to the question be altogether different to everybody else's? Especially as I'm right. \ Possibly because you were addressing a different question --- Reg. |
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